A rigid vessel of volume is held at by a reservoir

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Thermodynamic potentials and the formal structure of thermodynamics · Statistical mechanics of ideal classical systems

Thermal Physics, Ch The classical ideal gas from the partition function

Problem

A rigid vessel of volume V=2.00×10−3 m3V = 2.00\times10^{-3}\,\mathrm{m^3} is held at T=350 KT = 350\,\mathrm{K} by a reservoir. It contains NHe=3.00×1022N_{\rm He} = 3.00\times10^{22} helium atoms (M=4.003 g mol−1M = 4.003\,\mathrm{g\,mol^{-1}}) and NAr=1.00×1022N_{\rm Ar} = 1.00\times10^{22} argon atoms (M=39.95 g mol−1M = 39.95\,\mathrm{g\,mol^{-1}}). Both gases are monatomic and ideal, the atoms are independent, and the classical regime holds. For such a mixture the partition function factorises, Z=ZHeZArZ = Z_{\rm He}Z_{\rm Ar}, each species being divided by its own Ni!N_i!, so the free energies add: F=FHe+FArF = F_{\rm He} + F_{\rm Ar} with Fi=−NikBT[ln⁡(V/NiλT,i3)+1]F_i = -N_ik_BT[\ln(V/N_i\lambda_{T,i}^3) + 1]. ((a)) Chapter 1 obtained the pressure from wall collisions as pi=13nimivi2‾p_i = \tfrac13 n_i m_i \overline{v_i^2}. Using this chapter's internal energy of an ideal monatomic gas to supply vi2‾\overline{v_i^2}, find the root-mean-square speed of a helium atom and of an argon atom, and hence the total pressure in the vessel. ((b)) Obtain the total pressure again from p=−(∂F/∂V)T,NHe,NArp = -(\partial F/\partial V)_{T,N_{\rm He},N_{\rm Ar}}, and say in one sentence why the atomic masses cancel out of pp although they appear in λT,i\lambda_{T,i}. ((c)) Using μi=(∂F/∂Ni)T,V,Nj≠i\mu_i = (\partial F/\partial N_i)_{T,V,N_{j\ne i}}, evaluate the chemical potential of each species in units of kBTk_BT, and say which species has the more negative μ\mu and why. Take kB=1.381×10−23 J K−1k_B = 1.381\times10^{-23}\,\mathrm{J\,K^{-1}}, h=6.626×10−34 J sh = 6.626\times10^{-34}\,\mathrm{J\,s}, NA=6.022×1023 mol−1N_A = 6.022\times10^{23}\,\mathrm{mol^{-1}}.

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