A p-polarised plane wave of unit amplitude is incident from medium 1 (real index )…

PHYSICS · Multi-part · Fermi University Physics · Optics & Photonics · Wave propagation and light in media · Wave propagation and light in media

What an Instrument Can See, Ch The boundary as a two-port

Problem

A p-polarised plane wave of unit amplitude is incident from medium 1 (real index n1n_1) onto medium 2 (real index n2n_2) at angle θi\theta_i, refracting at θt\theta_t with n1sin⁡θi=n2sin⁡θtn_1\sin\theta_i=n_2\sin\theta_t; write rp,tpr_p,t_p for the reflection and transmission amplitude coefficients of this process, and rp′,tp′r_p',t_p' for the same interface traversed the other way, i.e. a p-polarised wave incident from medium 2 at θt\theta_t onto medium 1. ((a)) Time-reverse the first process: reverse the direction of travel of the incident, reflected and transmitted waves (for a real, lossless interface the coefficients are unaffected by this). Write the resulting situation as the superposition of two waves separately incident on the interface, and use linearity together with the fact that the reversed situation contains no wave leaving into medium 2, to derive the Stokes relations rp′=−rpr_p'=-r_p and tptp′=1−rp2t_pt_p'=1-r_p^2. ((b)) Air (n1=1n_1=1) meets BK7 glass (n2=1.5168n_2=1.5168) at θi=60.0∘\theta_i=60.0^\circ, for which the sign convention adopted throughout gives rp=+0.0395r_p=+0.0395 and tp=0.6332t_p=0.6332 (with θt=34.80∘\theta_t=34.80^\circ from Snell's law). Use the Stokes relations to predict rp′r_p' and tp′t_p' for light incident from inside the glass at 34.80∘34.80^\circ, and check your value of tp′t_p' against the direct formula tp′=2n2cos⁡θt/(n2cos⁡θi+n1cos⁡θt)t_p' = 2n_2\cos\theta_t/(n_2\cos\theta_i+n_1\cos\theta_t).

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