Chapter 12 defined the Fresnel number for an aperture of half-width observed a…

PHYSICS · Multi-part · Fermi University Physics · Optics & Photonics · Interference and diffraction · Fourier optics and image formation

What an Instrument Can See, Ch The lens as a Fourier transformer

Problem

Chapter 12 defined the Fresnel number NF=a2/(λz)N_F = a^2/(\lambda z) for an aperture of half-width aa observed a distance zz away, as the single number that decides whether the Fraunhofer (far-field) transform can be trusted at that distance. This chapter's transfer function G(νx,νy)=exp⁡[ikz1−λ2ν2]G(\nu_x,\nu_y) = \exp[ikz\sqrt{1-\lambda^2\nu^2}] is exact at every distance, and reduces to the Fresnel form where λν≪1\lambda\nu\ll1 and the dropped quartic phase πzλ3ν4/4\pi z\lambda^3\nu^4/4 stays well below a radian. A grating of half-width a=5.0 mma = 5.0\ \mathrm{mm} and pitch Λ=20 μm\Lambda = 20\ \mu\mathrm{m} is lit at λ=633 nm\lambda = 633\ \mathrm{nm} and observed at z=30 mmz = 30\ \mathrm{mm}. ((a)) Compute the Fresnel number NFN_F for this aperture and distance, and state whether the far-field Fraunhofer transform is a trustworthy description of the pattern at this zz. ((b)) Compute the grating's spatial frequency ν0=1/Λ\nu_0 = 1/\Lambda and the cutoff 1/λ1/\lambda, confirm that λν0≪1\lambda\nu_0 \ll 1, and evaluate the dropped quartic phase πzλ3ν04/4\pi z\lambda^3\nu_0^4/4 at this zz, to decide whether the small-angle step that turns this chapter's exact GG into Chapter 12's Fresnel transfer function is justified for this grating. ((c)) In one or two sentences, say why NFN_F and the condition for the Fresnel transfer function answer two different questions, even though both involve λ\lambda and zz.

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