An interferometer observes a spectroscopic binary whose two stars sit too close…
PHYSICS · Multi-part · Fermi University Physics · Optics & Photonics · Coherence and statistical optics · Coherence and statistical optics
What an Instrument Can See, Ch Spatial coherence and the van Cittert-Zernike theorem
Problem
An interferometer observes a spectroscopic binary whose two stars sit too close together for any single telescope to resolve, at wavelength λ=550nm. Each star is unresolved on its own, so it may be treated as a point (delta-function) incoherent source: a primary of flux I1 and a secondary of flux I2=rI1, with brightness ratio r≤1, separated on the sky by a small angle α. The interferometer's baseline B is aligned with the line joining the two stars, so the problem is one-dimensional, and the pair sits at angular positions θ=∓α/2 (primary, secondary) along that line. The van Cittert-Zernike theorem of the propagation-of-coherence section gives the complex coherence factor as the normalised Fourier transform of the source's angular brightness, μ12(B)=∫I0(θ)dθ∫I0(θ)e−i2πθB/λdθ, evaluated at the baseline B (the phase factor the theorem divides out is dropped throughout).
((a)) Write I0(θ) as two delta functions of weight I1 and I2 at θ=∓α/2, and show that μ12(B)=I1+I2I1eiπαB/λ+I2e−iπαB/λ.
((b)) Show that the squared fringe visibility is ∣μ12(B)∣2=1−(1+r)24rsin2(λπαB), and check that setting r=1 recovers the equal-brightness result ∣μ12(B)∣=∣cos(παB/λ)∣, which does reach zero.
((c)) The measured visibility first dips to a minimum ∣μ12∣=0.60 at a baseline B1=4.0m, and no shorter baseline shows a smaller value. Find the angular separation α of the two stars, in milliarcseconds.
((d)) Find the brightness ratio r from that minimum, and explain why this binary's visibility curve never falls to zero on any baseline.