A 10 m telescope observes at through air with m at 500 nm and a wind speed of 15 m s…

PHYSICS · Multi-part · Fermi University Physics · Optics & Photonics · Fourier optics and image formation · Fourier optics and image formation

What an Instrument Can See, Ch Keeping the phase: holography, wavefront modulation and adaptive optics

Problem

A 10 m telescope observes at λ=1.65 μm\lambda = 1.65\ \mu\mathrm{m} through air with r0=0.20r_0 = 0.20 m at 500 nm and a wind speed of 15 m s−1^{-1} across the pupil. Its adaptive optics system has a deformable mirror with actuator spacing d=0.50d = 0.50 m projected on the pupil, a closed-loop bandwidth of 40 Hz, and an on-axis guide star giving a subaperture signal-to-noise ratio of 6. Use the fitting-error term σfit2=0.34(d/r0)5/3\sigma^2_{\mathrm{fit}} = 0.34(d/r_0)^{5/3}, the temporal term σtemp2=(νG/ν3dB)5/3\sigma^2_{\mathrm{temp}} = (\nu_{\mathrm{G}}/\nu_{3\mathrm{dB}})^{5/3} with νG=0.43v/r0\nu_{\mathrm{G}} = 0.43v/r_0, and the noise term σnoise2=1/SNR2\sigma^2_{\mathrm{noise}} = 1/\mathrm{SNR}^2, with anisoplanatism zero on axis; r0r_0 scales as r0(λ)=r0(500 nm)(λ/500 nm)6/5r_0(\lambda) = r_0(500\ \mathrm{nm})(\lambda/500\ \mathrm{nm})^{6/5}. ((a)) Predict the Strehl ratio at 1.65 μ\mum from this error budget. ((b)) Using the diffraction-limited angular resolution of a lens acting as a Fourier transformer, θdiff=1.22λ/D\theta_{\mathrm{diff}} = 1.22\lambda/D, compute the Rayleigh-limited angular resolution of the unaberrated 10 m aperture at 1.65 μ\mum, in milliarcseconds. ((c)) State, with a one-sentence reason drawn from the pupil-sum picture of a low-order wavefront error, whether the corrected image's core width should be close to this diffraction-limited value even though the Strehl ratio found in part (a) is below 1.

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