Magnetic Moment and the Gyromagnetic Ratio

Angular momentum is invisible. What laboratories actually see — beam deflections, precession signals, split spectral lines, the hum of an MRI scanner — is magnetism. The bridge is one proportionality, μ=gγJ^\boldsymbol{\mu}=g\gamma\hat{\mathbf J}: every quantum of angular momentum carries a fixed ration of magnetic moment. Because the proportionality is rigid, the whole angular-momentum theory of the last several articles — the algebra, the ladder, the 2j+12j+1 rungs — translates line by line into a theory of tiny magnets, testable with a coil and a field. The exchange rate splits into two factors, and the split is the story. The classical part, γ=q/2m\gamma=q/2m, follows from freshman mechanics: a circulating charge is a current loop, and the loop's geometry cancels to leave charge-over-twice-mass. The quantum part is the dimensionless g-factor — and it refuses to be 1. Orbital motion obeys the classical bargain exactly (gL=1g_L=1); the electron's spin violates it by a factor of two (gs≈2.00232g_s\approx 2.00232), which is the cleanest proof in physics that spin is not a little ball spinning. Dirac's relativistic theory explains the 2; quantum electrodynamics computes the 0.00232 to twelve digits. This article builds the dictionary: the loop derivation, the Bohr magneton as the quantum of moment, the precession law ωL=∣gγ∣B\omega_L=|g\gamma| B that turns g-factors into measurable frequencies, and the Landé formula for atoms where orbit and spin both contribute. The payoff is a table of frequencies-per-tesla that runs NMR, ESR, MRI, and atomic clocks.

Key takeaways
  • A moment couples to a field via H=−μ⋅BH=-\boldsymbol{\mu}\cdot\mathbf{B}; for any angular momentum μ=gγJ^\boldsymbol{\mu}=g\gamma\hat{\mathbf J}, with γ=q/2m\gamma=q/2m the classical gyromagnetic ratio and gg a dimensionless quantum factor.
  • The current-loop derivation gives gL=1g_L=1 exactly for orbital motion — geometry cancels, leaving q/2mq/2m. Spin defies it: gs≈2.00232g_s\approx2.00232, twice as magnetic as its angular momentum "should" allow.
  • Quantization of J^z\hat J_z makes μz\mu_z discrete: μz=gγmℏ\mu_z=g\gamma m\hbar, in electron units the Bohr magneton μB=eℏ/2me=9.274×10−24\mu_B=e\hbar/2m_e=9.274\times10^{-24} J/T =57.88 μ=57.88\ \mueV/T.
  • In a uniform field the moment precesses, never aligns: d⟨J^⟩/dt=gγ ⟨J^⟩×Bd\langle\hat{\mathbf J}\rangle/dt=g\gamma\,\langle\hat{\mathbf J}\rangle\times\mathbf{B} at ωL=∣gγ∣B\omega_L=|g\gamma|B — g-factors are read off resonance dials.
  • Species dictionary (per tesla): electron spin 28.025 GHz · orbital 13.996 GHz · proton 42.577 MHz · neutron 29.165 MHz — the working frequencies of ESR, NMR and MRI.
  • Key idea: magnetic moment is angular momentum wearing a magnetic coat — μ=gγJ^\boldsymbol{\mu}=g\gamma\hat{\mathbf J} — and the g-factor on the label records whether the coat was cut classically (g=1g=1) or relativistically (g≈2g\approx2).
The core insight

Magnetic moment is angular momentum wearing a different coat: μ=gγJ^\boldsymbol{\mu}=g\gamma\hat{\mathbf J}, where the universal classical ratio γ=q/2m\gamma=q/2m carries the units and the dimensionless g-factor — 11 for orbits, ≈2\approx2 for spin — records the quantum tailoring.

Where this lives today

The dictionary is working infrastructure. Every MRI scanner is a 42.577-MHz-per-tesla proton radio; parts-per-million chemical shifts of that Larmor line are how NMR chemists read molecular structure. ESR g-factors near 2 diagnose defects in semiconductors; atomic magnetometers track alkali-atom precession to femtotesla sensitivity. And the anomaly is a two-front precision war: the electron's aea_e (Penning traps, 10−1310^{-13}) doubles as the best route to α\alpha, while the muon's g−2g-2, clocked at Fermilab against cyclotron rotation in a storage ring, is scrutinized for physics beyond the Standard Model. A century after the factor of two embarrassed everyone, the tenth decimal is where new physics is hunted.

The physical picture

Picture a charge qq circulating on a track: a current bounding an area is a magnet. Spin it twice as fast and the current doubles — the moment grows in lockstep with L\mathbf{L}. That lockstep is the whole content of μ∝L\boldsymbol{\mu}\propto\mathbf{L}; the constant carries a factor 12\tfrac12 because L=mvrL=mvr weighs one power of radius while μ=IA\mu=IA weighs area against a current falling as 1/r1/r. The geometry cancels; q/2mq/2m survives for any orbit.

Figure
From orbit to magnet — a circulating charge is a current loop, and μ rides L
One object, two faces: angular momentum L and magnetic moment μ charge q, mass m speed v · period T = 2πr/v L = mvr μ = IA = (q/2m) L the exchange rate γ = q / 2m orbital: g = 1 exactly spin: g ≈ 2.00232 proton: g ≈ 5.586 for negative charge (the electron) μ points opposite to L — moment antiparallel to angular momentum

Spin wrecks the picture, informatively. A spinning charged ball, analysed shell by shell with the same loop argument, predicts gs=1g_s=1; nature says gs≈2.00232g_s\approx2.00232 — twice as magnetic per unit of angular momentum as any classical rotation allows. So spin is not mechanical rotation: it is the intrinsic attribute Spin Angular Momentum established, with a coupling fixed by relativistic quantum mechanics rather than by a radius times a velocity. The second half of the picture is dynamical. A moment in a uniform field does not swing into alignment like a compass needle: μ\boldsymbol{\mu} is chained to J^\hat{\mathbf J}, and torque on an angular momentum changes direction, not magnitude. ⟨J^⟩\langle\hat{\mathbf J}\rangle sweeps a cone about B\mathbf{B} at the Larmor frequency ωL\omega_L, forever, absent dissipation. Every magnetic-resonance technology listens to that rotation.

Figure
Precession, not alignment — the moment sweeps a cone about B at the Larmor frequency
Torque μ × B turns J sideways — the cone never closes B ⟨J⟩ (and μ riding it) ω_L = |gγ|B J_z frozen per tesla: e⁻ spin · 28.025 GHz e⁻ orbital · 13.996 GHz proton · 42.577 MHz neutron · 29.165 MHz the frequency, not the moment itself, is what experiments measure — g-factors are read off resonance dials

The defining relation and the g-ledger

Everything in this article hangs on one operator equation. It answers the question: given that a system carries angular momentum J^\hat{\mathbf J} — orbital, spin, or total — how strong a magnet is it? The relation asserts the answer is always a rigid proportionality, with the system's identity compressed into a single pure number:

μ=g γ J^,γ=q2m\boldsymbol{\mu} = g\,\gamma\,\hat{\mathbf J}, \qquad \gamma = \frac{q}{2m}

where: μ\boldsymbol{\mu} is the moment operator (J^\hat{\mathbf J} rescaled, algebra and all), γ=q/2m\gamma=q/2m the classical gyromagnetic ratio carrying the units, and gg the dimensionless g-factor — the quantum correction to the classical bargain. Mind the sign: for the electron q=−e<0q=-e<0, so γ<0\gamma<0 and the moment points opposite to the angular momentum — a spin-up electron is a moment-down magnet. In a field, the coupling is the classical dipole energy promoted to an operator. With B=Bz^\mathbf{B}=B\hat{\mathbf z},

H=−μ⋅B=−gγB J^zH = -\boldsymbol{\mu}\cdot\mathbf{B} = -g\gamma B\,\hat J_z

where: the Hamiltonian is a rescaled J^z\hat J_z — its eigenstates are exactly the ladder states ∣j,m⟩|j,m\rangle of Ladder Operators and the Angular Momentum Spectrum. The spectrum of magnetism in a uniform field is the mm-ladder, relabeled in energy units. The measurable component along the field inherits the ladder's discreteness:

μz=gγ mℏ,m=−j,…,+j\mu_z = g\gamma\,m\hbar, \qquad m = -j,\dots,+j

where: μz\mu_z takes exactly 2j+12j+1 equally spaced values and nothing in between — the field selects among allowed orientations, never tilts continuously. This is space quantization; The Stern-Gerlach Experiment is its photograph — a beam in a field gradient splits into 2j+12j+1 spots, one per μz\mu_z.

carrierg-factorγ/2π\gamma/2\pi per teslawho measures it
electron orbital L^\hat{\mathbf L}gL=1g_L=1 exactly13.99613.996 GHz/Torbital Zeeman splitting
electron spin S^\hat{\mathbf S}gs=2.00232g_s=2.0023228.02528.025 GHz/TESR, Penning traps
proton spingp=5.586g_p=5.58642.57742.577 MHz/TNMR, MRI
neutron spingn=−3.826g_n=-3.82629.16529.165 MHz/T (opposite sense)neutron interferometry, EDM searches

The table is the article in miniature: orbital motion obeys the classical rate, the electron doubles it, and the nucleons scatter wildly — flags of composite structure. A neutral particle with a moment (the neutron) is by itself proof of charged constituents circulating inside.

Where the classical rate comes from

Derivation AThe orbital g-factor from a current loop

The goal is μL=(q/2m)L^\boldsymbol{\mu}_L=(q/2m)\hat{\mathbf L} — equivalently gL=1g_L=1 — from nothing but the definition μ=IA\mu=IA. The strategy is the classical circular orbit: compute the current the charge represents, multiply by the area, and watch radius and speed cancel in favour of angular momentum. The cancellation is the point — it makes γ=q/2m\gamma=q/2m universal, independent of orbit size or shape, which is what licenses promoting the result to an operator equation.

Step 1. The orbit is a current. A charge qq circling at speed vv on radius rr passes any fixed point once per period T=2πr/vT=2\pi r/v, so the loop carries

I=qT=qv2πr.I = \frac{q}{T} = \frac{qv}{2\pi r}.

Why: current is charge per time past a point — one charge, one lap, one period. No model of the charge has entered.

Step 2. Moment of the loop. A planar current loop of area AA has magnetic moment μ=IA\mu=IA, directed along the normal (right-hand rule with the current). With A=πr2A=\pi r^2,

μ=IA=qv2πr⋅πr2=qvr2.\mu = IA = \frac{qv}{2\pi r}\cdot \pi r^2 = \frac{qvr}{2}.

Step 3. Trade geometry for angular momentum. The same orbit carries L=mvrL=mvr, so vr=L/mvr=L/m and

μ=q2m L⟹μL=q2m L,gL=1.\mu = \frac{q}{2m}\,L \qquad\Longrightarrow\qquad \boldsymbol{\mu}_L = \frac{q}{2m}\,\mathbf{L}, \quad g_L = 1.

Why the one-half survives: L=mvrL=mvr weighs one power of rr, while μ∝vr/2\mu\propto vr/2 — the mismatch leaves exactly 12\tfrac12. Both vv and rr cancel, so every orbital state obeys the same ratio — the operator promotion is legitimate.

Step 4. Vector form and sign. For the electron q=−eq=-e: μL=−(e/2me)L\boldsymbol{\mu}_L=-(e/2m_e)\mathbf{L}, antiparallel to L\mathbf{L}. The relation holds as an operator identity, and gL=1g_L=1 is exact — no radiative correction; orbital angular momentum is ordinary mechanical motion of charge. Verified: the loop algebra checked symbolically with sympy — geometry cancels identically; matches Griffiths §4.4 and the exact orbital gL=1g_L=1.

The Bohr magneton: the quantum of moment

Insert the electron's numbers once and you get the currency of magnetic measurement. Orbital μz=−(e/2me) mℏ\mu_z=-(e/2m_e)\,m\hbar, so the natural unit is everything except the integer mm:

μB≡eℏ2me=9.274×10−24 J/T=57.88 μeV/T\mu_B \equiv \frac{e\hbar}{2m_e} = 9.274\times10^{-24}\ \mathrm{J/T} = 57.88\ \mu\mathrm{eV/T}

where: ee is the (positive) elementary charge and mem_e the electron mass (value verified from CODATA). Orbital Angular Momentum Operators quoted this number; here it earns its derivation — one ℏ\hbar of orbital angular momentum, converted at the rate e/2mee/2m_e. Conversions: 13.99613.996 GHz/T as a frequency (μB/h\mu_B/h), 0.67170.6717 K/T as a temperature (μB/kB\mu_B/k_B). The proton mass gives the nuclear magneton μN=eℏ/2mp=5.051×10−27\mu_N=e\hbar/2m_p=5.051\times10^{-27} J/T — down from μB\mu_B by exactly mp/me=1836.15m_p/m_e=1836.15. Nuclear magnetism is three orders feebler than electronic, which is why NMR needs strong fields and why everyday magnetism is overwhelmingly electronic. The electron's spin moment, in this currency, is

μS=−gsμBℏS^=−gsμB2σ,gs=2.00231930…\boldsymbol{\mu}_S = -g_s\frac{\mu_B}{\hbar}\hat{\mathbf S} = -g_s\frac{\mu_B}{2}\boldsymbol{\sigma}, \qquad g_s = 2.00231930\ldots

where: S^=ℏ2σ\hat{\mathbf S}=\tfrac\hbar2\boldsymbol{\sigma} for spin-12\tfrac12 (anatomy: Spin-1/2 and the Pauli Matrices); the minus sign is the electron's charge again. Numerically ∣μz∣=gs2μB≈1.001 μB|\mu_z|=\tfrac{g_s}{2}\mu_B\approx1.001\,\mu_B: half the angular momentum, one full magneton — an accident (gs⋅12≈1g_s\cdot\tfrac12\approx1) that will matter historically in the next article.

Spin breaks the classical bargain

Why gs≈2g_s\approx2? Three tiers, each owned elsewhere and stated here. Experiment (1925, spectral doublets and the anomalous Zeeman effect): the spin moment is twice too large for its angular momentum. Dirac's equation (1928): gs=2g_s=2 exactly for a point spin-12\tfrac12 particle — relativity's signature, derivation owned by the relativistic track. Then QED dresses the electron in virtual photons, shifting the value by the anomaly

ae≡gs−22=α2π+⋯=1.15965×10−3a_e \equiv \frac{g_s-2}{2} = \frac{\alpha}{2\pi} + \cdots = 1.15965\times10^{-3}

where: α≈1/137.04\alpha\approx1/137.04 is the fine-structure constant; Schwinger's 1948 one-loop term α/2π=1.1614×10−3\alpha/2\pi=1.1614\times10^{-3} already sits within 0.2%0.2\% of the full anomaly. Measured (one electron in a Penning trap) and computed gsg_s agree to about a part in 101210^{12} — the most precise confrontation of theory and experiment in science. The moral: the g-factor is a fingerprint. 11 says classical loop; 22 says relativistic point spin; 5.5865.586 (proton) or −3.826-3.826 (neutron) says composite — look inside.

Precession: how g-factors are measured

A static moment in a static field does something dynamical — and the dynamics is the measurement channel. The equation of motion comes from the expectation-value engine of Ehrenfest's Theorem, applied to J^\hat{\mathbf J} itself.

Go deeper · Derivation B · 1 minLarmor precession from the expectation-value engine
Derivation BLarmor precession from the expectation-value engine

The goal is the vector equation of motion for ⟨J^⟩\langle\hat{\mathbf J}\rangle in a uniform field — precession about B\mathbf{B} at ωL=∣gγ∣B\omega_L=|g\gamma|B, not alignment. The strategy: feed each component of J^\hat{\mathbf J} into the expectation-value engine d⟨A^⟩/dt=1iℏ⟨[A^,H^]⟩d\langle\hat A\rangle/dt=\tfrac{1}{i\hbar}\langle[\hat A,\hat H]\rangle (consumed from Ehrenfest's Theorem, not re-derived) with H^=−gγBJ^z\hat H=-g\gamma B\hat J_z, and let the algebra work. Watch what does not happen: nothing ever shortens the vector or pulls it toward the axis — the algebra can only rotate.

Step 1. Feed J^x\hat J_x to the engine. Only J^z\hat J_z appears in H^\hat H, so one commutator suffices:

d⟨J^x⟩dt=1iℏ⟨[J^x, −gγBJ^z]⟩=−gγBiℏ⟨−iℏJ^y⟩=gγB ⟨J^y⟩.\frac{d\langle\hat J_x\rangle}{dt} = \frac{1}{i\hbar}\big\langle[\hat J_x,\,-g\gamma B\hat J_z]\big\rangle = \frac{-g\gamma B}{i\hbar}\big\langle -i\hbar \hat J_y\big\rangle = g\gamma B\,\langle\hat J_y\rangle.

Why: [J^x,J^z]=−iℏJ^y[\hat J_x,\hat J_z]=-i\hbar\hat J_y — the same commutator that made components incompatible — converts a static Hamiltonian into rotation. Nothing else about the state is used.

Step 2. Repeat: [J^y,J^z]=+iℏJ^x[\hat J_y,\hat J_z]=+i\hbar\hat J_x gives d⟨J^y⟩/dt=−gγB⟨J^x⟩d\langle\hat J_y\rangle/dt=-g\gamma B\langle\hat J_x\rangle; [J^z,J^z]=0[\hat J_z,\hat J_z]=0 gives

d⟨J^z⟩dt=0.\frac{d\langle\hat J_z\rangle}{dt} = 0.

Why JzJ_z freezes: energy ∝⟨J^z⟩\propto\langle\hat J_z\rangle is conserved, so the cone angle never changes; alignment would need dissipation, a mechanism outside this Hamiltonian.

Step 3. Assemble. The three component equations are exactly a cross product:

d⟨J^⟩dt=gγ ⟨J^⟩×B,\frac{d\langle\hat{\mathbf J}\rangle}{dt} = g\gamma\,\langle\hat{\mathbf J}\rangle\times\mathbf{B},

— the classical torque equation, recovered exactly for any jj and any state, no classical limit taken.

Step 4. The transverse pair (⟨J^x⟩,⟨J^y⟩)(\langle\hat J_x\rangle,\langle\hat J_y\rangle) rotates rigidly at

ωL=∣gγ∣ B=∣g∣ ∣q∣B2m,\omega_L = |g\gamma|\,B = \frac{|g|\,|q|B}{2m},

with sense set by the sign of gγg\gamma (electron and proton precess oppositely). This Larmor frequency is directly countable as a resonance line — why the g-ledger is quoted in frequency per tesla. Verified: all three component equations checked numerically on j=12j=\tfrac12 and j=1j=1 matrices (machine precision); the solution ⟨S^x⟩=ℏ2cos⁡ωLt\langle\hat S_x\rangle=\tfrac\hbar2\cos\omega_L t, ⟨S^y⟩=−ℏ2sin⁡ωLt\langle\hat S_y\rangle=-\tfrac\hbar2\sin\omega_L t confirmed against exact evolution; matches Sakurai §3.2. The two-state solve lives in Spin Angular Momentum and is consumed, not re-run.

Spin Angular Momentum solved the spin-12\tfrac12 case explicitly — its 28.02 GHz/T electron figure is the j=12j=\tfrac12 instance of this vector law: gsμB/h=2.00232×13.996=28.025g_s\mu_B/h=2.00232\times13.996=28.025 GHz/T. For the proton, γp=2.6752×108\gamma_p=2.6752\times10^{8} rad s−1^{-1}T−1^{-1} (42.57742.577 MHz/T) and μp=2.793 μN\mu_p=2.793\,\mu_N; the anomaly κp=(gp−2)/2=1.79\kappa_p=(g_p-2)/2=1.79 above the Dirac value flags quark substructure.

When orbit and spin both contribute: the Landé g-factor

An atomic electron usually carries both L^\hat{\mathbf L} (gL=1g_L=1) and S^\hat{\mathbf S} (gs≈2g_s\approx2). The total moment μ=−μBℏ(L^+2S^)\boldsymbol{\mu}=-\tfrac{\mu_B}{\hbar}(\hat{\mathbf L}+2\hat{\mathbf S}) is then not parallel to J^=L^+S^\hat{\mathbf J}=\hat{\mathbf L}+\hat{\mathbf S} — the double spin weighting skews it. Spin–orbit coupling spins L^\hat{\mathbf L} and S^\hat{\mathbf S} rapidly about J^\hat{\mathbf J}; over a weak field's slow timescale the skewed part averages away, leaving only the J^\hat{\mathbf J}-projection — the Landé g-factor:

gJ=1+j(j+1)+s(s+1)−l(l+1)2j(j+1)g_J = 1 + \frac{j(j{+}1) + s(s{+}1) - l(l{+}1)}{2j(j{+}1)}

where: l,s,jl,s,j label the level, and the formula assumes gL=1g_L=1, gs=2g_s=2. The derivation — why "project onto J^\hat{\mathbf J}" is a theorem about vector operators, not a cartoon — is owned by Projection Theorem for Vector Operators and deliberately not reproduced here; this article states and stress-tests the result. The vector-model picture you can hold now:

Figure
The vector model — μ is skewed off J by the double-weighted spin; only its J-projection survives
L and S precess about J; the moment −(L + 2S) rides skewed J = L + S L S fast precession about J −μ ∝ L + 2S (skewed) surviving projection: g_J J g_J checkpoints ²S₁/₂ (pure spin): g_J = 2 s = 0 (pure orbit): g_J = 1 ²P₃/₂: 4/3 · ²P₁/₂: 2/3 weak-field Zeeman splittings ΔE = g_J μ_B m_j B read this projection directly off atomic spectra

Stress-test it where the answer is known — all four cases verified exactly. Pure spin (l=0l=0, j=s=12j=s=\tfrac12; the 2S1/2^2S_{1/2} ground state of hydrogen or silver): gJ=2g_J=2. Pure orbit (s=0s=0): gJ=1g_J=1 for any ll. Sodium's doublet levels: 2P3/2→43^2P_{3/2}\to\tfrac43, 2P1/2→23^2P_{1/2}\to\tfrac23. Three g-factors in one atom (2,43,232,\tfrac43,\tfrac23) is exactly why the "anomalous" Zeeman effect looked anomalous — each level splits at its own ΔE=gJμBmjB\Delta E=g_J\mu_B m_j B. (Quantitative Zeeman theory belongs to the hydrogen chapter.)

Limiting cases

caseresultmeaning
pure orbital (s=0s=0)μ=−μBℏL^\boldsymbol{\mu}=-\tfrac{\mu_B}{\hbar}\hat{\mathbf L}, gJ=1g_J=1classical bargain exact; no radiative correction
pure spin (l=0l=0)μ=−gsμBℏS^\boldsymbol{\mu}=-g_s\tfrac{\mu_B}{\hbar}\hat{\mathbf S}, gJ=2g_J=2Dirac value + QED anomaly ae=1.16×10−3a_e=1.16\times10^{-3}
mixed (l,s≠0l,s\ne0)gJ=1+j(j+1)+s(s+1)−l(l+1)2j(j+1)g_J=1+\tfrac{j(j+1)+s(s+1)-l(l+1)}{2j(j+1)}only the J^\hat{\mathbf J}-projection of μ\boldsymbol{\mu} survives
nuclear carrierμ∼μN=μB/1836\mu\sim\mu_N=\mu_B/1836same charge, 1836× the mass — magnetism 3 orders weaker
B→B\to gradientforce Fz=μz ∂zBzF_z=\mu_z\,\partial_z B_zuniform field only precesses; a gradient deflects — the Stern–Gerlach principle
classical limit j→∞j\to\infty2j+12j+1 orientations blur to a continuumspace quantization hides; the compass-needle picture returns

Worked examples

Example 1 — the MRI chain (confidence builder). Task: a hospital scanner runs at B=3B=3 T. Find the proton Larmor frequency, and the fraction of protons that actually contribute signal at body temperature T=310T=310 K.

Step 1. Frequency. The proton entry is γp/2π=42.577\gamma_p/2\pi=42.577 MHz/T, so at 3 T the scanner's radio dial sits at ν=42.577×3=\nu = 42.577\times3 = \boldsymbol{127.73\ \mathrm{MHz}}.

Step 2. Zeeman gap. ΔE=hν=8.46×10−26\Delta E = h\nu = 8.46\times10^{-26} J ≈0.53 μ\approx 0.53\ \mueV — eight orders below bond energies; the field barely perturbs the matter.

Step 3. Polarization: P=tanh⁡(ΔE/2kBT)P=\tanh(\Delta E/2k_BT); at 310 K the argument is tiny and tanh⁡\tanh is its argument:

P≈ℏωL2kBT=.P \approx \frac{\hbar\omega_L}{2k_BT} = \boldsymbol{9.9\times10^{-6} \approx 1.0\times10^{-5}}.

Step 4. Consequence: only ∼\sim10 protons per million are net-aligned. A 3 T scanner listens to a 127.73 MHz hum from a 10−510^{-5} polarization — which is why higher BB (better polarization and higher pickup frequency) is worth billions.

Example 2 — how big is a Bohr magneton, really? (exam level). Task: compare the magnetic energy of one Bohr magneton in a strong lab field (B=1B=1 T) with thermal energy at room temperature, and find the electron-spin resonance frequency in that field.

Step 1. Magnetic scale: μBB=9.274×10−24\mu_B B = 9.274\times10^{-24} J == \boldsymbol{57.88\ \mu\mathrm{eV}} at 1 T.

Step 2. Thermal scale: kBT=25.85k_BT = 25.85 meV at 300 K. The ratio is

μBBkBT=57.88 μeV25.85 meV=.\frac{\mu_B B}{k_BT} = \frac{57.88\ \mu\text{eV}}{25.85\ \text{meV}} = \boldsymbol{2.24\times10^{-3}}.

Thermal agitation out-shouts a tesla by a factor of 450 — why paramagnetism is weak and Curie-like (χ∝μB2/kBT\chi\propto\mu_B^2/k_BT), and why quantum magnetic devices run in cryostats (at 20 mK the ratio exceeds 30 and spins freeze into the ground rung).

Step 3. Spin resonance. The 1 T electron-spin splitting is gsμBB=g_s\mu_B B = \boldsymbol{115.9\ \mu\mathrm{eV}}: a photon of ν=gsμBB/h=\nu = g_s\mu_B B/h = \boldsymbol{28.025} GHz — microwave territory, every ESR spectrometer's dial. Cross-check: 28.025/13.996=2.0023=gs28.025/13.996 = 2.0023 = g_s — the dictionary's factor of two is the anomalous g-factor in plain sight.

Origins · 1 minLlewellyn Hilleth Thomas and how this was discovered
LH
Llewellyn Hilleth Thomas
1903–1992 · Cambridge, Copenhagen, Ohio State

In 1925 the new spin hypothesis had a factor-of-two scandal: with gs=2g_s=2 the fine-structure doublet splittings came out twice too large, and Heisenberg and Pauli were ready to bury the idea. Llewellyn Thomas, a 22-year-old Cambridge student visiting Bohr's institute, found the missing half in a weekend of special relativity: the electron's rest frame is a sequence of non-collinear boosts, and such a sequence composes into a rotation — the frame itself precesses at half the naive rate, cutting the spin–orbit interaction in two. His 1926 letter to Nature reconciled gs=2g_s=2 with spectroscopy overnight and converted the skeptics; Uhlenbeck recalled that even Einstein had to sit with the argument. The "Thomas half" — kinematic, exact — remains the standing warning that g-factors must be handled relativistically even when nothing moves fast. Thomas later co-authored the Thomas–Fermi model of the atom, a story for the approximation-methods chapter.

History
1915
— Einstein and de Haas measure rotation induced by remagnetization; systematic bias steers them to g near 1, the classical expectation
1921
— Stern and Gerlach observe discrete beam splitting — space quantization made visible
1925
— Uhlenbeck and Goudsmit propose electron spin carrying g about 2
1926
— Thomas's relativistic precession supplies the missing factor of one half in fine structure
1928
— Dirac's equation yields g equals 2 exactly for a point spin-half particle
1933
— Stern's group measures the proton moment: 2.8 nuclear magnetons, not 1 — first flag of substructure
1947
— Kusch and Foley detect the electron anomaly g slightly above 2
1948
— Schwinger computes the one-loop anomaly alpha over two pi

Going further

References. Griffiths, 3rd ed., §4.4 · Sakurai & Napolitano, 2nd ed., §1.1, §3.2 · Shankar, 2nd ed., Ch. 14 · Cohen-Tannoudji, Diu & Laloë, Vol. 1, Ch. IV & Complement · Townsend, Ch. 1 · CODATA 2018 recommended values (Bohr magneton, electron g-factor).

Provenance. Equations are standard textbook results: defining relation and orbital derivation from Griffiths §4.4; Larmor precession from Sakurai §3.2; Landé projection from Cohen-Tannoudji. Numbers to verify: Bohr magneton μB≈9.274×10−24 J/T\mu_B\approx9.274\times10^{-24}\,\mathrm{J/T}, electron anomaly ae≈1.15965×10−3a_e\approx1.15965\times10^{-3} and gs≈2.00232g_s\approx2.00232 (CODATA 2018), Schwinger term α/2π\alpha/2\pi, proton gp≈5.586g_p\approx5.586, and mass ratio mp/me≈1836m_p/m_e\approx1836. A verifier should recompute gJg_J for sample states (e.g. 2S1/2→2^2S_{1/2}\to2, 2P1/2→2/3^2P_{1/2}\to2/3) and check the current-loop algebra cancels geometry to give gL=1g_L=1. For this edition every numeric claim was machine-verified (sympy/numpy, 42 checks): the loop algebra symbolically, μB\mu_B/μN\mu_N/all four dictionary frequencies from CODATA, all four Landé special cases exactly, the precession equations on explicit j=12j=\tfrac12 and j=1j=1 matrices, both worked-example chains. Ownership note: the base carries a Landé projection-theorem derivation; per the chapter map it belongs to Projection Theorem for Vector Operators and is deliberately not reproduced — this article states the formula and verifies its special cases.

Upstream: Orbital Angular Momentum Operators (L^\hat{\mathbf L} machinery, first sight of μB\mu_B) · Angular Momentum Commutation Relations (the algebra the precession feeds on) · Spin Angular Momentum (the intrinsic carrier, two-state precession solve) · Ladder Operators and the Angular Momentum Spectrum (the mm-census). Downstream: The Stern-Gerlach Experiment (the gradient force that photographs μz\mu_z) · Spin-1/2 and the Pauli Matrices (μ\boldsymbol{\mu} in σ\boldsymbol{\sigma} language) · Projection Theorem for Vector Operators (the Landé derivation, owed and paid there) · the hydrogen chapter's Zeeman treatment.

If spin isn't literal rotation, why does it produce a magnetic moment at all?

Because "magnetic moment" is defined by coupling (H=−μ⋅BH=-\boldsymbol{\mu}\cdot\mathbf B), not by circulating charge. Spin enters the relativistic wave equation like any angular momentum, and the equation forces a coupling with gs=2g_s=2. The current loop is a sufficient mechanism for a moment, not a necessary one — the moment is real, the mechanical picture is not.

Why does the electron's moment point opposite to its spin?

Only because its charge is negative: γ=q/2m\gamma=q/2m with q=−eq=-e is negative. A positron's (or proton's) moment is parallel to its spin. Cache the consequences: for an electron in B=Bz^\mathbf B=B\hat{\mathbf z}, spin-up is the higher-energy state, and electron and proton spins precess in opposite senses in the same field.

Is g_L = 1 exact, or does QED correct it like it corrects g_s?

Exact. Orbital angular momentum is ordinary mechanical motion of charge; the loop argument holds operator-by-operator with no room for correction. Radiative effects dress the spin vertex (gs=2(1+ae)g_s=2(1+a_e)) but not the orbital coupling — the anomaly is a property of the intrinsic, relativistic degree of freedom, not of magnetism in general.

Where does the Landé formula stop working?

At two ends. In strong fields the Zeeman energy beats spin–orbit coupling: L^\hat{\mathbf L} and S^\hat{\mathbf S} decouple from J^\hat{\mathbf J} and precess separately about B\mathbf B (Paschen–Back), dissolving the projection picture. And it assumes gL=1g_L=1, gs=2g_s=2 exactly; precision work uses gs=2.00232g_s=2.00232, shifting gJg_J in the fourth decimal. Weak-field LS-coupled atoms are its home turf.

Why is nuclear magnetism ~1836 times weaker if the proton's g-factor is bigger than the electron's?

The mass in γ=q/2m\gamma=q/2m does the damage: the proton's unit is μN=μB/1836.15\mu_N=\mu_B/1836.15, so even with gp=5.586g_p=5.586 its moment is 2.79 μN≈1.5×10−3 μB2.79\,\mu_N\approx1.5\times10^{-3}\,\mu_B. The g-factor sets the style (and flags substructure); the magneton, set by the mass, sets the size. Hence NMR's strong fields and MRI's 10−510^{-5} polarizations.

The neutron is neutral. How can it have a magnetic moment and a gyromagnetic ratio?

A neutral composite can carry circulating charged constituents whose currents don't cancel: the neutron's quarks (udd) yield −1.913 μN-1.913\,\mu_N, antiparallel to spin as if a negative current dominates. A structureless neutral particle would have μ=0\mu=0 — the neutron's moment was early hard evidence of nucleon substructure. Its entry, 29.165 MHz/T reversed-sense, runs daily in neutron-beam physics.

Is the Larmor frequency the same as the frequency of the photon that flips the spin?

For j=12j=\tfrac12, exactly: the Zeeman gap is ΔE=ℏωL\Delta E=\hbar\omega_L, so resonance equals precession — one number per tesla. For higher jj with equal spacing, the same frequency drives all Δm=±1\Delta m=\pm1 transitions. The identity breaks when quadrupole couplings or zero-field splittings stagger the rungs — then the line splits into a multiplet, which is what spectroscopists mine for structure.

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