Effect of Concentration and Ka on Titration Feasibility

A student titrates 0.10 M acetic acid (Ka=1.8×10−5K_a = 1.8\times10^{-5}) with 0.10 M NaOH. They see a beautiful, steep jump through the equivalence point. Phenolphthalein snaps from colorless to pink over half a drop. The same student then tries 0.0010 M acetic acid, or switches to a "weak acid" with Ka=1×10−9K_a = 1\times10^{-9}. The curve goes flat and mushy. No indicator on the shelf can find the equivalence point within acceptable error. Nothing about the chemistry is broken. The equilibrium still exists, and the stoichiometry is still 1:1. But the titration itself has stopped being useful. This is the difference between a reaction being thermodynamically real and a reaction being analytically feasible. This matters because titrimetry is only as good as its endpoint. An analyst does not get to see the equivalence point directly. They infer it from a sudden change in pH, potential, or color. This change is detected by an indicator or an electrode. If the curve near equivalence is gentle rather than steep, a problem arises. A one-drop overshoot in delivering titrant translates into a large systematic error. This error appears in the inferred equivalence volume. It can be larger than the precision the method is expected to deliver. Knowing in advance whether a given weak acid/base will even work matters. This applies at a given concentration. It is a routine, load-bearing judgment call in analytical practice, not a footnote. The big picture is that titration feasibility is governed by two things. These act together, never separately: the analytical concentration CC of the analyte and its equilibrium constant KaK_a (or KbK_b). Neither alone tells you the sharpness of the break. A very strong-tasting acid at vanishing concentration titrates as poorly as a reasonably concentrated but very weak acid. The product CKaC K_a sets the height of the pH jump at the equivalence point. More precisely, this height depends on the fraction of the initial acid dissociated. It also depends on the buffering capacity this creates. There is a widely used rule of thumb: CKa≳10−8C K_a \gtrsim 10^{-8}. This separates titratable from non-titratable systems. This article builds that rule from first principles rather than asserting it. What follows is a full derivation of the equivalence-point pH. It also covers the size of the pre/post-equivalence break as functions of CC and KaK_a. There are three fully worked numerical examples. These span "textbook clean" to "borderline failure." A systematic table of limiting cases follows. The historical context is also included, showing why analytical chemists settled on today's criteria. The treatment builds directly on Weak Acid-Strong Base Titration Curves and Weak Base-Strong Acid Titration Curves. It sets up the machinery needed for Polyprotic Acid Titration Curves. It also helps in choosing correctly among Acid-Base Indicators: Theory and Transition Range.

Key takeaways
  • The sharpness of a titration break depends on both concentration CC and KaK_a (or KbK_b), never on either alone.
  • The equivalence-point pH of a weak acid titrated with strong base is set by hydrolysis of the conjugate base: pHeq=7+12pKa+12log⁡Ceq\mathrm{pH}_{eq} = 7 + \tfrac12\mathrm{p}K_a + \tfrac12\log C_{eq}.
  • The size of the pH jump across the last 0.1% of titrant collapses smoothly as CC drops or as KaK_a drops — there is no sharp cliff, only diminishing returns.
  • A practical, defensible feasibility criterion is CKa≳10−8C K_a \gtrsim 10^{-8} (equivalently CKb≳10−8CK_b\gtrsim10^{-8}) for a break detectable by ordinary indicators or a pH meter to ±0.02\pm 0.02–0.050.05 pH.
  • Diluting a weak acid tenfold shifts pHeq\mathrm{pH}_{eq} by only about −0.5-0.5 unit, but it shrinks the jump far more severely because the buffer region also flattens.
  • Polyprotic and mixed-acid systems (foreshadowing later material) require pairwise feasibility: each successive equivalence point must independently satisfy CiKa,i≳10−8C_iK_{a,i}\gtrsim10^{-8} and the two constants must differ enough to be resolved.
  • Key idea: feasibility is set by how much the last small increment of titrant changes [H+][\mathrm{H}^+] near the stoichiometric point, and that sensitivity scales with KaC\sqrt{K_aC}, not with KaK_a or CC separately.

Where this lives today

Feasibility screening based on CKaCK_a (or the analogous CKbCK_b, CKfCK_f, and ΔE∘\Delta E^\circ criteria for other titration types) is not a historical curiosity — it is a routine gatekeeping calculation in modern method development. Pharmaceutical quality control labs validating an acid–base assay for a drug substance must check, before ever running a titration, whether the compound's functional groups (often weak acids or bases with pKa\mathrm pK_a values between 3 and 10, and concentrations dictated by dosage-form solubility limits) will give a usable endpoint; many active pharmaceutical ingredients are instead assayed by non-aqueous titration in glacial acetic acid or another differentiating solvent precisely because their aqueous KaK_a is too small to satisfy the feasibility threshold — a direct, industrial-scale application of the logic developed here. Environmental and water-quality laboratories run into the same constraint when titrating very dilute natural-water samples for alkalinity or acidity: at concentrations near 10−410^{-4}–10−310^{-3} M (typical for weakly buffered surface waters), only relatively strong-acting species (carbonic acid's first dissociation, or strong mineral acidity) give usable potentiometric breaks, while weaker contributing equilibria are folded into a smooth, gently sloping curve and estimated by Gran-function linearization rather than by looking for a visual inflection. In biochemistry and clinical chemistry, the same CKaCK_a logic underlies why physiological buffers (bicarbonate, phosphate, protein histidine residues, each with pKa\mathrm pK_a near physiological pH and millimolar concentrations) are excellent buffers but would make terrible titration analytes — their whole biological utility (resisting pH change, i.e., a flat titration curve near their pKa\mathrm pK_a) is the mirror image of what a titrimetric method needs (a sharp curve at the endpoint). Understanding feasibility in the titration sense thus directly illuminates why buffering capacity and titratability are opposite requirements on the same underlying equilibrium chemistry — a conceptual bridge worth carrying into the study of Polyprotic Acid Titration Curves, where the feasibility criterion must be applied separately, and self-consistently, to each successive dissociation step.

Ask the tutor: For a diprotic acid with Ka1=1.0×10−3K_{a1}=1.0\times10^{-3} and Ka2=1.0×10−8K_{a2}=1.0\times10^{-8} at 0.10 M, is the second equivalence point separately feasible, and how would I check it?

The physical picture

Picture the titration curve of a weak acid HA with strong base as three physically distinct regions glued together: a rising buffer region (before equivalence), a steep transition (at equivalence), and a leveling excess-base region (after equivalence). The buffer region is controlled by the Henderson–Hasselbalch relationship and is inherently gentle — that is what a buffer is for. The steepness the analyst actually needs comes entirely from the transition region, where the solution stops being a good buffer because one of the buffer components (HA) has essentially run out. The key physical fact is this: right at equivalence, the solution is not neutral — it is a solution of the conjugate base A⁻ in water, and its pH is set by the hydrolysis equilibrium A−+H2O⇌HA+OH−\text{A}^- + \text{H}_2\text{O} \rightleftharpoons \text{HA} + \text{OH}^-. How far this hydrolysis proceeds — and therefore how far the equivalence-point pH sits from neutral — depends on Kb=Kw/KaK_b = K_w/K_a and on the concentration of A⁻ at that point, CeqC_{eq}. A weaker acid (smaller KaK_a, so its conjugate base is a stronger base) produces more extensive hydrolysis and a farther-from-7 equivalence pH. Dilution lowers CeqC_{eq}, which also pushes the equivalence pH toward neutral because a more dilute base hydrolyzes proportionally more (fractional dissociation increases as concentration drops), but the absolute change is modest — a factor of 10 dilution shifts pHeq\mathrm{pH}_{eq} by only log⁡10≈0.5\log\sqrt{10}\approx 0.5. The steepness of the break, however, is far more sensitive to both CC and KaK_a than the equivalence pH itself, because steepness depends on how quickly the solution's buffering capacity collapses as the last bit of HA is consumed. A dilute or very weak acid never builds up much buffering capacity in the first place (small [HA]0[\mathrm{HA}]_0, or KaK_a so small that little dissociates), so there is little capacity to lose — the curve near equivalence is already nearly flat well before you get there, because the solution was poorly buffered even at 50% titration. This is the mechanistic reason the CKaCK_a product, not either factor alone, governs feasibility.

Figure
Titration curves of 0.10 M and 0.0010 M acetic acid (Ka=1.8×10−5K_a=1.8\times10^{-5}) titrated with matched-concentration NaOH, showing the collapse of the equivalence break upon dilution
Volume NaOH added (mL) pH 0 50 (equiv.) 100 2 7 12 V_eq 0.10 M / 0.10 M — sharp break 0.0010 M / 0.0010 M — flattened

Now contrast concentration effects with KaK_a effects at fixed concentration. Weakening the acid (lowering KaK_a while holding C=0.10C = 0.10 M) has a qualitatively similar effect: the buffer region shifts to higher pH (since pH≈pKa\mathrm{pH}\approx \mathrm{p}K_a at half-equivalence), and the jump shrinks, because a weak conjugate acid means a strongly hydrolyzing conjugate base whose own buffering (from the large excess of un-reacted A⁻/HA left over at 99.9% completion) extends further and further past the "true" equivalence point.

Figure
Effect of Ka at fixed concentration C = 0.10 M: acetic acid (Ka=1.8×10⁻⁵) vs a very weak acid (Ka=1×10⁻⁹)
Volume NaOH added (mL) pH 2 7 13 equiv. Ka = 1.8×10⁻⁵ — clean break Ka = 1×10⁻⁹ — curve nearly flat throughout

The core ideas

The equivalence-point pH for titrating a weak acid HA (initial concentration C0C_0, volume V0V_0) with strong base of matching or arbitrary concentration, at the point where moles base added equal moles HA initially present, follows from treating the resulting solution as a simple solution of the conjugate base A⁻ at concentration CeqC_{eq}:

pHeq=7+12pKa+12log⁡Ceq\mathrm{pH}_{eq} = 7 + \frac{1}{2}\mathrm{p}K_a + \frac{1}{2}\log C_{eq}

where: — pKa=−log⁡Ka\mathrm{p}K_a = -\log K_a for the weak acid, — CeqC_{eq} is the analytical concentration of A⁻ at the equivalence point (moles of original HA divided by the total volume, HA solution plus titrant added), — the "7" arises from Kw=10−14K_w = 10^{-14} at 25 °C (pOH=12pKb−12log⁡Ceq\mathrm{pOH}=\tfrac12\mathrm{p}K_b - \tfrac12\log C_{eq}, then pH=14−pOH\mathrm{pH}=14-\mathrm{pOH}).

Reading: every factor-of-10 decrease in KaK_a (weaker acid) raises pHeq\mathrm{pH}_{eq} by 0.5 unit; every factor-of-10 dilution at equivalence lowers pHeq\mathrm{pH}_{eq} by 0.5 unit. The two effects are symmetric in this formula but act oppositely on where pHeq\mathrm{pH}_{eq} sits relative to 7 — dilution always pulls it back toward neutral (feasibility-hurting direction being pH closer to a flat region), while decreasing KaK_a pushes it further from 7 while simultaneously flattening the curve. The paradox — moving pH further from 7 while the curve gets less steep — is resolved by looking at the jump, not the equivalence pH, which is the second core relationship. A working measure of feasibility is the size of the pH change across the interval from 99.9% to 100.1% titrated (a standard "sharpness window" corresponding to the ±0.1%\pm 0.1\% volumetric precision of a well-calibrated buret). Just before equivalence (say, fraction titrated f=1−εf = 1-\varepsilon with ε\varepsilon small), essentially all HA is converted except a tiny leftover; just after (f=1+εf=1+\varepsilon), there is a tiny excess of strong base. Approximating both sides:

ΔpHjump≈pKa+log⁡(εCeqKa/[H+]eq (…)) →simplified ΔpHjump ∼ log⁡(C Ka)+const.\Delta\mathrm{pH}_{jump} \approx \mathrm{p}K_a + \log\left(\frac{\varepsilon C_{eq}}{K_a/[\mathrm H^+]_{eq}\,(\ldots)}\right)\ \xrightarrow{\text{simplified}}\ \Delta\mathrm{pH}_{jump}\ \sim\ \log(C\,K_a) + \text{const.}

where: — the leading behavior of the jump size scales with log⁡(CKa)\log(CK_a) once the excess-strong-base contribution (which is independent of KaK_a and controlled purely by dilution) is added in, — "const." bundles the fixed contributions from KwK_w and the chosen ε\varepsilon window, — this is not an exact closed form (the full expression requires solving a cubic in [H+][\mathrm H^+] near equivalence) but it captures why the practically used feasibility threshold is stated as a bound on the product CKaCK_a, not on CC or KaK_a individually.

Reading: the jump does not depend on CC and KaK_a through some complicated combination — to leading order it depends on their product. This is why the standard teaching rule is stated as CKa≳10−8CK_a\gtrsim10^{-8}: it is precisely the statement that log⁡(CKa)≳−8\log(CK_a)\gtrsim-8, i.e., that the leading term in the jump-size expression stays above the noise floor set by how precisely pH or an indicator color can be read (typically ±0.1\pm0.1–0.30.3 pH unit of genuine ambiguity in color-change titrations).

Derivation AEquivalence-point pH from conjugate-base hydrolysis

Goal. Derive pHeq=7+12pKa+12log⁡Ceq\mathrm{pH}_{eq} = 7 + \tfrac12\mathrm{p}K_a + \tfrac12\log C_{eq} for the titration of weak acid HA with strong base, starting only from the hydrolysis equilibrium of A⁻.

Step 1 — Identify the species present at equivalence. At the stoichiometric point, moles of OH⁻ added exactly equal initial moles of HA. Every HA molecule has been converted to A⁻ (the strong-base–weak-acid neutralization HA+OH−→A−+H2O\mathrm{HA}+\mathrm{OH}^-\to\mathrm A^-+\mathrm H_2\mathrm O goes essentially to completion, since Ka≫KwK_a\gg K_w for any titratable acid). The solution is therefore, to excellent approximation, a simple solution of NaA at concentration Ceq=nHA,0/VtotalC_{eq} = n_{\mathrm{HA},0}/V_{total}, where Vtotal=V0+VeqV_{total}=V_0+V_{eq} includes the titrant volume added.

Step 2 — Write the hydrolysis equilibrium. The conjugate base reacts with water:

A−+H2O⇌HA+OH−,Kb=KwKa\mathrm A^- + \mathrm H_2\mathrm O \rightleftharpoons \mathrm{HA} + \mathrm{OH}^-, \qquad K_b = \frac{K_w}{K_a}

Let x=[OH−]x=[\mathrm{OH}^-] produced. Then [HA]=x[\mathrm{HA}]=x, [A−]≈Ceq−x≈Ceq[\mathrm A^-]\approx C_{eq}-x\approx C_{eq} (valid when hydrolysis is small, checked after solving).

Step 3 — Solve the equilibrium expression.

Kb=x2Ceq−x≈x2CeqK_b = \frac{x^2}{C_{eq}-x}\approx\frac{x^2}{C_{eq}}

so

x=[OH−]=KbCeq=KwKaCeqx=[\mathrm{OH}^-]=\sqrt{K_bC_{eq}}=\sqrt{\frac{K_w}{K_a}C_{eq}}

Step 4 — Convert to pH. Take −log⁡-\log of both sides of [OH−]=KwCeq/Ka[\mathrm{OH}^-]=\sqrt{K_wC_{eq}/K_a}:

pOH=12(pKw−pKa−log⁡Ceq)⋅(−1) ⇒ pOH=12pKw−12pKa+12log⁡1Ceq\mathrm{pOH}=\frac12\Big(\mathrm pK_w-\mathrm pK_a-\log C_{eq}\Big)\cdot(-1)\ \Rightarrow\ \mathrm{pOH}=\frac12\mathrm pK_w-\frac12\mathrm pK_a+\frac12\log\frac{1}{C_{eq}}

Working through the logarithm bookkeeping carefully: −log⁡x=−12log⁡Kw+12log⁡Ka−12log⁡Ceq-\log x = -\tfrac12\log K_w+\tfrac12\log K_a-\tfrac12\log C_{eq}, i.e.

pOH=12pKw−12pKa−12log⁡Ceq\mathrm{pOH}= \frac12\mathrm pK_w-\frac12\mathrm pK_a-\frac12\log C_{eq}

Then using pH=pKw−pOH\mathrm{pH}=\mathrm pK_w-\mathrm{pOH} with pKw=14.00\mathrm pK_w=14.00 at 25 °C,

pHeq=pKw−(12pKw−12pKa−12log⁡Ceq)=12pKw+12pKa+12log⁡Ceq\mathrm{pH}_{eq} = \mathrm pK_w-\left(\frac12\mathrm pK_w-\frac12\mathrm pK_a-\frac12\log C_{eq}\right)=\frac12\mathrm pK_w+\frac12\mathrm pK_a+\frac12\log C_{eq}

With pKw=14.00\mathrm pK_w=14.00, 12pKw=7.00\tfrac12\mathrm pK_w=7.00, giving the stated result

pHeq=7.00+12pKa+12log⁡Ceq\mathrm{pH}_{eq}=7.00+\frac12\mathrm pK_a+\frac12\log C_{eq}

Limiting case check. As Ka→KwK_a\to K_w (an acid so weak its conjugate base behaves almost like a strong base), pKa→14\mathrm pK_a\to 14, giving pHeq→14+12log⁡Ceq\mathrm{pH}_{eq}\to 14+\tfrac12\log C_{eq} — correctly approaching the pH of a strong base solution of concentration CeqC_{eq}, consistent with the fact that an infinitely weak acid's "titration" is really just diluting a strong base's worth of hydroxide equivalent.

Go deeper · Derivation B · 3 minFeasibility threshold: why CKa ≳ 10⁻⁸
Derivation BFeasibility threshold: why CKa ≳ 10⁻⁸

Goal. Show that the standard practical threshold for titrating a weak acid — CKa≳10−8CK_a\gtrsim10^{-8} — follows from requiring the fractional dissociation of HA to be neither negligible (curve indistinguishable from titrating water) nor so large the acid behaves as effectively strong (also fine, but the interesting boundary is the weak side).

Step 1 — Fractional dissociation at the start of titration. For a weak acid alone in water at concentration CC, the fraction ionized is

α=[A−]C=−Ka+Ka2+4KaC2C\alpha = \frac{[\mathrm A^-]}{C}=\frac{-K_a+\sqrt{K_a^2+4K_aC}}{2C}

For Ka≪CK_a\ll C (the ordinary "weak acid" regime), this simplifies to α≈Ka/C\alpha\approx\sqrt{K_a/C}.

Step 2 — Connect α\alpha to buffering capacity near the midpoint. The buffer capacity (Van Slyke capacity) of a HA/A⁻ mixture peaks at [HA]=[A−][\mathrm{HA}]=[\mathrm A^-], i.e. at half-equivalence, and there

βmax≈0.576 CT\beta_{max}\approx 0.576\,C_T

where CTC_T is the total analytical concentration of the acid/base pair at that point (a well-known result independent of KaK_a provided the acid is weak enough that this half-equivalence buffer is actually well-formed, which requires [H+][\mathrm H^+] at that point, ≈Ka\approx K_a, to be small compared to CTC_T so that self-ionization of water and direct strong-acid-like behavior don't dominate).

Step 3 — What actually limits sharpness is the size of the discontinuity in slope, not the capacity itself. The controlling comparison is between the change in [H+][\mathrm H^+] demanded by the stoichiometry (a near step-function change as ff crosses 1) and the change in [H+][\mathrm H^+] that the leftover buffer components can "absorb" while resisting that change. Near equivalence, the residual concentration of unreacted HA (just before) or unreacted A⁻ hydrolysis product (just after) both scale as a fraction of CC, and the pH shift needed to titrate that residual through its own equilibrium scales as

Δ(pH near eq.)∼12log⁡ ⁣(1KaC)+const\Delta(\text{pH near eq.}) \sim \frac12\log\!\left(\frac{1}{K_aC}\right)+\text{const}

This diverges (curve gets sharper) as KaC→0K_aC\to 0 is wrong at face value — the correct sense is the opposite: as KaCK_aC shrinks, the concentration of H⁺ or OH⁻ generated by the analyte itself at equivalence (of order KwC/Ka⋅(…)\sqrt{K_wC/K_a}\cdot(\ldots), from Step 3 of the pH derivation) becomes comparable to [H+][\mathrm H^+] contributions from water autoionization and from small volumetric/experimental uncertainties in delivered titrant, washing out any sharp inflection. Formally, the second-derivative test for an inflection (d2pH/dV2=0d^2\mathrm{pH}/dV^2=0 at a genuine equivalence point) requires the first derivative dpH/dVd\mathrm{pH}/dV at that point to exceed the noise floor δ(pH)/δV\delta(\mathrm{pH})/\delta V set by delivery precision.

Step 4 — Quantifying the threshold. Empirically and from numerical solution of the full titration cubic (Ringbom's classical treatment), the pH change across the interval f=0.999f=0.999 to f=1.001f=1.001 (i.e., ±0.1%\pm0.1\% of VeqV_{eq}, matched to ordinary buret precision of about one drop in 50 mL) drops below about 0.3–0.4 pH units — too small to be read reliably by eye with an indicator, or to locate confidently even with a pH meter to better than a few percent relative error in VeqV_{eq} — right around

CKa≈10−8CK_a \approx 10^{-8}

using CC = the analyte's initial formal concentration (mol/L) before titrant dilution. This is why the criterion is quoted as a round number: it is not a sharp physical cutoff (there is no discontinuity in nature) but the point at which the achievable break falls below what ordinary glassware and detection methods can resolve.

Limiting case check. At C=0.10C=0.10 M (a typical titrant/analyte concentration), the threshold Ka≳10−8/0.10=10−7K_a\gtrsim10^{-8}/0.10=10^{-7} says any acid with pKa\mathrm pK_a up to about 7 is titratable at this concentration — consistent with textbook practice of titrating acids as weak as pKa≈6\mathrm pK_a\approx6–77 (e.g., some substituted phenols) at ordinary concentrations, while acids like phenol itself (Ka=1.0×10−10K_a=1.0\times10^{-10}) are known to be essentially untitratable in water at 0.1 M (CKa=1.0×10−11CK_a=1.0\times10^{-11}, three orders of magnitude below threshold) — matching common laboratory experience that phenol cannot be titrated directly with aqueous NaOH using a color-change endpoint.

Worked examples

Example 1 — Foundational: is 0.120 M chloroacetic acid titratable, and where does its equivalence point sit? Chloroacetic acid, Ka=1.36×10−3K_a = 1.36\times10^{-3} (pKa=2.867\mathrm pK_a=2.867), is titrated as a 0.120 M solution (V0=25.00V_0=25.00 mL) with 0.150 M NaOH. Feasibility check first.

CKa=(0.120)(1.36×10−3)=1.63×10−4CK_a = (0.120)(1.36\times10^{-3}) = 1.63\times10^{-4}

This exceeds 10−810^{-8} by four orders of magnitude — an unambiguous, comfortably titratable system, expected to give a break of several pH units. Equivalence volume. Moles HA =0.120 mol/L×0.02500 L=3.00×10−3= 0.120\ \mathrm{mol/L}\times0.02500\ \mathrm L = 3.00\times10^{-3} mol. Then

Veq=3.00×10−3 mol0.150 mol/L=0.02000 L=20.00 mLV_{eq} = \frac{3.00\times10^{-3}\ \mathrm{mol}}{0.150\ \mathrm{mol/L}} = 0.02000\ \mathrm L = 20.00\ \mathrm{mL}

Concentration of A⁻ at equivalence. Total volume =25.00+20.00=45.00= 25.00+20.00=45.00 mL, so

Ceq=3.00×10−3 mol0.04500 L=0.0667 MC_{eq} = \frac{3.00\times10^{-3}\ \mathrm{mol}}{0.04500\ \mathrm L} = 0.0667\ \mathrm{M}

Equivalence-point pH, using the derived relation:

pHeq=7.00+12(2.867)+12log⁡(0.0667)\mathrm{pH}_{eq}=7.00+\frac12(2.867)+\frac12\log(0.0667)
pHeq=7.00+1.434+12(−1.176)=7.00+1.434−0.588=7.85\mathrm{pH}_{eq}=7.00+1.434+\frac12(-1.176)=7.00+1.434-0.588=7.85

So the equivalence point sits at pH 7.85 — mildly basic, as expected for the conjugate base of a moderately strong weak acid, and well inside the transition range of phenolphthalein (8.0–9.6, admittedly at the low edge — bromothymol blue, 6.0–7.6, or a calculated potentiometric endpoint would be safer choices, foreshadowing the indicator-selection logic developed under Acid-Base Indicators: Theory and Transition Range). The comfortably large CKaCK_a value guarantees a sharp break; the choice of indicator is then a secondary, separate question of matching the transition range to pHeq\mathrm{pH}_{eq}.

Example 2 — Applied: standardizing a NaOH solution against potassium hydrogen phthalate (KHP), and checking whether dilution during the titration compromises the endpoint. KHP (monoprotic as the acidic proton relevant here, Ka=3.9×10−6K_a = 3.9\times10^{-6}, pKa=5.41\mathrm pK_a = 5.41) is a National Institute of Standards and Technology-traceable primary standard. Suppose 0.7112 g of KHP (molar mass 204.22 g/mol) is dissolved in 75.00 mL of water and titrated with NaOH of nominal concentration 0.1000 M. Moles KHP:

n=0.7112 g204.22 g/mol=3.483×10−3 moln = \frac{0.7112\ \mathrm g}{204.22\ \mathrm{g/mol}} = 3.483\times10^{-3}\ \mathrm{mol}

Predicted equivalence volume:

Veq=3.483×10−3 mol0.1000 mol/L=34.83 mLV_{eq} = \frac{3.483\times10^{-3}\ \mathrm{mol}}{0.1000\ \mathrm{mol/L}} = 34.83\ \mathrm{mL}

Initial concentration of the acidic proton:

C0=3.483×10−3 mol0.07500 L=0.04644 MC_0 = \frac{3.483\times10^{-3}\ \mathrm{mol}}{0.07500\ \mathrm L} = 0.04644\ \mathrm M

Feasibility:

CKa=(0.04644)(3.9×10−6)=1.8×10−7CK_a = (0.04644)(3.9\times10^{-6}) = 1.8\times10^{-7}

Still comfortably above the 10−810^{-8} threshold (by a factor of 18), so KHP remains a workable, if noticeably gentler, titration than chloroacetic acid — consistent with the well-known practical fact that KHP titrations require a carefully chosen indicator (phenolphthalein, transition 8.0–9.6) and careful technique near the endpoint, rather than being "sloppy-proof" the way a strong-acid/strong-base titration is. Equivalence pH, with CeqC_{eq} computed at total volume 75.00+34.83=109.8375.00+34.83=109.83 mL:

Ceq=3.483×10−30.10983=0.03172 MC_{eq} = \frac{3.483\times10^{-3}}{0.10983} = 0.03172\ \mathrm M
pHeq=7.00+12(5.41)+12log⁡(0.03172)=7.00+2.705+12(−1.499)\mathrm{pH}_{eq} = 7.00+\frac12(5.41)+\frac12\log(0.03172) = 7.00+2.705+\frac12(-1.499)
pHeq=7.00+2.705−0.749=8.96\mathrm{pH}_{eq}=7.00+2.705-0.749=8.96

This lands squarely in phenolphthalein's transition range (colorless below ~8.0, fully pink above ~9.6, with the visually detected color change typically perceived around pH 8.5–9), explaining the traditional pairing of KHP standardizations with phenolphthalein and the classic advice to titrate to "the first persistent faint pink," since the true equivalence pH (8.96) sits above the midpoint of the indicator's range — titrating to full, robust pink would systematically overshoot VeqV_{eq}. Sensitivity check — does the exact concentration of KHP matter much? Suppose a student mistakenly dissolves the KHP in only 25.00 mL instead of 75.00 mL (a 3× concentration error in the analyte, though the titrant strength is unaffected). Then C0′=3.483×10−3/0.02500=0.1393C_0' = 3.483\times10^{-3}/0.02500=0.1393 M, and CKaCK_a rises to 5.4×10−75.4\times10^{-7} — the titration becomes sharper, not worse, and VeqV_{eq} is unchanged (it depends only on moles of KHP and molarity of titrant, not on the volume of water used to dissolve the solid). This confirms an important practical point: diluting the analyte before titrating affects curve sharpness and equivalence pH, but never the stoichiometric endpoint volume itself — a fact worth isolating explicitly since it is easy to conflate "dilution hurts the curve" with "dilution biases the result," which it does not.

Example 3 — Exam/competition level: two structurally similar weak acids, only one of which is titratable, and finding the minimum concentration at which the second becomes marginally feasible. Acid A: pKa=4.20\mathrm pK_a = 4.20 (Ka=6.31×10−5K_a=6.31\times10^{-5}). Acid B: pKa=8.90\mathrm pK_a = 8.90 (Ka=1.26×10−9K_a=1.26\times10^{-9}), structurally similar (say, a substituted phenol) but far weaker. Both are prepared at C=0.0500C=0.0500 M. Acid A feasibility:

CKa=(0.0500)(6.31×10−5)=3.16×10−6CK_a = (0.0500)(6.31\times10^{-5}) = 3.16\times10^{-6}

Well above 10−810^{-8} — clearly titratable, with equivalence pH (at, say, Ceq≈0.025C_{eq}\approx0.025 M after dilution by titrant) of

pHeq=7.00+12(4.20)+12log⁡(0.025)=7.00+2.10−0.80=8.30\mathrm{pH}_{eq}=7.00+\frac12(4.20)+\frac12\log(0.025)=7.00+2.10-0.80=8.30

a clean break usable with phenolphthalein or a pH meter. Acid B feasibility:

CKa=(0.0500)(1.26×10−9)=6.3×10−11CK_a = (0.0500)(1.26\times10^{-9}) = 6.3\times10^{-11}

This is roughly three orders of magnitude below the 10−810^{-8} threshold — acid B is not titratable at this concentration by any ordinary means. Its titration curve would be nearly indistinguishable from adding strong base to pure water: the "buffer region" barely exists because so little of the acid dissociates even at the start, and the equivalence-point break is buried in a curve that is already almost flat throughout. Question: at what concentration would acid B become marginally titratable (CKa=10−8CK_a = 10^{-8}, the threshold itself)?

Cmin=10−8Ka=10−81.26×10−9=7.9 MC_{min} = \frac{10^{-8}}{K_a} = \frac{10^{-8}}{1.26\times10^{-9}} = 7.9\ \mathrm{M}

This is a striking and instructive result: 7.9 M is far beyond the solubility of essentially any real weak acid in water (and would in any case violate the dilute-solution assumptions built into the derivation, such as ignoring activity coefficients and ionic strength effects). The calculation demonstrates concretely that acid B, with pKa=8.90\mathrm pK_a=8.90, cannot be made titratable in aqueous solution by any practically achievable concentration increase — the only fixes are a nonaqueous solvent (which changes the effective KaK_a entirely) or an entirely different analytical method, such as back-titration or a spectrophotometric approach, rather than direct acid–base titration in water. Limiting-case sanity check on Example 3: setting pKa\mathrm pK_a for acid B down to 6.90 instead of 8.90 (i.e., Ka=1.26×10−7K_a=1.26\times10^{-7}, a hundredfold stronger acid) gives Cmin=10−8/1.26×10−7=0.079C_{min}=10^{-8}/1.26\times10^{-7}=0.079 M — a perfectly ordinary, easily prepared concentration, showing the threshold behaves continuously and sensibly as KaK_a is dialed between "impossible" and "routine."

Limiting cases, scope & common traps

RegimeBehaviorFeasibility verdict
KaK_a large (strong-acid-like, Ka≳1K_a\gtrsim1), any reasonable CCCurve approaches strong-acid/strong-base shape; pHeq→7\mathrm{pH}_{eq}\to7Always feasible; formula for pHeq\mathrm{pH}_{eq} still applies but hydrolysis is negligible
CC large, KaK_a moderate (10−310^{-3}–10−610^{-6})Sharp, textbook-clean breakFeasible; standard titrations (acetic, chloroacetic, KHP) live here
CC small (<10−3<10^{-3} M), KaK_a moderateBreak present but narrower; indicator choice becomes criticalMarginal — check CKaCK_a explicitly
CC ordinary (0.01–0.5 M), KaK_a very small (<10−8<10^{-8})Curve nearly flat everywhere; no usable inflectionNot feasible by direct aqueous titration
Both CC small and KaK_a smallCurve indistinguishable from dilute strong-base addition to waterDefinitely not feasible
C→∞C\to\infty (hypothetical)CKaCK_a can always in principle be pushed above thresholdFeasible only if solubility and activity-coefficient assumptions remain valid — usually not achievable in practice for very weak acids
Ka→KwK_a\to K_wpHeq→14+12log⁡Ceq\mathrm{pH}_{eq}\to14+\tfrac12\log C_{eq} (limiting case in the first derivation)Acid indistinguishable from water itself; meaningless to titrate

The chemist behind it

The systematic, quantitative treatment of titration feasibility — going beyond qualitative "is it possible" toward a numerical criterion based on the size of the achievable break — is most closely associated with the Finnish analytical chemist Anders Ringbom, whose mid-twentieth-century work on complexometric and acid–base titration theory formalized the idea that a titration's usefulness could be quantified by the magnitude of the discontinuity in a titration function at the stoichiometric point, expressed as a function of the relevant equilibrium constant and concentration. Ringbom's approach — computing the change in a "p-function" (pH, pM, or pE depending on titration type) across a narrow window around the equivalence point, and comparing it to the resolving power of the detection method — is the direct ancestor of the CKaCK_a-type feasibility criteria used in every modern analytical chemistry course, and it generalizes cleanly to complexometric titrations (feasibility governed by CKfCK_f, the conditional formation constant) and redox titrations (feasibility governed by the separation of standard potentials, foreshadowing later material on redox titration curves).

Origins · 1 minAnders Ringbom and how this was discovered
AR
Anders Ringbom
1905–1976 · Finnish analytical chemist, professor at Åbo Akademi University, whose treatise "Complexation in Analytical Chemistry" (1963) established quantitative feasibility criteria for titrations across acid-base, complexometric, and redox systems, unifying them under a single conceptual framework of comparing a titration's break sharpness to instrumental or visual detection limits

History
- 1920s — Brønsted–Lowry acid–base theory establishes KaK_a as the central quantity governing weak-acid equilibria, the necessary foundation for any feasibility analysis.
- 1940s — Systematic tabulation of KaK_a values for organic and inorganic weak acids (Kolthoff and others) makes quantitative feasibility screening practical for the first time.
- 1963 — Anders Ringbom publishes a unified feasibility framework (jump-size versus detection-limit comparison) applicable across acid–base, complexometric, and redox titrations.
- 1960s–1970s — Widespread adoption of the pH meter and glass electrode shifts practical feasibility limits somewhat below the older visual-indicator-based thresholds, prompting refinement of the classical CKa≳10−8CK_a\gtrsim10^{-8} rule.
- Present — Computer-simulated titration curves and Gran-plot linearization methods let analysts test feasibility numerically for arbitrary CC and KaK_a before ever touching a buret, though the underlying CKaCK_a logic remains the conceptual backbone.
Why is it CKa and not just Ka or just C that determines feasibility?

Because the physical quantity that must exceed a detection threshold — the size of the pH jump near equivalence — emerges from the derivation as depending on the product of concentration and equilibrium constant, not on either alone. A very weak acid at very high concentration can dissociate enough to build a workable buffer and a workable break; a moderately strong weak acid at vanishingly low concentration has almost nothing there to react with sharply. Both extremes, and everything in between, are captured correctly only by tracking CKaCK_a together, which is exactly what the Ringbom-style feasibility analysis does.

Does the CKa ≳ 10⁻⁸ threshold change if I use a pH meter instead of an indicator?

Yes, somewhat. The number 10−810^{-8} was calibrated broadly around what a careful analyst can detect using color-change indicators and ordinary burets (roughly 0.3–0.5 pH unit of ambiguity). A well-calibrated glass electrode read to 0.01 pH unit, combined with first- or second-derivative (Gran plot) processing of closely spaced data points, can push the practical limit down by perhaps one to two orders of magnitude, to around CKa∼10−9CK_a\sim10^{-9}–10−1010^{-10}. Below that, however, the underlying equilibrium chemistry itself no longer produces a genuine inflection, and no instrument can recover information that the equilibrium has erased.

Why does diluting the analyte not change the equivalence volume, if it changes everything else about the curve?

The equivalence volume is fixed by stoichiometry: moles of titrant delivered at equivalence must equal moles of analyte originally present, and moles of analyte is set only by its original concentration times its original volume — a quantity untouched by how much extra water is added to the flask before titrating. What dilution does change is the shape of the curve (buffer region flattens, equivalence pH shifts toward 7) and the practical difficulty of locating that fixed volume experimentally, but the volume itself is a purely stoichiometric number.

How does this feasibility logic extend to weak base titrations with strong acid?

By complete symmetry: replace KaK_a with KbK_b for the weak base, and the equivalence-point pH formula becomes pHeq=7−12pKb−12log⁡Ceq\mathrm{pH}_{eq}=7-\tfrac12\mathrm pK_b-\tfrac12\log C_{eq} (the conjugate acid of the weak base now hydrolyzes to make the solution acidic at equivalence). The feasibility threshold becomes CKb≳10−8CK_b\gtrsim10^{-8}, derived by an entirely parallel argument built on the hydrolysis of the protonated conjugate acid rather than the deprotonated conjugate base. This is exactly the mirror-image logic used in Weak Base-Strong Acid Titration Curves.

Can two weak acids with very different Ka but the same CKa product give practically identical titration curves?

Not quite identical, though qualitatively similar in sharpness. The CKaCK_a product controls the size of the equivalence-point break to leading order, but the position of the curve (where the buffer region sits on the pH axis, roughly at pH≈pKa\mathrm{pH}\approx\mathrm pK_a at half-equivalence, and where pHeq\mathrm{pH}_{eq} sits) depends on KaK_a and CC separately, not just their product. Two acids with the same CKaCK_a but very different individual KaK_a and CC values will have breaks of comparable steepness occurring at quite different pH values on the vertical axis.

What happens if CKa is comfortably above threshold but the titrant itself is very dilute?

Feasibility as derived here concerns the analyte's own equilibrium behavior and assumes the titrant is strong (fully dissociated) regardless of its concentration — a dilute strong base is still a strong base and reacts completely with HA. What a very dilute titrant does affect is practical convenience: a larger volume must be delivered to reach equivalence, magnifying the effect of any fixed-volume delivery uncertainty (e.g., buret reading error) on the relative precision of VeqV_{eq}, and diluting CeqC_{eq} further, which modestly flattens the curve through the dilution term already built into the pHeq\mathrm{pH}_{eq} formula, but it does not introduce a separate feasibility failure mode.

Before this

Where this leads