The Mass Spectrum and the m/z Axis

A mass spectrum is a bar-code of a molecule's disassembly. Every peak is a fragment, weighed with extraordinary precision. The pattern of peaks encodes the molecule's identity almost as specifically as a fingerprint. This includes which one is tallest, which one sits at the far right edge. It also includes which cluster of small peaks trails a big one. Learning to read this axis is the single most transferable skill in mass spectrometry. Every later topic builds on this. This includes Electron Ionization and the Molecular Ion, Isotope Patterns in Mass Spectra, and Interpreting Fragmentation Patterns. Each is just a more detailed conversation about what is plotted on this same horizontal scale. The stakes are concrete. Consider a forensic toxicologist identifying a street drug. Consider a synthetic chemist confirming a coupling reaction worked. Consider a proteomics lab matching a peptide to a genome. All of them stare first at the same two axes. Mass-to-charge ratio runs left to right, and relative abundance runs bottom to top. Get the vocabulary wrong, and every downstream interpretation drifts. For example, confuse the base peak with the molecular ion. Or misread "m/z" as literally "mass." This is a foundational, almost bookkeeping-level topic. But it is the bookkeeping on which the entire structural-elucidation edifice stands. The big picture connects directly to the instrument itself. It is described in The Mass Spectrometer: Components and Workflow. Ions are made, then sorted by mass-to-charge ratio in some analyzer. This analyzer may be a magnetic sector, quadrupole, time-of-flight, or ion trap. A detector then counts the sorted ions. The output of that sorting-and-counting process is exactly the spectrum this article dissects. It is a histogram of ion abundance versus m/z. Nothing about the analyzer's mechanism changes what the axis means. A quadrupole and a time-of-flight instrument, given the same sample, should in principle report the same m/z values. They differ only in resolution, scan speed, and noise characteristics. This article delivers a precise operational vocabulary. This includes m/z, relative abundance, base peak, molecular ion (M⁺•), and the normalization convention. This convention turns raw ion counts into the percent-relative-abundance bar chart. That bar chart appears in every textbook and database. The article works through the arithmetic of normalization with real numbers. It distinguishes the molecular ion from the base peak with a worked example. In that example, the two are not the same peak. This is the case that trips up nearly every beginner. It also previews why real spectra show a forest of small peaks. These small peaks sit one and two mass units above the main ones. The mechanism behind this is not yet explained.

Key takeaways
  • The x-axis is m/z (mass-to-charge ratio), not "mass" — the two coincide only when charge z = 1, the overwhelmingly common case in routine EI-MS.
  • The y-axis is relative abundance, conventionally normalized so the tallest peak (the base peak) is set to 100%.
  • The base peak is the most abundant ion; it need not be the heaviest ion and need not be the molecular ion.
  • The molecular ion (M⁺•), when observed, sits at the m/z equal to the compound's molecular mass and represents the intact molecule stripped of one electron.
  • Peak intensities are read off a stick diagram: each vertical line's height is proportional to ion abundance at that m/z, reported to the nearest whole m/z unit in low-resolution work.
  • Small satellite peaks near the main peaks (M+1, M+2, …) are isotope contributions, not noise or error — a preview of a story told in full elsewhere.
  • Key idea: a mass spectrum is a normalized histogram of ion abundance versus mass-to-charge ratio, and every peak label (M⁺•, base peak, fragment) is a claim about which ion, at which m/z, produced how much signal relative to the strongest signal in that run.
The core insight

The mass spectrum plots relative abundance (y, base peak ≡ 100%) against m/z (x); reading it correctly means separating three independent facts about any one peak — its mass-to-charge ratio, its height relative to the base peak, and whether it corresponds to the intact molecular ion or a fragment.

Where this lives today

Every commercial spectral database — NIST/EPA/NIH mass spectral library, Wiley Registry, METLIN for metabolomics — stores compound identities exactly as this article has framed them: a list of (m/z, relative abundance) pairs, base peak normalized to 100%, molecular ion flagged separately when observed. Automated library-search algorithms used in forensic toxicology screening, doping-control laboratories, and environmental contaminant analysis compute similarity scores by comparing an unknown's normalized stick spectrum against thousands of reference spectra stored in precisely this format. In pharmaceutical quality control, LC-MS/MS methods used to confirm drug identity and purity report both the molecular ion (often as a protonated adduct [M+H]⁺ in soft ionization) and characteristic fragment ions, with regulatory guidance (such as that from the FDA and EMA) explicitly requiring the analyst to state which peak is the base peak and which corresponds to the intact analyte ion, avoiding exactly the confusion this article warns against. In proteomics and intact-protein mass spectrometry, multiply-charged ions generated by electrospray ionization populate an entire m/z axis with a "charge-state envelope" — a series of peaks at different m/z all corresponding to the same protein molecule, differing only in how many protons it happens to be carrying. Deconvolution software untangles this envelope back into a single neutral molecular mass, a direct and more elaborate descendant of the m/z-versus-mass distinction introduced here. Portable and benchtop GC-MS instruments used in field forensics, arson investigation, and airport security screening rely on exactly the normalized-stick-spectrum display convention described above, because it is the only representation robust enough to survive comparison against a stored library regardless of the specific instrument's sensitivity or the amount of sample recovered from a crime scene or checked bag.

Ask the tutor: In my spectrum, the tallest peak isn't at the highest m/z value I can find — which one should I call the molecular ion, and how do I justify that choice?

The physical picture

Picture the ion source of an electron-ionization mass spectrometer, described mechanically in The Mass Spectrometer: Components and Workflow. A beam of ~70 eV electrons strikes gas-phase molecules of the analyte and knocks out one electron, producing a radical cation:

M+e−⟶M+∙+2e−M + e^- \longrightarrow M^{+\bullet} + 2e^-

This species, called the molecular ion and given the symbol M⁺• (the dot marks the unpaired electron, the plus marks the missing electron's charge), carries essentially the full mass of the neutral molecule, now short one electron — an amount so small (0.00055 u) that it is ignored in ordinary integer-mass bookkeeping. The 70 eV impact deposits far more energy than a single C–C bond requires to break (roughly 3–4 eV), so a large fraction of molecular ions do not survive intact. They fragment, in ways that reflect the molecule's connectivity, into smaller ions and neutral pieces. Every ion produced — whether the surviving molecular ion or one of its fragments — is then accelerated, sorted by m/z in the mass analyzer, and struck against a detector that outputs a current or pulse count proportional to how many ions of that particular m/z arrived. The raw output is an ion current recorded as a function of m/z: a curve or, at typical unit-mass resolution, a set of discrete counts at integer m/z values. Two independent numbers describe each peak. First, its position on the x-axis — the mass-to-charge ratio itself, dimensionless by IUPAC convention (mass in atomic mass units divided by an integer charge number, itself dimensionless, though most working chemists still say "m/z = 91" as if it carried units of mass). Second, its height on the y-axis, which by long convention is rescaled relative to the single most abundant ion in the entire spectrum. That most-abundant ion, whatever its mass, defines the base peak and is assigned exactly 100% relative abundance; every other peak's height is reported as a percentage of that reference. This normalization is what allows spectra from different instruments, different ion currents, and different sample amounts to be compared directly — a spectrum plotted at 10⁻¹² A full-scale and one plotted at 10⁻⁹ A full-scale look identical once both are rescaled to base peak = 100%. It also means relative abundance carries no information at all about how much sample was present; a barely-detectable trace and a saturating overload give visually similar bar-chart shapes, though real-world dynamic range and detector saturation do impose practical limits.

Figure
Anatomy of a stick mass spectrum: m/z axis, relative abundance, base peak, and molecular ion
m/z Relative abundance (%) 100 50 0 43 m/z 43 58 m/z 58 15 71 86 M⁺• , m/z 86 M+1 (¹³C satellite) BASE PEAK MOLECULAR ION

Look at the figure's arithmetic carefully: the base peak at m/z 43 is set to 100% by definition, whatever its actual ion count was. The molecular ion at m/z 86 stands at only 22% relative abundance — smaller than the base peak, smaller even than the fragment at m/z 58 (30%) — yet it is still the molecular ion, because "molecular ion" is a statement about chemical identity (the intact molecule, radical-cation form) and mass, not about height. This is the single most common point of confusion for a first-time reader of a spectrum, and it is addressed head-on in the worked examples.

Figure
Same compound, same data, plotted with a different absolute ion-current scale — the normalized picture is identical
Raw ion current (arbitrary, instrument A) 43 4.8×10⁻⁹ A 58 86 Normalized spectrum (base peak = 100%) 43 (100%) 58 (30%) 86 (22%) =

The core ideas

The mass-to-charge ratio is formally defined as a ratio of two integers (mass number in atomic mass units, charge number in units of elementary charge):

mz=ion mass (u)number of elementary charges on the ion\frac{m}{z} = \frac{\text{ion mass (u)}}{\text{number of elementary charges on the ion}}

where: m is the ion's mass expressed in unified atomic mass units (u, numerically ≈ its nominal or monoisotopic mass), and z is the (positive integer, almost always 1 in routine EI spectra) number of charges the ion carries.

Reading: because z = 1 for the vast majority of ions formed by electron ionization, m/z is numerically equal to the ion's mass in daltons in nearly every spectrum an undergraduate will meet; the distinction becomes essential only for multiply-charged ions (electrospray of proteins, discussed elsewhere) where a single physical mass produces several different m/z peaks. Relative abundance is defined by a normalization against the tallest peak in the spectrum:

% Relative Abundancei=IiIbase peak×100\%\,\text{Relative Abundance}_i = \frac{I_i}{I_{\text{base peak}}} \times 100

where: IiI_i is the ion current (or integrated ion count) measured at a given m/z value ii, and Ibase peakI_{\text{base peak}} is the ion current at the single most abundant m/z in the spectrum — by construction the largest II value in the whole data set, so the base peak's own relative abundance is always exactly 100%.

Reading: every other bar in the spectrum is a fraction of the tallest bar; this is why relative-abundance spectra look identical whether the instrument's raw ion current was measured in picoamps or nanoamps — the normalization divides that instrument-dependent scale factor clean away. The nominal mass of the molecular ion, when a molecule of known elemental formula CcHhNnOo…\text{C}_c\text{H}_h\text{N}_n\text{O}_o\ldots loses one electron, is essentially the sum of the most abundant isotope masses:

m(M+∙)≈12.000 c+1.00783 h+14.00307 n+15.99491 o+⋯m(\text{M}^{+\bullet}) \approx 12.000\,c + 1.00783\,h + 14.00307\,n + 15.99491\,o + \cdots

where: each coefficient is the exact mass of the most abundant naturally occurring isotope of that element (¹²C, ¹H, ¹⁴N, ¹⁶O, …), and the sum is taken over all atoms in the molecular formula, with the mass of the missing electron (0.00055 u) conventionally neglected at this level of precision.

Reading: this equation is the bridge between a structural formula on paper and a single number on the m/z axis — it is why a chemist can predict, before ever running the sample, roughly where the molecular ion peak should appear.

Derivation AFrom raw detector counts to the normalized bar chart

Goal. Show explicitly how a table of raw ion counts recorded during a scan becomes the percent-relative-abundance values printed under each stick in a published spectrum.

Step 1 — the raw data. During a single scan, the detector (an electron multiplier, in most EI instruments) records an ion arrival rate (counts per second, or an amplified current in amps) at each m/z value visited. Suppose a scan of some hydrocarbon fragment ion series returns the following representative currents, in arbitrary detector units (a.u.): m/z 15 → 1,150 a.u.; m/z 43 → 9,600 a.u.; m/z 58 → 2,880 a.u.; m/z 71 → 480 a.u.; m/z 86 → 2,112 a.u. These are the numbers actually plotted in the first figure.

Step 2 — identify the base peak. Scan the list of raw currents for the single largest value. Here that is 9,600 a.u. at m/z 43. By definition this becomes the base peak, and it is assigned relative abundance 100% regardless of its absolute current.

Step 3 — normalize every peak, including the base peak itself, against that maximum. Apply the normalization equation to each entry:

%RA(15)=11509600×100=11.98%≈12%\%\text{RA}(15) = \frac{1150}{9600}\times100 = 11.98\% \approx 12\%
%RA(43)=96009600×100=100%\%\text{RA}(43) = \frac{9600}{9600}\times100 = 100\%
%RA(58)=28809600×100=30.0%\%\text{RA}(58) = \frac{2880}{9600}\times100 = 30.0\%
%RA(71)=4809600×100=5.0%\%\text{RA}(71) = \frac{480}{9600}\times100 = 5.0\%
%RA(86)=21129600×100=22.0%\%\text{RA}(86) = \frac{2112}{9600}\times100 = 22.0\%

Step 4 — check internal consistency. Every computed percentage must lie between 0% and 100% inclusive, with exactly one peak (the base peak) equal to 100%; any percentage exceeding 100% signals an arithmetic or identification error, since nothing in the spectrum can by definition exceed the base peak's own normalized height. All five values above satisfy 0<%RA≤1000 < \%\text{RA} \le 100, with m/z 43 alone reaching the ceiling — consistent with the stick diagram already drawn.

Step 5 — state the general result. The percent relative abundance of any peak ii is fixed the instant the base peak is identified; changing the total sample amount, ionization efficiency, or detector gain rescales every raw current by the same multiplicative factor kk, so

%RAi=kIikIbase×100=IiIbase×100\%\text{RA}_i = \frac{k I_i}{k I_{\text{base}}}\times 100 = \frac{I_i}{I_{\text{base}}}\times 100

is unchanged — the normalized spectrum is an intrinsic property of the sample's fragmentation behavior at a fixed ionization energy, not of how much material was injected.

Go deeper · Derivation B · 1 minPredicting the nominal mass of a molecular ion from a molecular formula
Derivation BPredicting the nominal mass of a molecular ion from a molecular formula

Goal. Derive, from first principles of isotope masses, exactly where the molecular ion of a specific compound should land on the m/z axis, and confirm it against the base-peak/molecular-ion figure above.

Step 1 — write the molecular formula. Take 2-hexanone, CH₃COCH₂CH₂CH₂CH₃, molecular formula C₆H₁₂O. Count atoms directly from the structure: 6 carbons, 12 hydrogens, 1 oxygen.

Step 2 — assemble exact monoisotopic masses. Use the most abundant isotope of each element: ¹²C ≡ 12.0000 u (exact, by definition of the unified atomic mass unit), ¹H = 1.00783 u, ¹⁶O = 15.99491 u.

Step 3 — sum contributions atom type by atom type.

6×12.0000=72.0000 u6\times12.0000 = 72.0000\ \text{u}
12×1.00783=12.0940 u12\times1.00783 = 12.0940\ \text{u}
1×15.99491=15.9949 u1\times15.99491 = 15.9949\ \text{u}

Step 4 — add the three subtotals.

m(M)=72.0000+12.0940+15.9949=100.0889 um(\text{M}) = 72.0000 + 12.0940 + 15.9949 = 100.0889\ \text{u}

Step 5 — subtract the mass of the departed electron and round to nominal (integer) mass for low-resolution reporting. The neutral molecule's exact mass is 100.089 u; removing one electron (0.00055 u) changes this in the sixth significant figure, utterly negligible at unit-mass resolution. The molecular ion should therefore appear at

m/z(M+∙)=100  (nominal, to the nearest whole number)m/z(\text{M}^{+\bullet}) = 100 \ \ (\text{nominal, to the nearest whole number})

Step 6 — limiting-case sanity check. If instead the molecule contained no oxygen at all (say hexane, C₆H₁₄, replacing the carbonyl oxygen with two more hydrogens), the same procedure gives 6(12.0000)+14(1.00783)=72.0000+14.1096=86.116(12.0000) + 14(1.00783) = 72.0000+14.1096 = 86.11 u, nominal mass 86 — precisely the m/z value chosen for the molecular ion in the worked stick-diagram figure above, confirming the bookkeeping is self-consistent between the schematic figure and this general method. As oxygen or nitrogen atoms are added or removed from a formula, the predicted nominal mass shifts by their respective integer nominal masses (16 for O, 14 for N), a pattern that becomes the basis of the nitrogen rule discussed under Electron Ionization and the Molecular Ion.

Worked examples

Example 1 (foundational) — building the normalized spectrum from a raw data table. A low-resolution EI mass spectrum of methyl butanoate (CH₃CH₂CH₂CO₂CH₃, MW 102) is recorded, and the electron multiplier reports the following peak-area currents (arbitrary units, a.u.), reading directly off the instrument's data system:

m/zRaw current (a.u.)
291,840
433,220
716,900
74780
1021,518

Step 1. Scan for the maximum raw current: 6,900 a.u. at m/z 71. This is the base peak, corresponding structurally to loss of •OCH₃ from the molecular ion (an acylium ion, CH₃CH₂CH₂C≡O⁺). Step 2. Normalize every entry against 6,900:

%RA(29)=18406900×100=26.7%\%\text{RA}(29) = \frac{1840}{6900}\times100 = 26.7\%
%RA(43)=32206900×100=46.7%\%\text{RA}(43) = \frac{3220}{6900}\times100 = 46.7\%
%RA(71)=100%  (base peak, by construction)\%\text{RA}(71) = 100\%\ \ (\text{base peak, by construction})
%RA(74)=7806900×100=11.3%\%\text{RA}(74) = \frac{780}{6900}\times100 = 11.3\%
%RA(102)=15186900×100=22.0%\%\text{RA}(102) = \frac{1518}{6900}\times100 = 22.0\%

Step 3. Identify the molecular ion. Its m/z must equal the compound's molecular weight — here 102, matching the given formula's nominal mass (5×12+10×1.00783+2×15.99491=60+10.078+31.990=102.075\times12 + 10\times1.00783 + 2\times15.99491 = 60 + 10.078 + 31.990 = 102.07 u, nominal 102). So the peak at m/z 102, at 22.0% relative abundance, is M⁺•. Step 4. State the answer with correct terminology: the base peak is at m/z 71 (100%), the molecular ion is at m/z 102 (22.0%), and these are two different peaks — a result that is completely typical of esters, which fragment efficiently at 70 eV and rarely give a molecular ion taller than several of their fragments.

Example 2 (applied) — using base-peak identity as a first clue in unknown identification. A quality-control chemist runs GC-MS on a suspected batch of acetophenone (C₆H₅COCH₃, MW 120) contaminated with an unknown side product. The total ion chromatogram shows two resolved peaks; the mass spectrum under the second chromatographic peak shows a base peak at m/z 105 (100%), a moderate peak at m/z 77 (65%), a small peak at m/z 51 (18%), and a peak at m/z 120 (38%). Step 1. Interpret m/z 120 first, since it is a candidate molecular ion: it matches acetophenone's nominal mass exactly (8×12+8×1.00783+15.99491=96+8.063+15.995=120.068\times12 + 8\times1.00783 + 15.99491 = 96+8.063+15.995=120.06 u, nominal 120), so tentatively M⁺• = 120. Step 2. Interpret m/z 105 as loss of a 15-mass-unit fragment from the molecular ion:

120−105=15 u,consistent with loss of a methyl radical (∙CH3)120 - 105 = 15\ \text{u},\quad \text{consistent with loss of a methyl radical (}^{\bullet}\text{CH}_3\text{)}

producing the resonance-stabilized benzoyl cation, C₆H₅C≡O⁺, at m/z 105 — chemically reasonable as the dominant fragmentation channel, which is exactly why it is the base peak rather than the molecular ion. Step 3. Interpret m/z 77 as loss of carbon monoxide from the benzoyl cation:

105−77=28 u=CO105 - 77 = 28\ \text{u} = \text{CO}

giving the phenyl cation, C₆H₅⁺, at m/z 77 — a classic, textbook-recognizable fragment. Step 4. Interpret m/z 51 as loss of acetylene (C₂H�2, 26 u) from the phenyl cation:

77−51=26 u=C2H277-51 = 26\ \text{u} = \text{C}_2\text{H}_2

Step 5. Conclude: every peak is self-consistently explained as a stepwise fragmentation of acetophenone (120 → 105 → 77 → 51), so the second chromatographic peak is authentic acetophenone, not a contaminant, and the base peak (m/z 105, 100%) is the acylium fragment, not the molecular ion (m/z 120, only 38%) — precisely the terminology distinction the article opened with, now applied to solve a real identification problem.

Example 3 (exam/competition level) — reconstructing an incomplete normalized spectrum and testing the ceiling constraint. A partially transcribed spectrum lists four peaks with the following relative abundances: m/z 27 (38.5%), m/z 55 (100%, "base peak" labeled by the original analyst), m/z 70 (61.9%), and m/z 98 (xx%, illegible in the notebook). The chemist recalls that the raw ion currents, before normalization, were 640 a.u., 1,664 a.u., 1,030 a.u., and 292 a.u. respectively, for m/z 27, 55, 70, and 98, in that order. Determine xx, and verify the "base peak" label was assigned correctly. Step 1 — verify the base peak claim independently of the label. Compare the four raw currents directly: 640, 1664, 1030, 292. The maximum is 1664 a.u., occurring at m/z 55 — so the base-peak assignment is correct; m/z 55 does have the largest raw ion current among the four listed peaks. Step 2 — recompute the two given percentages as an internal consistency check on the normalization constant.

%RA(27)=6401664×100=38.46%≈38.5% ✓\%\text{RA}(27) = \frac{640}{1664}\times100 = 38.46\% \approx 38.5\%\ \checkmark
%RA(70)=10301664×100=61.90%≈61.9% ✓\%\text{RA}(70) = \frac{1030}{1664}\times100 = 61.90\% \approx 61.9\%\ \checkmark

Both match the notebook's transcribed values to the precision given, confirming 1,664 a.u. is indeed the correct normalization denominator throughout this data set. Step 3 — solve for the missing percentage at m/z 98.

x=2921664×100=17.55%x = \frac{292}{1664}\times100 = 17.55\%

Step 4 — sanity-check the answer against the ceiling rule. Since 292 a.u. < 1664 a.u., xx must lie strictly between 0% and 100%; 17.55% satisfies this comfortably, with plenty of margin, so no transcription error is indicated. Step 5 — identify m/z 98 chemically, as a bonus check. If this spectrum belongs to cyclohexanone (C₆H₁₀O, nominal mass 6×12+10×1.00783+15.99491=72+10.078+15.995=98.076\times12+10\times1.00783+15.99491 = 72+10.078+15.995=98.07, nominal 98), then m/z 98 is the molecular ion itself, appearing here at 17.55% relative abundance — smaller than three separate fragment peaks (m/z 27, 55, and 70, the ring-opening/CO-loss fragments characteristic of cyclic ketones), once again illustrating that the molecular ion is frequently not the tallest peak in the spectrum, exactly as flagged in the very first figure of this article.

Limiting cases, scope & common traps

SituationWhat the axis/terminology meansCommon error to avoid
Singly charged ion (z = 1), the routine EI casem/z is numerically equal to ion mass in daltonsSaying "the mass axis" as if z were never anything but 1
Multiply charged ion (z = 2, 3, …), common in ESI of large biomoleculesSame physical ion mass appears at several different, smaller m/z valuesAssuming a peak at m/z 500 must mean a 500 Da ion
Base peak = molecular ion (occurs for very stable ring systems, aromatics)Both labels correctly apply to the same single peakAssuming this coincidence is the typical case rather than a special one
Base peak ≠ molecular ion (occurs for esters, aliphatic ketones, most fragmenting molecules)Two distinct peaks, two distinct facts, both legitimateCalling the tallest peak "the molecular ion" out of habit
No detectable molecular ion at allExtensive fragmentation consumed all M⁺•; M is inferred indirectly (softer ionization, chemical logic)Concluding the compound "has no molecular weight" rather than that M⁺• simply fell below the noise floor
Very low intensity, near baseline noiseRelative abundance can be near 0% and still represent a real, identifiable ionDiscarding a small, chemically diagnostic peak as "just noise"

The chemist behind it

The vocabulary and conventions used throughout this article — m/z, the normalized base-peak scale, the very idea of plotting a "spectrum" of masses — trace back to the parallel invention of mass spectrography by Francis William Aston and, earlier, the foundational work of J. J. Thomson on positive rays. But the person most responsible for turning mass spectrometry from a physicist's tool for measuring isotope masses into a chemist's routine structural technique was Fred W. McLafferty, whose systematic cataloguing of fragmentation behavior (and the rearrangement that bears his name) established the interpretive logic — reading peak-to-peak mass losses as chemical bond cleavages — that Example 2 and Example 3 above rely on directly.

Origins · 1 minFred W. McLafferty and how this was discovered
FW
Fred W. McLafferty
1923–2021 · American analytical chemist, Cornell University

McLafferty spent decades building the empirical and mechanistic foundation for interpreting electron-ionization mass spectra of organic molecules, moving the field from isotope physics toward structural organic chemistry. His 1959 description of what became known as the McLafferty rearrangement — a six-membered-ring transition state through which a molecular ion loses a neutral alkene fragment via γ-hydrogen transfer — gave chemists a predictive, mechanistic rule for peaks that had previously been merely catalogued. He also drove the large-scale compilation of reference spectra into searchable libraries, work that underlies every modern computerized spectral-match identification.

History
- 1897 — J. J. Thomson identifies the electron and begins investigating positive rays, the ancestor technique to mass spectrometry.
- 1919 — Francis Aston builds the first true mass spectrograph and discovers isotopes of neon by mass separation, work recognized with the 1922 Nobel Prize in Chemistry.
- 1942 — Commercial EI mass spectrometers become available for petroleum and organic analysis, standardizing routine m/z scanning.
- 1959 — Fred McLafferty describes the rearrangement mechanism that carries his name, giving structural chemists a predictive tool for interpreting fragment peaks.
- 1966 — Chemical ionization is introduced, softening fragmentation and producing spectra with a much more prominent molecular-ion-region peak, directly motivating the base-peak-versus-molecular-ion distinction taught here.
Why is the y-axis called "relative abundance" instead of just "intensity" or "counts"?

"Relative abundance" specifically signals that the numbers have been normalized against the base peak and are therefore percentages, not raw instrument counts or currents. Calling it simply "intensity" risks implying an absolute, instrument-dependent quantity, when in fact the entire point of the convention is that two different instruments, given the same sample, should report the same set of relative-abundance percentages even though their raw ion currents (in amps or counts per second) can differ by orders of magnitude. The word "relative" is doing real, load-bearing work: it means "relative to the base peak," a fixed internal reference chosen anew for every individual spectrum, exactly as the derivation in this article works through numerically.

Is the base peak always the same as the molecular ion?

No, and this is the most important distinction taught here. The molecular ion is defined structurally — it must be the intact molecule minus one electron, so its m/z must match the compound's molecular weight. The base peak is defined purely by height — it is whichever peak in that particular spectrum happens to have the largest ion current. For robust, highly conjugated, or aromatic molecules the two frequently coincide, because the intact radical cation is unusually stable and survives ionization well. For most aliphatic compounds, especially those bearing easily broken bonds (esters, ketones with accessible α-hydrogens, branched alkanes), a fragment ion outcompetes the molecular ion for abundance, and the base peak sits at a different, usually lower, m/z.

Does a taller peak always mean more of that ion's structure is chemically "preferred," in some thermodynamic sense?

Peak height reflects the kinetics of ion fragmentation pathways under the specific conditions of electron ionization (typically 70 eV electron energy, gas-phase, low pressure), not a thermodynamic equilibrium. A tall fragment peak means that particular bond-cleavage pathway is fast and low-barrier from the excited molecular ion's perspective — often because it produces an especially stable cation (resonance-stabilized acylium or benzylic cations, for instance) or loses an especially stable small neutral (CO, an alkene, water). This kinetic framing is central to the mechanistic reasoning used in Interpreting Fragmentation Patterns, where peak-to-peak mass differences are read as specific, chemically reasonable bond cleavages rather than arbitrary numbers.

What happens to the spectrum if the electron energy used for ionization is lowered from the standard 70 eV?

Lowering electron energy toward the ionization threshold reduces the internal energy deposited into the molecular ion, so less fragmentation occurs and the molecular ion peak grows relative to the fragment peaks — sometimes becoming the base peak itself. Below roughly 15 eV, ionization efficiency drops sharply and total signal becomes very weak, which is why 70 eV became the practical standard: it lies on a broad plateau where ionization efficiency is high and fragmentation patterns are highly reproducible from instrument to instrument, letting spectra be compared meaningfully against library references. This tradeoff, and gentler alternatives like chemical ionization, are developed further in Electron Ionization and the Molecular Ion.

Why do real spectra show small peaks one or two mass units above a main peak, and should a beginner worry about them?

Those satellite peaks (commonly called M+1 and M+2 relative to whichever main peak they trail) arise because natural samples are isotopic mixtures — a small but fixed fraction of every carbon atom is ¹³C rather than ¹²C, and analogous minor isotopes exist for Cl, Br, S, and other elements. A beginner should not discard these as noise; they are real, quantitatively predictable signal that in fact encodes useful information (number of carbons present, presence of chlorine or bromine, and so on). The full quantitative treatment of these ratios is the subject of Isotope Patterns in Mass Spectra; for the purposes of simply reading the m/z axis, it is enough to recognize such peaks as isotopic in origin rather than as fragmentation products or instrumental artifacts.

Can relative abundance values from two different runs of the same compound be compared directly, peak-for-peak?

Yes, to a good approximation, provided the ionization method and electron energy are held constant (the 70 eV EI standard exists precisely to make such comparisons reliable), because the normalization step removes dependence on sample quantity and detector gain. Small run-to-run variations of a few percent in relative abundance are normal and expected, arising from minor differences in source temperature, pressure, or instrument tuning; spectral library matching algorithms are built with tolerance for exactly this level of noise. Large, systematic differences instead usually indicate a genuinely different compound, a different ionization method (EI versus CI versus ESI), or a different charge state, not simply run-to-run instrumental drift.

If a spectrum shows no peak at all near the expected molecular weight, does that mean the molecular formula guess was wrong?

Not necessarily — it may simply mean the molecular ion is too unstable to survive the 70 eV EI process in detectable numbers, a common situation for alcohols, branched-chain compounds, and molecules with easy fragmentation pathways from an easily ionized site. In such cases chemists often switch to a softer ionization technique (chemical ionization, or electrospray in LC-MS) specifically to preserve and observe [M+H]⁺ or another intact adduct ion, rather than concluding the proposed formula must be incorrect. The absence of a peak at the expected mass under harsh EI conditions is diagnostic of fragmentation efficiency, not proof that the molecular weight assignment itself is wrong.

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