Conformations of Butane: Gauche and Anti

Take a molecule of butane, grab the C2–C3 bond with two mental hands, and twist. Nothing breaks — no bond is made or lost. Yet the potential energy of the molecule rises and falls smoothly as you rotate. It traces out a landscape with two distinct kinds of valleys and two distinct kinds of hills. This is the conformational analysis of butane. It is the first molecule complicated enough to show that not all staggered arrangements are equally good. Not all eclipsed arrangements are equally bad, either. It is the natural sequel to the ethane story. There, every staggered conformation was identical by symmetry. Every eclipsed conformation was identical too. Butane matters because it is the smallest possible model for a common situation. That situation arises whenever a carbon chain carries a substituent bigger than hydrogen on each of two adjacent carbons. The moment you replace one of ethane's six hydrogens with a methyl group on each carbon, the rotational profile splits. The single staggered minimum of ethane becomes two inequivalent minima (anti and gauche). The single eclipsed maximum splits into two inequivalent maxima (methyl-eclipsing-methyl, and methyl-eclipsing-hydrogen). Understanding why requires combining two physical effects. Torsional strain from filled-orbital interactions was already present in ethane. A new effect appears too, one that ethane's hydrogens were too small to reveal: steric strain. This is the van der Waals repulsion between atoms or groups that crowd each other in space. The big picture is that conformational preferences are not exotic quantum curiosities. They are the mechanistic seed of essentially all higher structural chemistry. The anti/gauche energy difference in butane (about 0.9 kcal/mol) sets an important scale. It explains why polymer chains, lipid tails, and protein side chains prefer extended over folded local geometries. The gauche destabilization itself is the direct ancestor of 1,3-diaxial strain in cyclohexanes. This article works out, bond by bond and orbital by orbital, why the anti conformer is the global minimum. It explains why gauche is a local minimum roughly 0.9 kcal/mol higher. It explains why the two eclipsed maxima differ by roughly 2.5 kcal/mol. Finally, it shows how to build the full energy-versus-dihedral curve from these pieces. This uses nothing but curved-arrow orbital reasoning and hard-sphere steric bookkeeping. By the end you will be able to construct butane's torsional energy diagram from scratch. You will be able to assign Newman projections to every stationary point. You will be able to rank the four distinct conformers by energy with justified numbers. And you will be able to explain — mechanistically, not just by rote — why "anti is best, gauche is next, and the two eclipsed forms are both bad but not equally bad."

Key takeaways
  • Rotation about the C2–C3 bond of butane generates a mix of torsional (hyperconjugative) and steric (van der Waals) effects, unlike ethane where only torsional strain operates.
  • Four distinct stationary conformers exist per 360° turn: anti (θ = 180°), gauche (θ = ±60°), and two eclipsed forms — methyl/methyl eclipsed (θ = 0°) and methyl/H eclipsed (θ = ±120°).
  • Anti is the global minimum; gauche lies about 0.9 kcal/mol higher due to steric repulsion between the two methyl groups 60° apart.
  • The fully eclipsed (methyl-over-methyl, θ = 0°) conformer is the global maximum, roughly 4.5–5.0 kcal/mol above anti; the methyl/H-eclipsed maxima are lower, roughly 3.6 kcal/mol above anti.
  • The anti ⇌ gauche equilibrium favors anti by about 70:30 to 75:25 at room temperature, computable directly from ΔG∘\Delta G^\circ via Keq=e−ΔG∘/RTK_{eq} = e^{-\Delta G^\circ/RT}.
  • The gauche interaction — steric strain between two groups 60° apart — recurs throughout organic chemistry, most famously as 1,3-diaxial strain in cyclohexane chairs.
  • Key idea: rotating the C2–C3 bond of butane superimposes van der Waals steric strain on top of ethane's torsional strain, splitting one staggered minimum into two (anti, gauche) and one eclipsed maximum into two (methyl/methyl, methyl/H).
The core insight

Conformational energy in butane is the sum of a torsional (hyperconjugative, orbital-overlap) contribution — periodic in the dihedral angle with the same threefold pattern as ethane — and a steric (through-space, van der Waals) contribution that depends on how close the two terminal methyl groups approach each other at a given dihedral angle. The gauche destabilization is steric, not torsional, in origin.

Where this lives today

The anti/gauche energetics of butane are not a historical curiosity confined to textbooks; they are the working currency of modern structural biology, materials science, and drug design. In lipid bilayers, the gauche-defect population along each hydrocarbon tail — governed by exactly the Boltzmann analysis above — determines membrane fluidity and phase-transition temperature, and is measured directly by deuterium NMR order parameters and Raman spectroscopy of C–H stretching regions. In polymer science, the fraction of gauche vs. anti bonds along a polyethylene chain controls chain persistence length, crystallinity, and mechanical modulus, and force-field parameters used in molecular dynamics simulations of polymers are calibrated directly against the butane rotational profile (this is, in fact, the standard benchmark test for any new molecular-mechanics force field: reproduce the butane anti/gauche/eclipsed energy diagram correctly, or the force field is rejected). In pharmaceutical chemistry, the preferred bioactive conformation of a flexible drug molecule binding to a protein pocket is frequently a higher-energy gauche-like rotamer paid for by favorable binding interactions — medicinal chemists routinely use the ≈0.9 kcal/mol gauche penalty as a benchmark "cost" that a binding interaction must overcome, when designing conformationally locked analogs (for example, replacing a flexible chain with a ring to pre-organize the bioactive gauche conformation and gain binding entropy). Finally, this same gauche-interaction bookkeeping is the direct conceptual ancestor of the 1,3-diaxial strain analysis used in Conformations of Cyclohexane: Chair and Ring Flip, and more broadly frames how chemists reason about Ring Strain in Cycloalkanes: Baeyer's Model and Reality whenever a ring geometry forces bond angles or dihedrals away from their free-rotation optimum.

Ask the tutor: How does the single butane gauche interaction generalize into the 1,3-diaxial strain analysis used for substituted cyclohexane chairs?

The physical picture

Consider butane, CH₃–CH₂–CH₂–CH₃, and focus on rotation about the central C2–C3 bond. Label the dihedral angle θ as the angle between the C1–C2 bond and the C3–C4 bond, measured looking down the C2–C3 axis in a Newman projection with C2 in front and C3 behind. At θ = 0°, the two methyl groups (C1 and C4) are eclipsed directly on top of each other. At θ = 180°, they point in exactly opposite directions. Every 60° of rotation brings you to another staggered or eclipsed arrangement, and because C2 and C3 each carry two hydrogens plus one methyl plus the bond to the other carbon, the substituent pattern on the front and back carbons is not threefold symmetric the way it is in ethane (where front and back are each three equivalent hydrogens). This asymmetry is exactly why the six stationary points along the rotation profile break into two pairs of inequivalent minima and maxima rather than one of each. At any dihedral angle, two physical effects operate simultaneously. The first is torsional strain, inherited unchanged in its physical origin from ethane: when two bonds on adjacent atoms are eclipsed, the filled σ(C–H) or σ(C–C) bonding orbital on the front carbon overlaps in a destabilizing four-electron sense with the filled σ-orbital on the back carbon behind it, while the stabilizing hyperconjugative donation σ(C–H) → σ*(C–H) is maximized precisely in the staggered geometry, where donor and acceptor orbitals are anti-periplanar (θ ≈ 180° between them locally). This is why staggered conformations are always torsionally preferred over eclipsed ones, for any bond, before any steric consideration is added. The second effect, entirely absent (or negligible) in ethane, is steric strain: the direct through-space van der Waals repulsion that arises when two atoms or groups are pushed closer together than the sum of their van der Waals radii. In ethane every eclipsing partner is a lone hydrogen (van der Waals radius ≈ 1.2 Å), so the steric penalty for eclipsing is small and the entire 2.9 kcal/mol barrier is essentially pure torsional strain. In butane, however, two of the substituents on the terminal carbons are methyl groups (effective steric bulk far larger than H), so whenever a rotation brings the two methyls close together — whether eclipsed or gauche-staggered — an additional steric penalty appears on top of the torsional background. This is the whole story of butane conformational analysis: take ethane's torsional profile, and add a steric bump wherever the two methyls get close.

Figure
Newman projections of the four stationary conformers of butane, viewed down C2→C3
CH₃ H H H H CH₃ anti, θ=180° E = 0 (reference) CH₃ H H H CH₃ H gauche, θ=60° E ≈ +0.9 kcal/mol CH₃ H H CH₃(behind) Me/Me eclipsed, θ=0° E ≈ +4.5–5.0 kcal/mol CH₃ H H H CH₃ Me/H eclipsed, θ=120° E ≈ +3.6 kcal/mol
Figure
Torsional energy of butane as a function of C2–C3 dihedral angle θ
Dihedral angle θ (degrees) Energy (kcal/mol) 0 60 120 180 240 300 360 0 2 4 Me/Me gauche Me/H anti (min) Me/H gauche Me/Me

The core ideas

The total conformational energy along the C2–C3 rotation is well modeled as a sum of a torsional (hyperconjugative) term with the same periodicity as ethane's, plus a steric correction that is only significant near the eclipsed and gauche geometries where the methyls approach one another:

E(θ)=Etors(θ)+Esteric(θ)E(\theta) = E_{\text{tors}}(\theta) + E_{\text{steric}}(\theta)

where:

  • Etors(θ)E_{\text{tors}}(\theta) is a threefold-periodic torsional term, Etors(θ)=V32[1+cos⁡(3θ)]E_{\text{tors}}(\theta) = \frac{V_3}{2}\left[1 + \cos(3\theta)\right], inherited in physical origin from ethane's σ→σ* hyperconjugation and Pauli/exchange repulsion between eclipsed filled orbitals,
  • Esteric(θ)E_{\text{steric}}(\theta) is the extra van der Waals penalty that appears whenever the two terminal methyl groups are close, largest at θ = 0° (eclipsed, closest approach) and present but smaller at θ = ±60° (gauche),
  • V3V_3 is the intrinsic threefold torsional barrier height per bond, close to the 2.9 kcal/mol value found in ethane.

The anti/gauche energy difference itself is captured by a much simpler relationship, since torsional strain is essentially the same at all staggered angles (θ = 60°, 180°, 300°) by the periodicity of EtorsE_{\text{tors}}:

ΔEgauche–anti≈Esteric(60∘)−Esteric(180∘)≈Esteric(60∘)\Delta E_{\text{gauche–anti}} \approx E_{\text{steric}}(60^\circ) - E_{\text{steric}}(180^\circ) \approx E_{\text{steric}}(60^\circ)

where:

  • the anti conformer (θ = 180°) has essentially zero extra steric strain, because the two methyls point in opposite directions and are far apart,
  • the gauche conformer (θ = 60°) has the two methyls held 60° apart, close enough for a measurable but modest van der Waals repulsion, empirically about 0.9 kcal/mol (some texts report 0.8–1.1 kcal/mol depending on method).

Finally, the equilibrium populations of anti and gauche butane at any temperature follow directly from the Boltzmann/equilibrium relation, remembering that gauche is a doubly-degenerate conformer (θ = +60° and θ = −60° are mirror images, equal in energy but conformationally distinct rotamers):

[gauche][anti]=2 e−ΔGgauche–anti∘/RT\frac{[\text{gauche}]}{[\text{anti}]} = 2\, e^{-\Delta G^\circ_{\text{gauche–anti}}/RT}

where:

  • the factor of 2 accounts for the two degenerate gauche wells (+60° and −60°) versus the single anti well (180°),
  • ΔGgauche–anti∘\Delta G^\circ_{\text{gauche–anti}} is the free energy difference between one gauche conformer and the anti conformer (≈ 0.9 kcal/mol, dominated by the enthalpic steric term since entropy differences between rotamers are small),
  • R=1.987×10−3R = 1.987 \times 10^{-3} kcal mol⁻¹ K⁻¹ and TT is the absolute temperature.
Derivation ABuilding the torsional profile: why anti is the minimum and Me/Me-eclipsed is the maximum

Goal. Starting only from Newman projections and orbital/steric reasoning, rank all six stationary conformers of butane (θ = 0°, 60°, 120°, 180°, 240°, 300°) by energy, and justify the ranking mechanistically rather than by lookup.

Step 1 — Identify the six stationary points by symmetry of substitution. Looking down C2→C3, the front carbon (C2) bears one CH₃ (up to C1) and two H's; the back carbon (C3) bears one CH₃ (down to C4) and two H's. Every 60° of rotation brings some front substituent directly in front of some back substituent (eclipsed) or directly between two back substituents (staggered). Because the front and back substituent sets are each {CH₃, H, H} rather than {H, H, H}, rotating by 60° does not return an identical picture — it takes six full 60° steps to return to the start, and inspection shows the six stationary conformers fall into two staggered types and two eclipsed types:

  • θ = 180°: the two methyls are anti (dihedral C1–C2–C3–C4 = 180°) — staggered type A.
  • θ = 60° and θ = 300°: the two methyls are gauche (60° apart, mirror images of each other) — staggered type B, doubly degenerate.
  • θ = 0°: the two methyls eclipse each other directly — eclipsed type A, the most crowded point on the whole curve.
  • θ = 120° and θ = 240°: each methyl eclipses a hydrogen on the other carbon — eclipsed type B, doubly degenerate.

Step 2 — Assign the torsional (orbital) contribution, identical in kind to ethane at every staggered vs. eclipsed point. At any staggered angle, each C–H (or C–C) bond on C2 is anti-periplanar to a C–H (or C–C) bond on C3, allowing σ(C–H)→σ*(C–H) donation that lowers energy relative to the eclipsed geometry, exactly as derived for ethane. At any eclipsed angle, bonds on C2 and C3 point directly at one another; the filled σ-orbitals experience four-electron (Pauli) destabilization, and the donor/acceptor alignment needed for stabilizing hyperconjugation is lost because the relevant dihedral is 0° rather than 180°. This torsional contribution alone would make θ = 180°, 60°, 300° roughly equal minima and θ = 0°, 120°, 240° roughly equal maxima — the ethane-like skeleton of the curve.

Step 3 — Add the steric correction, which is what actually splits the degeneracies. Torsional strain treats all staggered points as equivalent and all eclipsed points as equivalent, because it only cares about orbital alignment, not about what is aligned. Steric strain breaks this equivalence because it cares about what atoms are approaching each other and how close:

  • At θ = 180° (anti), the two methyls point in exactly opposite directions — the through-space C1···C4 distance is maximized. Essentially zero extra steric strain beyond the torsional background.
  • At θ = 60° or 300° (gauche), the two methyls are pulled to within a C1···C4 distance small enough that their van der Waals radii spheres begin to overlap (the H···H, H···C, and closest C–H bonds of the two methyls crowd each other). This adds a steric penalty on top of the torsional background, without requiring any bond eclipsing at all — gauche butane is fully staggered, so its extra energy relative to anti is purely steric, not torsional.
  • At θ = 0° (Me/Me eclipsed), the two methyls are not just close but directly superimposed when viewed down the C2–C3 axis: this is both torsionally eclipsed and maximally sterically crowded — the two effects stack, making this conformer the highest point on the whole curve.
  • At θ = 120° or 240° (Me/H eclipsed), one methyl eclipses a hydrogen while the other methyl eclipses nothing crowded (it sits near a hydrogen on the far side). This is torsionally eclipsed but only mildly sterically strained (one big group meets one small group), so it is a local maximum but distinctly lower than the Me/Me eclipsed maximum.

Step 4 — Assemble the full ranking. Combining the constant torsional background with the angle-dependent steric correction gives, from lowest to highest energy:

anti (180°)  <  gauche (60°, 300°)  <  Me/H eclipsed (120°, 240°)  <  Me/Me eclipsed (0°)\text{anti (180°)} \;<\; \text{gauche (60°, 300°)} \;<\; \text{Me/H eclipsed (120°, 240°)} \;<\; \text{Me/Me eclipsed (0°)}

This ordering — one true global minimum, one pair of degenerate local minima, one pair of degenerate local maxima, and one true global maximum — is exactly what is plotted in the energy-vs-θ figure above, and it is the qualitative skeleton that every subsequent conformational analysis (pentane, hexane, cyclohexane) builds upon.

Go deeper · Derivation B · 2 minQuantifying the barriers: assembling ΔH‡ values from torsional and steric increments
Derivation BQuantifying the barriers: assembling ΔH‡ values from torsional and steric increments

Goal. Use approximate, additive increments — a torsional background per eclipsing interaction plus a steric penalty per close methyl–methyl or methyl–hydrogen contact — to reconstruct the experimentally observed barrier heights of butane, and check internal consistency.

Step 1 — Recall the ethane increments. In ethane, each H–H eclipsing interaction costs about 1.0 kcal/mol of torsional strain (three such interactions give the observed 2.9–3.0 kcal/mol barrier). This per-eclipsing-pair increment is taken as the baseline torsional cost, independent of what atoms are eclipsing, when no extra sterics are present.

Step 2 — Build the Me/Me-eclipsed conformer (θ = 0°) from increments. At θ = 0°, three eclipsing interactions occur across the C2–C3 bond: CH₃(C1)/CH₃(C4), H/H, and H/H. Using the ethane-like torsional increment (~1.0 kcal/mol each) for the two H/H eclipses gives about 2.0 kcal/mol from those alone. The CH₃/CH₃ eclipsing interaction is not just torsional — it is torsional plus a substantial steric clash, since two methyl groups (~2.0 Å van der Waals radius for the methyl as a group) are forced to near-zero separation in projection. Empirically this single interaction contributes roughly 2.5–3.0 kcal/mol (torsional 1.0 plus steric ≈ 1.5–2.0). Summing:

ΔHMe/Me‡≈1.0+1.0⏟2 \timesH/H eclipse+(1.0+1.5–2.0)⏟Me/Me eclipse≈4.5–5.0 kcal/mol\Delta H^\ddagger_{\text{Me/Me}} \approx \underbrace{1.0 + 1.0}_{\text{2 \times H/H eclipse}} + \underbrace{(1.0 + 1.5\text{–}2.0)}_{\text{Me/Me eclipse}} \approx 4.5\text{–}5.0 \text{ kcal/mol}

matching the experimentally estimated barrier of about 4.5–5.0 kcal/mol for rotation through the fully eclipsed methyl-over-methyl geometry.

Step 3 — Build the Me/H-eclipsed conformer (θ = 120°) from increments. At θ = 120°, the three eclipsing interactions are CH₃/H, H/CH₃, and H/H (the two methyls are not eclipsing each other here — each methyl eclipses a hydrogen on the opposite carbon, and the two hydrogens eclipse each other). Using 1.0 kcal/mol as the baseline torsional cost for each of the three eclipsing pairs, plus a smaller steric increment (~0.5–0.6 kcal/mol total) for the two methyl–hydrogen close contacts (much smaller than methyl–methyl, since one partner is a bare hydrogen):

ΔHMe/H‡≈1.0+1.0+1.0⏟3 eclipsing pairs+0.5–0.6⏟extra Me ⋅ H steric≈3.6 kcal/mol\Delta H^\ddagger_{\text{Me/H}} \approx \underbrace{1.0+1.0+1.0}_{\text{3 eclipsing pairs}} + \underbrace{0.5\text{–}0.6}_{\text{extra Me}\,\cdot\,\text{H steric}} \approx 3.6 \text{ kcal/mol}

matching the experimentally estimated barrier of about 3.4–3.6 kcal/mol for rotation through either methyl/hydrogen-eclipsed geometry.

Step 4 — Cross-check with the gauche well depth. The gauche conformer is fully staggered, so unlike the two eclipsed maxima it carries no torsional-eclipsing penalty at all — its entire excess energy over anti is the steric term from the 60°-separated methyls, and this is exactly the ≈0.9 kcal/mol figure used throughout. As a limiting-case check: if the two terminal groups were both hydrogens instead of methyls (i.e., if butane were actually ethane), the analogous "gauche" steric term would vanish entirely, because H···H at a 60° dihedral separation is far outside van der Waals contact — consistent with ethane showing no splitting of its staggered conformers at all, exactly as observed.

Worked examples

Example 1 — Foundational: locating the anti and gauche wells on a dihedral-angle axis and confirming the population ratio at 298 K. Sketch the Newman projection of butane looking from C2 toward C3, with the front carbon's methyl group (to C1) pointing straight up (θ_front = 90° position on the clock face, by convention set to 12 o'clock). Rotating the back carbon (C3, bearing CH₃ to C4) around the axis, place its methyl group at the 12 o'clock position as well: this is the θ = 0° geometry, methyl directly eclipsing methyl. Now rotate the back carbon by 180° so its methyl points straight down (6 o'clock): this is θ = 180°, the anti conformer, and by construction the two methyls are as far apart as geometry allows for this bond — it is the reference zero of energy. Rotating the back carbon by only 60° from anti (so its methyl sits at either the 4 o'clock or 8 o'clock position, i.e., θ = 60° or θ = 300°) gives the two degenerate gauche conformers; note both are fully staggered (every front bond bisects a back bond angle) — no eclipsing torsional penalty is present, confirming that the entire ≈0.9 kcal/mol gauche penalty is steric. Now compute the anti:gauche ratio at T = 298 K using ΔG∘=0.9\Delta G^\circ = 0.9 kcal/mol and remembering the degeneracy factor of 2 for the two gauche wells:

[gauche][anti]=2 exp⁡ ⁣(−0.9(1.987×10−3)(298))=2 exp⁡(−1.521)=2(0.2185)=0.437\frac{[\text{gauche}]}{[\text{anti}]} = 2\,\exp\!\left(-\frac{0.9}{(1.987\times10^{-3})(298)}\right) = 2\,\exp(-1.521) = 2(0.2185) = 0.437

Converting to mole fractions, with xanti+xgauche=1x_{\text{anti}} + x_{\text{gauche}} = 1 and xgauche/xanti=0.437x_{\text{gauche}}/x_{\text{anti}} = 0.437:

xanti=11+0.437=0.696,xgauche=0.4371.437=0.304x_{\text{anti}} = \frac{1}{1+0.437} = 0.696, \qquad x_{\text{gauche}} = \frac{0.437}{1.437} = 0.304

So roughly 70% anti, 30% gauche (split between the two mirror-image gauche wells, ≈15% each) at room temperature — matching the commonly quoted 70:30 to 72:28 experimental split for butane derived from Raman and electron-diffraction studies. As a limiting-case check: if ΔG∘\Delta G^\circ were driven to zero (imagine a hypothetical butane analog where the gauche steric penalty vanished), the ratio would become [gauche]/[anti]=2[\text{gauche}]/[\text{anti}] = 2, i.e., 67% gauche total (33% anti) — the population would be dictated purely by the 2:1 degeneracy of the wells, exactly the entropy-only limit, and anti would lose its majority status. This confirms that anti's dominance is an enthalpic effect fighting against, and winning over, an entropic (multiplicity) bias toward gauche.

Example 2 — Applied: estimating the conformational contribution to the melting/boiling behavior of a longer alkane chain. Consider hexadecane, CH₃(CH�2)₁₄CH₃, used as a simple model for a saturated fatty-acid tail. Each internal C–C bond (there are 13 internal, non-terminal C–C bonds capable of gauche/anti isomerism) behaves, to a good first approximation, like the C2–C3 bond of butane, since the local environment of any interior CH₂–CH₂ bond resembles butane's substitution pattern (each carbon bears one "continuation of the chain" group playing the role of a methyl, plus two hydrogens). Using the same ΔG∘≈0.9\Delta G^\circ \approx 0.9 kcal/mol per gauche defect and the same population analysis as above, at 298 K each internal bond independently carries about 30% probability of being gauche rather than anti (roughly split 15%/15% between the two gauche senses). The number of gauche "kinks" expected along the whole chain, on average, is then:

⟨ngauche⟩≈13×0.304≈3.95\langle n_{\text{gauche}}\rangle \approx 13 \times 0.304 \approx 3.95

So a molten or dissolved hexadecane chain carries, on average, roughly four gauche kinks distributed along its 13 rotatable internal bonds, each kink shortening the effective end-to-end extension of the chain and disrupting the all-anti, fully extended zig-zag that would otherwise pack most efficiently into a crystal lattice. This is mechanistically why the all-anti extended conformation is the one realized in the solid state (where crystal packing forces favor the straightest, most close-packed chain) while the liquid and gas phases carry a substantial population of gauche defects — the same anti/gauche energetics computed for isolated butane, simply summed over every rotatable bond of a longer chain. It is also the conformational seed of why lipid bilayer fluidity depends so sensitively on temperature: heating the bilayer above its transition temperature converts anti-rich, ordered tails into gauche-rich, disordered (fluid) tails, following exactly the Boltzmann weighting worked out for butane itself.

Example 3 — Exam/competition level: distinguishing gauche destabilization from eclipsing destabilization using a substituted system. A common trap question: 2,3-dimethylbutane, (CH₃)₂CH–CH(CH�3)₂, is examined for rotation about its central C2–C3 bond. Each of C2 and C3 now bears two methyl groups and one hydrogen (rather than one methyl and two hydrogens, as in butane). Predict how the anti/gauche energy gap compares to that of butane itself, and identify the new lowest-energy staggered conformer.

Reasoning. In plain butane, the anti conformer places the single large group (CH₃) on each carbon 180° apart, leaving both gauche relationships in the staggered form as Me/H (small penalty, but the defining "gauche interaction" is Me···Me at 60°, since there is only one methyl per carbon to worry about). In 2,3-dimethylbutane, each carbon carries two methyls, so no single staggered conformation can avoid having at least one methyl on C2 gauche to at least one methyl on C3 — the number of independent methyl···methyl gauche contacts is now unavoidable and must be counted per conformer. Setting θ = 0° as one methyl-pair eclipsed and working through the geometry: at the staggered conformation where the hydrogens on C2 and C3 are anti to each other (i.e., H–C2–C3–H = 180°), each carbon's two methyls splay out symmetrically, and each methyl on C2 is gauche to one methyl on C3 (not both, since the far methyl on C3 is gauche to the other substituent position) — actually working the Newman diagram shows this conformation carries two Me/Me gauche interactions (one on each side), each contributing roughly the same ≈0.9 kcal/mol steric penalty found in butane's single gauche interaction, because the local steric environment of any one methyl···methyl gauche pair is essentially unchanged by what else is attached elsewhere on the molecule (a good use of the transferability of steric increments). This conformation is in fact the global minimum for 2,3-dimethylbutane and is analogous to butane's anti, but it carries roughly:

ΔEthis conformer vs. all-anti-if-possible≈2×0.9≈1.8 kcal/mol\Delta E_{\text{this conformer vs. all-anti-if-possible}} \approx 2 \times 0.9 \approx 1.8 \text{ kcal/mol}

of unavoidable gauche penalty relative to a hypothetical (unattainable) conformer with zero Me/Me gauche contacts — illustrating the exam-level insight that once a carbon bears two large groups instead of one, gauche interactions can become geometrically compulsory rather than optional, and the "best" available conformer is simply the one that minimizes the number and severity of unavoidable gauche contacts rather than eliminating them outright. This same reasoning — counting compulsory gauche interactions per staggered rotamer — is exactly the tool later used to rank axial/equatorial substitution patterns in cyclohexanes and to predict which staggered rotamer of a chiral synthetic intermediate will be preferentially populated in solution.

Limiting cases, scope & common traps

SituationWhat happensWhy
Both substituents on C2, C3 shrunk to H (→ ethane)Gauche/anti splitting vanishes; single staggered minimumNo steric term survives at 60° separation between two bare hydrogens
One substituent shrunk to H, other kept as CH₃ (→ propane, C2–C3 rotation)No anti/gauche distinction possible (only one large group per bond)Threefold symmetry restored on the CH₃-bearing carbon's partner side
Temperature → ∞Gauche population → 2/3, anti → 1/3 (pure degeneracy, no enthalpic preference)ΔG∘/RT→0\Delta G^\circ/RT \to 0, so Keq→2K_{eq} \to 2 from the degeneracy factor alone
Temperature → 0Population collapses entirely into antiBoltzmann factor for the higher-energy gauche wells vanishes
Bulkier substituents (e.g., tert-butyl in place of methyl)Gauche penalty grows sharply; anti preference becomes nearly absoluteSteric term scales strongly with group size (van der Waals radius, A-value)
Ring-constrained systems (e.g., cyclohexane C–C bonds)Gauche-like arrangements become compulsory for some ring bondsRing closure forces certain dihedrals near 60° regardless of substituent preference

The chemist behind it

The quantitative dissection of butane's rotational barrier into torsional and steric contributions grew out of physical-organic chemistry's mid-twentieth-century push to make Torsional Strain and the Origin of the Ethane Barrier and its extensions to substituted ethanes fully quantitative, using microwave spectroscopy, electron diffraction, and Raman spectroscopy to pin down rotamer populations directly from experiment. The person most associated with turning "steric strain" from a qualitative hand-wave into numbers that could be added up bond by bond, in the spirit used throughout this article, is Derek H. R. Barton, whose 1950 Nobel-cited insight that conformation controls reactivity launched the entire modern discipline of conformational analysis — though the specific butane rotational profile itself was refined over decades by spectroscopists including S. Mizushima and later by force-field pioneers (Allinger and coworkers) who built the steric increments used above into predictive molecular mechanics.

Origins · 1 minDerek Harold Richard Barton and how this was discovered
DH
Derek Harold Richard Barton
1918–1998 · British organic chemist, pioneer of conformational analysis

Barton showed that the three-dimensional shape adopted by a molecule — not just its connectivity — dictates chemical reactivity, using steroid and terpenoid chemistry as his proving ground. His 1950 paper "The Conformation of the Steroid Nucleus" argued that axial and equatorial substituents on cyclohexane rings react at different rates because of exactly the kind of steric and torsional bookkeeping worked out here for butane, scaled up to a fused ring system. He shared the 1969 Nobel Prize in Chemistry with Odd Hassel for developing the concept of conformation and its applications in chemistry.

History
- 1936 — Kemp and Pitzer's calorimetric work on ethane reveals a rotational barrier, planting the seed for all subsequent conformational analysis.
- 1943–1949 — Sidney Mizushima and coworkers use electron diffraction and Raman spectroscopy on substituted ethanes and butane-like systems to establish that anti and gauche rotamers coexist at measurable, temperature-dependent ratios.
- 1950 — Derek Barton publishes his landmark analysis connecting steroid ring conformation to reactivity, formalizing axial/equatorial and by extension gauche/anti reasoning.
- 1953 — Odd Hassel's X-ray and electron-diffraction studies of cyclohexane confirm the chair geometry and quantify 1,3-diaxial interactions, the direct multi-bond descendant of the single butane gauche interaction.
- 1969 — Barton and Hassel share the Nobel Prize in Chemistry "for their contributions to the development of the concept of conformation and its application in chemistry."
Why does butane have two different eclipsed conformers instead of one, unlike ethane?

In ethane, both carbons carry three equivalent hydrogens, so every 60° rotation encounters a chemically identical environment: any eclipsed geometry eclipses H against H, no matter where you start. Butane's central C2–C3 bond connects two carbons that each carry one CH₃ and two H substituents — a lower-symmetry substitution pattern. Rotating by 60° increments therefore visits genuinely different eclipsing partners: sometimes methyl eclipses methyl (θ=0°), sometimes methyl eclipses hydrogen while the other methyl also eclipses a hydrogen (θ=120°, 240°). Because steric strain depends on what is eclipsed, not just that something is eclipsed, these two classes of stationary point end up at different energies, splitting what would otherwise be one triply-degenerate eclipsed maximum (as in ethane) into two distinct maxima.

Is the anti conformer of butane perfectly planar, and does that matter?

Yes — in the anti conformer, all four carbons (C1–C2–C3–C4) lie in a single plane, with the dihedral angle exactly 180°. This planarity is a convenient visual feature but is not itself the source of anti's stability; the stability comes from the C1···C4 separation being maximized at 180°, which minimizes steric repulsion, combined with full staggering, which maximizes stabilizing hyperconjugative donation. If you instead consider the gauche conformer, the four backbone carbons trace a non-planar, roughly "sickle" or gauche zig-zag shape, which is why extended polymer chains overwhelmingly favor stringing together anti (planar zig-zag) linkages when packing into a crystal.

How was the 0.9 kcal/mol gauche/anti energy difference actually measured?

Several independent spectroscopic methods converge on this value. Electron diffraction in the gas phase measures the average C1···C4 distance and its temperature dependence, which reports directly on the anti:gauche population ratio through the different C1···C4 distances each conformer implies. Raman and infrared spectroscopy identify conformer-specific vibrational bands (certain skeletal modes shift measurably between anti and gauche forms) and track their relative intensities as a function of temperature, from which ΔH∘\Delta H^\circ and ΔS∘\Delta S^\circ are extracted via a van't Hoff analysis of the temperature-dependent equilibrium constant. NMR studies of appropriately substituted or isotopically labeled analogs provide corroborating values. All these methods agree on a gauche destabilization in the range of about 0.8 to 1.1 kcal/mol, most commonly quoted as approximately 0.9 kcal/mol (roughly 3.8 kJ/mol).

Does the gauche interaction ever become favorable rather than destabilizing?

Yes, in special cases. When gauche substituents can engage in a favorable through-space or through-bond interaction — for example, an electronegative atom gauche to a polar bond enabling a stabilizing hyperconjugative n→σ interaction (the "gauche effect" seen in molecules like 1,2-difluoroethane) — the gauche conformer can actually be preferred over anti despite the steric cost. This is a distinct, electronically driven phenomenon layered on top of the purely steric gauche interaction discussed for butane, and it shows that "gauche" describes a geometric* relationship (60° dihedral), while whether that geometry is stabilizing or destabilizing depends entirely on what groups occupy the positions.

Why do we ignore contributions from C1–C2 and C3–C4 bond rotations when analyzing butane conformers?

Rotation about the terminal C1–C2 bond (or equivalently C3–C4) only interchanges the positions of three chemically equivalent hydrogens on the terminal methyl group, exactly like ethane's rotation — it produces no new distinguishable conformer of the whole molecule and contributes a small, conformationally uniform torsional barrier (essentially the methyl-rotation barrier, close to ethane's ~3 kcal/mol) that is the same in every rotamer about C2–C3. Because this contribution does not differentiate anti from gauche from eclipsed, it is conventionally factored out of the conformational analysis, which focuses entirely on the one bond (C2–C3) whose rotation genuinely changes the molecule's shape and energy in a conformer-distinguishing way.

How does the butane analysis change for larger n-alkanes like pentane or hexane?

Each internal C–C bond of a longer chain has a local environment very similar to butane's C2–C3 bond — one carbon flanked by "rest of chain" (playing the role of CH₃) and two hydrogens, next to another carbon with the same pattern — so the same anti/gauche/eclipsed energetics apply bond by bond, to a good first approximation (the "local" approximation used in worked example 2 above). New wrinkles appear only when two non-adjacent gauche bonds interact: for example, in pentane, a gauche-gauche combination at both internal bonds can bring the terminal methyls of C1 and C5 into a severe steric clash (the "gauche-gauche" or "syn-pentane" interaction), an additional destabilization of roughly 3.0–3.4 kcal/mol that has no counterpart in butane itself, since butane has only one internal rotatable bond and cannot generate this longer-range clash.

Why does the anti conformer dominate at room temperature despite gauche having a 2-fold degeneracy advantage?

The degeneracy factor of 2 favors gauche entropically (there are two equally low gauche wells for every one anti well), which would give a 2:1 gauche:anti ratio if the two rotamer types had equal energy. But the enthalpic penalty of about 0.9 kcal/mol for each gauche well works against this multiplicity, and at 298 K the Boltzmann factor e−0.9/(0.593)≈0.22e^{-0.9/(0.593)} \approx 0.22 is small enough to overcome the factor-of-2 degeneracy advantage, giving a net ratio of about 0.44:1 (gauche:anti) rather than 2:1. In short, anti wins because its enthalpic advantage outweighs gauche's entropic (multiplicity) advantage at ordinary temperatures; only at very high temperatures does the entropic term dominate and push the population toward the degeneracy-only limit of 2:1 gauche:anti.

Before this

Where this leads