Double- versus Single-Barbed (Fishhook) Arrows
Every arrow you draw on a mechanism is a claim. It shows where electrons go, and how many travel together. Draw the wrong kind of arrowhead, and you have not made a small stylistic slip. Instead, you have asserted the existence of a different chemical species entirely. That species has an odd electron instead of a lone pair, a radical instead of an anion. The double-barbed arrow and the single-barbed "fishhook" arrow look almost identical on the page. They differ only in whether the arrowhead has one flight-feather or two. Yet they encode two fundamentally distinct ways a covalent bond can break or form. This distinction matters because it is the fork in the road. It separates two entire subfields of reactivity. Heterolysis — both bonding electrons departing together — is the language of ionic mechanisms. This includes nucleophilic substitution, acid–base chemistry, carbonyl addition, everything built from The Curved-Arrow Formalism. Homolysis — the electrons splitting one apiece — is the language of radical chemistry. This covers combustion, polymerization, autoxidation, and much of atmospheric and biological damage chemistry. A student who fishhooks an SN2 mechanism, or double-arrows a radical chain propagation step, has done more than break a drawing convention. The resulting intermediate literally does not exist under those conditions. Any subsequent step drawn from it is fiction. The big picture is this: an arrow is bookkeeping for electron pairs and electron spins. The two arrow types are not interchangeable notation for the same idea. They describe different bond-breaking physics, governed by different orbital symmetry. They involve different intermediates (carbocations/carbanions versus radicals). They involve different thermodynamics (heterolytic versus homolytic bond dissociation energies). They also require different solvent/environment conditions. Polar, ionizing media favor heterolysis. Gas phase, nonpolar media, light, or initiators favor homolysis. This article gives you the precise formal definition of each arrow. It explains the orbital and electron-counting mechanism by which each is drawn correctly. It offers worked examples spanning acid–base chemistry to radical halogenation. It also provides a clear map of the traps. These include curly-arrow "double fishhooks," arrows drawn with the wrong number of electrons. They also include the illegal mixing of one-electron and two-electron steps in a single mechanism. It sets you up for the deeper question of why a bond chooses to break one way rather than the other. That question is the subject of Homolytic versus Heterolytic Bond Cleavage.
- A double-barbed arrow (⤻, two-line arrowhead) moves two electrons — a lone pair or a bonding pair — as one packet; it describes heterolysis/heterolytic bond formation, giving ions.
- A single-barbed "fishhook" arrow (⇀, one-line arrowhead) moves one electron; it describes homolysis/homolytic bond formation, giving radicals.
- Fishhooks are always drawn in pairs for a single bond-breaking event — one electron goes to each fragment — because total electron count and spin must be conserved.
- Full arrows are used for ionic/polar mechanisms (acid–base, SN1/SN2, addition–elimination at carbonyls); fishhooks are used for radical mechanisms (halogenation, autoxidation, polymerization, pericyclic-adjacent radical steps).
- The choice of arrow type is not a drawing preference — it is determined by the electronic nature of the intermediate the mechanism actually produces.
- Mixing the two arrow conventions within one bond-breaking step is a formal error: it would require a bond to have a non-integer number of electrons in one packet.
- Key idea: the number of barbs on the arrowhead literally counts the electrons in motion — two full lines move an electron pair, one half-line moves a single electron — and this choice fixes whether your mechanism lives in the world of ions or the world of radicals.
An arrow's barb count is an electron count: a full (double-barbed) arrow relocates two electrons together, generating or consuming a lone pair and producing charged, closed-shell (even-electron) species; a fishhook (single-barbed) arrow relocates one electron, and because electrons cannot vanish, fishhooks are always used in matched pairs to convert one bond into two half-filled orbitals — radicals.
Where this lives today
The distinction is load-bearing across nearly all of modern chemistry and biology. In polymer manufacturing, free-radical polymerization of ethylene, styrene, and acrylates (producing polyethylene, polystyrene, and acrylic plastics at industrial scale) is drawn entirely with fishhook arrows, from peroxide-initiator homolysis through propagation to radical termination — while ionic (living anionic or cationic) polymerizations used for precision block copolymers are drawn entirely with double-barbed arrows, and the choice of mechanism directly determines the polymer's molecular weight distribution and architecture. In atmospheric and combustion chemistry, ozone depletion by chlorofluorocarbons proceeds through a Cl• radical chain (fishhooks: Cl• + O₃ → ClO• + O₂, then ClO• + O → Cl• + O₂), a mechanism whose correct radical description was central to the Nobel-recognized work of Rowland, Molina, and Crutzen. In medicinal chemistry and toxicology, cytochrome P450 oxidations proceed through high-valent iron-oxo radical rebound mechanisms (fishhook C–H abstraction followed by radical recombination) that determine drug metabolite structures and sites of toxic bioactivation, in contrast to purely ionic phase-II conjugation chemistry (glucuronidation, sulfation) drawn with double-barbed arrows. In materials and battery chemistry, single-electron-transfer (SET) steps in redox flow batteries and in dissolving-metal reductions (Birch reduction, SmI₂-mediated radical cyclizations widely used in total synthesis) are fishhook chemistry, mechanistically distinct from the double-barbed hydride/proton-transfer steps that complete the same overall transformations. And in antioxidant biochemistry, vitamin E and other radical-trapping antioxidants function by donating a hydrogen atom (fishhook H-atom transfer, quenching a lipid peroxyl radical) rather than by the double-barbed proton-transfer chemistry of ordinary acid–base reactions — a mechanistic distinction with direct consequences for how antioxidant efficacy is measured and designed.
Ask the tutor: Why does the same C–Br bond in the same molecule sometimes break heterolytically and sometimes homolytically, and what specific factor decides it?
The physical picture
Return to the underlying object every arrow represents: a molecular orbital, occupied by either two electrons (a bonding pair or lone pair) or, transiently in a radical, by one electron (a singly occupied molecular orbital, SOMO). The curved arrow is not a cartoon of "motion" in real space; it is a bookkeeping device that says this orbital's electron population is being transferred into that orbital. The whole content of The Curved-Arrow Formalism is the rule that arrow tails start on electrons (a bond or lone pair) and heads point to where those electrons end up (a new bond, a new lone pair, or an atom that becomes electron-poor/rich). The double-barbed arrow moves a pair. Its tail sits on a filled orbital holding two electrons — a lone pair on a Lewis base, or a σ or π bonding pair. Its head lands on an atom (forming a new lone pair there), on another atom in a new bond, or between two atoms forming a new bond. Because two electrons move as a unit, the atom that loses them becomes formally more positive by one unit of charge (if it had electrons removed from a lone pair or one end of a bond it "owned") and the destination becomes more negative by one unit — this is exactly how formal charges update in an ionic mechanism. The species produced are still closed-shell: every electron remains paired, just redistributed. This is heterolytic cleavage or heterolytic bond formation, and it is the entire grammar of acid–base chemistry, SN1/SN2, E1/E2, carbonyl addition, and aromatic substitution. The single-barbed fishhook arrow moves one electron. Its tail sits on a singly occupied orbital (a radical) or on one lobe of a bond that is being split symmetrically; its head lands on a single new location, contributing one electron toward a new bond or a new SOMO. Crucially, because a covalent σ or π bond is a two-electron object, homolysis of a bond requires drawing two fishhooks, one for each electron, each hook sending its electron to a different fragment. The bookkeeping consequence: no formal charges are created (each fragment keeps exactly the number of electrons "its half" of the bond contributed), but each product becomes a radical — an atom or molecule with an odd, unpaired electron in a previously bonding or nonbonding orbital. The orbital-symmetry root of the difference is worth stating explicitly. Heterolysis is favored when the bond's electron pair can be stabilized asymmetrically — one fragment's LUMO/empty orbital accepts nothing, the other's HOMO keeps both electrons, typically because of polarity built into the bond (C–Br is already polarized Cδ+–Brδ−) or because an external nucleophile/base assists by donating into the σ* orbital as the bond breaks (concerted heterolysis, as in SN2). Homolysis is favored when the bond is nonpolar or nearly so (C–C, O–O peroxide bonds, X–X halogens under photolysis) so that splitting the pair symmetrically, one electron to each fragment, costs less energy than forcing an asymmetric ionic split in a medium that cannot stabilize the resulting ions (gas phase, nonpolar solvent, or high temperature/photochemical activation).
The core ideas
Formal charge bookkeeping under a double-barbed arrow step obeys the same rule you already know from Lewis structures:
where: an atom "owns" all its nonbonding electrons plus one electron from each bond it participates in; a double-barbed arrow moving a lone pair or bond pair changes this ownership by exactly 2 electrons at the two ends of the arrow (tail atom loses 1 unit of ownership if the pair becomes a new bond, or 2 if it becomes fully external as in a leaving anion; head atom gains correspondingly), always yielding integer, even-electron formal charges. Radical (fishhook) bookkeeping instead conserves spin and electron count atom-by-atom, with no formal charge created:
where: each homolysis of one σ or π bond creates two new unpaired electrons (net +2 to the radical count), and each radical–radical combination step destroys two unpaired electrons (net −2); a well-formed radical chain mechanism must have this quantity conserved at every single step (each elementary step changes it by exactly 0, +2, or −2, never by an odd number, since electrons cannot appear or vanish singly). The diagnostic equation that tells you which arrow to reach for is the comparison of activation pathways available in the medium:
where: is lowered by polar/protic solvents that solvate the resulting ion pair (or by an internal/external nucleophile assisting departure) and by substituents that stabilize charge (resonance, hyperconjugation, adjacent lone pairs); is lowered by weak, nonpolar bonds (O–O, N–Br, halogen–halogen), by initiators (light, peroxides, heat) that supply the bond dissociation energy directly, and is essentially insensitive to solvent polarity since no charge is created. Whichever pathway has the lower under the actual reaction conditions is the one nature (and your mechanism) takes — and that in turn dictates which arrow type is correct, not merely stylistic.
Goal. Show, arrow by arrow, why acid–base proton transfer is drawn with full (double-barbed) arrows, and why any other arrow choice would misrepresent the electron count.
Step 1 — Identify the electron source. Ammonia's nitrogen carries a lone pair, occupying nitrogen's sp³ HOMO. This lone pair is the only nucleophilic (electron-rich, high-energy, non-bonding) site in the molecule, so the arrow tail must start here — not on an N–H bond, which is lower in energy and not oriented toward the electrophile.
Step 2 — Identify the electrophilic sink. The H–Cl σ* orbital is the lowest unoccupied molecular orbital available; H is electrophilic because Cl is far more electronegative and pulls the bonding pair toward itself, leaving H partially positive (Hδ+–Clδ−). The arrowhead of the first arrow must land exactly on this H, since that is where the incoming lone pair will build a new bond.
Step 3 — Draw arrow 1 (double-barbed): N lone pair → new N–H bond. Two electrons move as a single packet from nitrogen to the region between N and H. Nitrogen's formal charge rises by +1 (it retains ownership of only one electron of the new bond, having contributed both), reaching +1 overall on the resulting ammonium nitrogen.
Step 4 — Draw arrow 2 (double-barbed): H–Cl bond → Cl lone pair. As the new N–H bond forms, the old H–Cl bonding pair cannot simply vanish (electrons are conserved); it must relocate entirely onto chlorine, becoming a new chloride lone pair. This is a second double-barbed arrow, tail on the H–Cl bond, head on Cl. Chlorine's formal charge falls by 1 (from 0 to −1), since it now owns both electrons of what was a shared bond.
Step 5 — Verify electron and charge conservation. Total electrons: NH₃ (8 valence electrons around N–H₃ framework plus lone pair) plus HCl (8 valence electrons) is unchanged in NH₄⁺ + Cl⁻ — nothing was created or destroyed, only two electron pairs relocated. Total charge: 0 (NH₃) + 0 (HCl) = +1 (NH₄⁺) + (−1) (Cl⁻) = 0. Both arrows were double-barbed because at no point did any orbital end up with a single, unpaired electron — every species before and after is closed-shell. Attempting to draw this with fishhooks would require splitting the N lone pair or the H–Cl bond into single electrons, generating a nitrogen radical cation and a hydrogen/chlorine radical pair that simply are not the observed products; the fishhook mechanism is not merely "non-preferred," it describes a different, wrong reaction.
Go deeper · Derivation B · 2 minMechanism 2 — Constructing a correct homolytic (fishhook) arrow step: Cl₂ photolysis initiating radical chlorination
Goal. Show why bond homolysis under photochemical initiation requires paired single-barbed fishhooks, and how the propagation steps that follow must also use fishhooks consistently to conserve one unpaired electron per species.
Step 1 — Identify the bond that will split symmetrically. The Cl–Cl bond is nonpolar (both atoms identical, zero electronegativity difference), so there is no thermodynamic driving force to send both electrons to one chlorine and leave the other electron-deficient; heterolysis here would generate Cl⁺ and Cl⁻, a highly unfavorable, high-energy charge separation with no stabilizing solvent (this reaction is typically run in nonpolar solvent or gas/liquid phase with no ion-stabilizing medium). Symmetric splitting is strongly preferred.
Step 2 — Supply the activation energy via a photon. Absorption of UV/visible light (for Cl₂, ~330 nm region for weak absorption; more efficiently with added initiators) promotes an electron from the Cl–Cl σ bonding MO into the σ* antibonding MO. This directly weakens/breaks the bond without involving any nucleophile or Lewis base — there is no orbital available to accept two electrons as a pair, consistent with a nonpolar-bond, non-ionic pathway.
Step 3 — Draw fishhook 1: one electron of the Cl–Cl bonding pair moves to become a lone electron on the left chlorine. Tail starts at the midpoint/on the bond, single-barbed head lands on the left Cl, denoting that this Cl now holds a SOMO — a chlorine radical, •Cl, with charge 0 (it keeps its original 6 nonbonding electrons plus this 1, for 7 total valence electrons, matching neutral Cl).
Step 4 — Draw fishhook 2: the other electron of the same bonding pair moves to become a lone electron on the right chlorine. This is mandatory, not optional: if only one fishhook were drawn, one electron would simply disappear from the universe, violating conservation. The second fishhook, tail on the same bond, head on the right Cl, produces the second •Cl radical. Two fishhooks, each carrying one electron, are the only legal way to draw homolysis of a two-electron bond.
Step 5 — Verify: no formal charge appears anywhere. Each chlorine atom retains exactly the number of electrons "owed" to it by the original neutral, covalent bond (one each); charge conservation is trivially satisfied (0 → 0 + 0) and spin is now unpaired on both atoms (each has one unpaired electron, total system spin still zero for the pair as generated together, but each individual radical is paramagnetic).
Step 6 — Continue with fishhooks through propagation (chain step 1). A •Cl radical attacks methane: one fishhook from the C–H bonding pair moves to combine with the Cl radical's SOMO, forming a new H–Cl bond (this fishhook's head meets the incoming Cl radical's own single fishhook tail — i.e., two single-barbed arrows converge to remake one full 2-electron bond, H–Cl); the second fishhook from that same broken C–H bond moves onto carbon, generating a new radical, •CH₃. Every species in this chain — •Cl, •CH�3, later •CH3 + Cl2 → CH3Cl + •Cl — is a radical or combines exactly two radical-forming fishhooks per bond change, never a lone single fishhook acting alone, and never a double-barbed arrow mixed into a bond-breaking step that only has one electron available on that atom.
Worked examples
Example 1 (foundational): Drawing the correct arrow for deprotonation of acetic acid by hydroxide. Acetic acid, CH₃COOH, is deprotonated by hydroxide. First identify the source: the O–H bond's bonding pair is the electrons that will move (not a lone pair on oxygen, since it is the bond itself that breaks). Hydroxide's oxygen lone pair is the nucleophile attacking the acidic proton. Draw arrow 1, double-barbed, tail on the OH⁻ lone pair, head landing on the acidic H of the carboxylic acid — this forms the new O–H bond of water. Draw arrow 2, double-barbed, tail on the old C(=O)–O–H bond (the one being broken), head moving onto the carboxyl oxygen, generating a new lone pair there. Check charge: OH⁻ (charge −1) becomes neutral H₂O (its oxygen ownership drops correctly), and the carboxylic acid (neutral) becomes carboxylate (charge −1, oxygen now owns an extra lone pair). Total charge conserved: −1 + 0 = 0 + (−1). Both arrows are double-barbed because every species — acetic acid, hydroxide, water, acetate — is closed-shell; the acetate anion product is stabilized by resonance delocalization of that new lone pair into the neighboring C=O π system, which is only meaningful because it is a discrete electron pair being delocalized, a claim you can only make with double-barbed formalism. As a limiting-case check: if instead of OH⁻ we used a radical base, this mechanism would be entirely different (H-atom abstraction, fishhooks) — the arrow type is dictated by the actual electronic character of the reagent, hydroxide's electron pair versus a hypothetical radical's single electron.
Example 2 (applied): NBS allylic bromination — distinguishing the ionic bromination pathway from the correct radical pathway. N-Bromosuccinimide (NBS) with cyclohexene under radical initiation (AIBN or light) is the textbook case where students are tempted to draw an ionic-style (double-barbed) bromination mechanism by analogy with Br₂ addition, and get it wrong. The correct picture: initiation generates a small, steady-state concentration of Br• via homolysis (two fishhooks splitting a weak N–Br or Br–Br bond, exactly as in the Cl₂ derivation above — one fishhook to each fragment). Propagation step 1: Br• abstracts an allylic hydrogen from cyclohexene. Draw this with fishhooks: one fishhook from the allylic C–H bonding pair goes to pair up with Br•'s own single fishhook (converging into the new H–Br bond, a legitimate 2-electron bond built from two 1-electron fishhook contributions), and the second fishhook from that same C–H bond moves onto the allylic carbon, generating an allylic radical. This allylic radical is resonance-delocalized — but drawn with fishhooks, not double-barbed arrows, because the delocalizing species is a SOMO (one electron), moving between the two termini of the allyl system: one fishhook, tail on the C=C π bond, head moving to the adjacent carbon, shifting the radical position while the unpaired electron count stays at exactly one throughout. Propagation step 2: this allylic radical abstracts a Br atom from Br₂ (regenerated in low concentration from NBS + HBr equilibrium), again via two fishhooks converging into a new C–Br bond and one fishhook forming a new Br• that continues the chain. At no point in this entire sequence does an ion appear; drawing double-barbed arrows here (as if Br+ were adding electrophilically across the alkene, Markovnikov-style) describes the wrong mechanism — that ionic pathway is what happens with Br₂ alone in the dark in a polar solvent, a mechanistically and regiochemically distinct reaction (vicinal dibromide via bromonium ion, not allylic monobromide via radical chain).
Example 3 (exam/competition level): Distinguishing a single mechanism that contains both a heterolytic and a homolytic step — retro-ene-adjacent radical clock ring-opening used to probe SN1 vs SN2 character. Consider a mechanistic puzzle used to probe whether a solvolysis proceeds through a discrete cation (heterolytic, double-barbed throughout) or has any radical character: a cyclopropylcarbinyl-type leaving group is solvolyzed, and the "radical clock" cyclopropylcarbinyl-to-homoallyl rearrangement rate is compared against a control. Two candidate mechanisms must be drawn with strictly self-consistent arrows. Candidate A (pure heterolytic/cationic pathway). The C–OTs (tosylate) bond ionizes: one double-barbed arrow, tail on the C–O bond, head moving fully onto the tosylate oxygen (departing as the resonance-stabilized tosylate anion, its negative charge delocalized over three oxygens via further double-barbed arrows into the sulfonyl group). This generates a cyclopropylcarbinyl cation. Ring-opening to the homoallyl cation is then drawn with a second double-barbed arrow: tail on a cyclopropane C–C bonding pair (one of the two bonds flanking the cationic carbon, whose orbital is aligned for hyperconjugative overlap with the empty p orbital), head moving to form a new π bond between the migrating carbon and the original cationic center, while the ring carbon that lost the bond becomes the new cationic center. This is legitimate because the empty orbital receiving the pair is a true LUMO (p orbital of a carbocation, zero electrons), consistent with a two-electron, heterolytic-style bond reorganization even though no external nucleophile is involved — it is a cationic rearrangement, still entirely double-barbed, because the driving orbital interaction is a filled σ(C–C) donating into an empty p orbital, a two-electron process. Candidate B (radical pathway, if homolysis competed). If instead the C–LG bond broke homolytically (relevant when radical initiators or radical-generating conditions are present, or when testing whether trace radical character exists), the ring-opening step must use fishhooks: one fishhook from the strained cyclopropane C–C bond moves to pair with the existing radical's SOMO (extending conjugation/forming a new π-bond electron pair correctly requires care — in the genuine radical mechanism, one fishhook moves from the breaking C–C σ bond to combine with the adjacent carbon radical's unpaired electron, forming a new π bond, while the second fishhook from that same σ bond becomes the new, ring-opened radical center on the far carbon). The diagnostic power of the "radical clock" is precisely that cyclopropylcarbinyl radicals ring-open extremely fast (~10⁸ s⁻¹), so if products show the ring-opened (homoallyl) skeleton even under conditions expected to be purely ionic, or if the ratio of ring-opened to unopened product tracks known radical rate constants rather than cationic ones, the mechanism has radical character and must be redrawn with fishhooks, not double-barbed arrows, for at least that step. This is the real experimental use of the arrow-type distinction: chemists infer which arrow is correct from kinetics and product ratios, then must draw the mechanism to match, never the reverse.
Limiting cases, scope & common traps
| Situation | Correct arrow | Why |
|---|---|---|
| Brønsted acid–base proton transfer | Double-barbed | Lone pair and bond pair move as intact 2e⁻ packets; products closed-shell |
| SN1/SN2, E1/E2 | Double-barbed | Ionic or concerted 2e⁻ bond-breaking/forming; carbocation or backside-attack TS, no unpaired spins |
| Carbonyl addition (Grignard, hydride) | Double-barbed | Nucleophile lone pair and π-bond pair both move as 2e⁻ units |
| Halogen photolysis / peroxide initiation | Fishhook (×2) | Nonpolar, weak σ bond; no stabilizing medium for ions; symmetric split cheaper |
| Radical chain propagation (H-abstraction, addition to alkene) | Fishhook | Each step consumes one radical, produces one radical; SOMO chemistry throughout |
| Radical recombination/termination | Fishhook (×2, converging) | Two SOMOs combine into one new bonding pair |
| Pericyclic (Diels–Alder, Cope) | Double-barbed, cyclic set | Concerted, even-electron, aromatic TS — no radicals generated at any point |
| Single-electron transfer (SET) redox steps | Fishhook | Exactly one electron hops between redox partners (e.g., Na → alkyl halide in dissolving-metal reduction) |
The chemist behind it
The curved-arrow formalism, from which both the double-barbed and single-barbed conventions descend, was systematized in the late 1920s and 1930s by the English chemist Sir Robert Robinson and, independently and influentially in pedagogical form, by Christopher Ingold, who provided much of the rigorous electronic-theory language (nucleophile, electrophile, heterolysis, homolysis — Ingold coined several of these very terms) that makes the two arrow types meaningful rather than merely decorative. Ingold's systematic classification of reaction mechanisms (SN1, SN2, E1, E2) explicitly rested on distinguishing concerted, two-electron, heterolytic bond reorganizations from the free-radical chemistry being simultaneously developed by others; the fishhook notation for one-electron processes matured alongside the growing understanding of radical chain reactions (combustion, polymerization) through the 1930s–1950s, with major mechanistic clarity contributed by workers such as Frank Whitmore (carbocation rearrangements, firmly in the double-barbed/heterolytic camp) and Morris Kharasch (who established the radical, anti-Markovnikov mechanism of HBr addition to alkenes under peroxide conditions — precisely the historical experiment that forced organic chemists to formally separate homolytic from heterolytic addition and therefore to need two distinct arrow symbols in the first place).
Origins · 1 minSir Christopher Kelk Ingold and how this was discovered
Ingold built the electronic-theoretic vocabulary of mechanistic organic chemistry — nucleophile, electrophile, heterolysis, homolysis, and the SN1/SN2/E1/E2 mechanistic classification — largely through kinetic studies (with Edward Hughes) that inferred mechanism from rate law and stereochemistry, exactly the discipline that later students must apply to decide honestly which arrow type a real reaction deserves.
Why can't I just use a double-barbed arrow for a radical mechanism if it's easier to draw?
Because the arrow's barb count is a literal, quantitative claim about how many electrons move, not a stylistic choice. A double-barbed arrow asserts that two electrons travel together, producing a new lone pair or bond and leaving the source atom with an integer formal charge — always describing closed-shell, even-electron species. If the actual mechanism produces a radical (an atom with a genuinely unpaired, singly-occupied orbital, as verified by ESR spectroscopy, radical-clock rearrangement rates, or the classic peroxide-effect regiochemical switch), then only a single electron has moved into that new orbital, and a double-barbed arrow overstates the electron count by one. The resulting "mechanism" would depict a species — a closed-shell anion, say — that does not correspond to the paramagnetic radical actually detected experimentally.
How do I know, before drawing anything, whether a bond will break heterolytically or homolytically?
Look at three things: bond polarity, the reaction medium, and how the bond is being activated. A polar bond (C–halogen, C–O in a good leaving group, O–H) sitting in a polar, ionizing solvent (water, alcohols, DMSO) with a genuine nucleophile or base present strongly favors heterolysis — the medium can stabilize the resulting charges. A nonpolar or weak, symmetric bond (O–O peroxide linkage, halogen–halogen, some N–Br bonds) activated by heat, light, or a radical initiator (AIBN, benzoyl peroxide) favors homolysis, especially in nonpolar solvents where ions would be prohibitively high in energy. When in doubt, check for diagnostic experimental clues: anti-Markovnikov regiochemistry, radical clock rearrangements, or ESR-active intermediates all signal homolysis; strict Markovnikov regiochemistry, solvent-polarity rate dependence, and carbocation rearrangements signal heterolysis.
Is it ever correct to mix double-barbed and single-barbed arrows within the same overall mechanism?
Yes — but never within the same bond-breaking or bond-forming event. A single multi-step mechanism can perfectly legitimately contain one step drawn with double-barbed arrows (say, a final proton transfer via acid–base chemistry) and an earlier step drawn with fishhooks (say, a homolytic initiation or a single-electron-transfer step), provided each individual step's arrows are internally consistent with the actual electron count and spin state of the species involved at that exact point. What is never legitimate is drawing one arrowhead of a single bond-breaking event as double-barbed and treating the resulting fragment as if it only received one electron, or vice versa — that conflates two incompatible electron-countings within one elementary step.
Why does breaking a C–C bond homolytically require exactly two fishhooks rather than one?
A single covalent σ bond is, by definition, a two-electron object — one bonding molecular orbital doubly occupied. If you draw only one fishhook, you are claiming that only one electron left that orbital, but a filled bonding MO holding two electrons cannot lose only one electron and remain a normal, complete bond broken into two well-defined fragments; you would be left with an orbital population that does not correspond to any real, stable species (an oddly half-broken bond). Conservation of electrons demands that both electrons be accounted for: one fishhook sends one electron to become the new SOMO on one fragment, and a second, separately drawn fishhook sends the other electron to become the SOMO on the other fragment. Together, exactly two electrons are relocated, one apiece, matching the two genuinely observed radical products.
Does the double-barbed versus fishhook distinction map onto "polar" versus "nonpolar" mechanisms in general?
Largely yes, with the understanding that "polar mechanism" is really shorthand for "heterolytic, ionic-intermediate mechanism," which is what double-barbed arrows depict, and "radical mechanism" is shorthand for "homolytic, radical-intermediate mechanism," depicted by fishhooks. The correlation with solvent polarity is a consequence, not the definition: polar solvents stabilize the charged intermediates that heterolytic (double-barbed) mechanisms generate, so heterolysis is common in polar media, while homolysis, generating uncharged radicals, proceeds efficiently even in nonpolar media or the gas phase. But the fundamental distinction the arrows encode is about electron pairing (two electrons together vs. one electron alone), not solvent polarity itself — that is simply the most common environmental correlate.
Why do resonance structures of a radical use fishhooks while resonance structures of a carbanion use double-barbed arrows?
Resonance arrows describe the same physical electron distribution reinterpreted through different, equally valid Lewis structures — the arrow type must match what is actually delocalizing. In an allylic carbanion, the delocalized negative charge is carried by a full electron pair moving between resonance forms, so double-barbed arrows are correct: tail on the π bond, head forming a new lone pair one carbon over, with a compensating double-barbed arrow showing the old lone pair becoming part of a new π bond. In an allylic radical, only a single unpaired electron is delocalizing across the π system, so exactly one fishhook is drawn per resonance step: tail on the π bond, head moving the SOMO one carbon over, with no lone pair or additional bond pair anywhere in the structure. Using a double-barbed arrow for the radical case would falsely claim two electrons are delocalizing, when spectroscopically (by ESR) there is only ever one unpaired electron in the system at a time.
If fishhook and double-barbed arrows both start on a "bond," how do I tell which one to draw just by looking at the starting material?
You cannot tell from the starting material's Lewis structure alone — polarity of the bond is a strong hint (polar bonds favor heterolysis, nonpolar bonds favor homolysis under forcing conditions) but the deciding factor is the reaction conditions and the nature of what's attacking or activating that bond. A C–Br bond can be broken heterolytically (double-barbed, ionizing solvent, SN1) or homolytically (two fishhooks, AIBN/light, radical chain) depending entirely on what else is present and how energy is being delivered. The correct procedure is: identify the reagents and conditions first (is there a radical initiator, light, or heat with a weak bond present, versus a polar solvent, nucleophile, or acid/base?), infer from that which pathway is operative, and only then choose the arrow type that matches the resulting intermediate's actual electronic structure.