Hell-Volhard-Zelinsky Reaction
A carboxylic acid's alpha carbon resists enolization under ordinary acidic conditions. Yet chemists routinely brominate it cleanly at that position. This is the paradox the Hell–Volhard–Zelinsky (HVZ) reaction resolves. Carboxylic acids themselves barely enolize. But a catalytic dose of phosphorus tribromide converts a small fraction of the acid into its acyl bromide. Acyl bromides enolize far more readily than the parent acid ever could. The result is a catalytic cycle that delivers alpha-bromo carboxylic acids in high yield. The catalytic acyl halide is regenerated at the end of every turnover. The reaction matters because alpha-halo acids are exceptionally versatile synthetic handles. The carbon–halogen bond installed alpha to the carbonyl is activated toward nucleophilic substitution. This activation comes from the adjacent electron-withdrawing group. So alpha-bromo acids convert smoothly into alpha-amino acids (via ammonia displacement). They also convert into alpha-hydroxy acids, alpha-cyano acids, and unsaturated acids (via elimination). The classic laboratory synthesis of amino acids — the Strecker-independent route — leans on this single transformation. So do countless industrial preparations of substituted acetic and propionic acid derivatives. The big picture is a lesson in relative enol content. A simple carboxylic acid's enol tautomer is destabilized by extensive delocalization. The carbonyl oxygen's lone pair delocalizes into the carboxylate-like resonance system. This makes the C–H alpha to a group far less acidic. It is also less enolizable than the C–H alpha to a ketone. Converting to removes the OH's electron-donating resonance contribution. This sharpens the carbonyl's electrophilicity. Critically, it also makes the corresponding enol (built from the acyl bromide) stable enough to react with molecular bromine at a useful rate. This is fundamentally the same Alpha-Halogenation Under Acidic Conditions mechanism seen for ketones. Here it is transplanted onto an acyl bromide instead of a ketone. The catalytic P/PBr₃ machinery is bolted on to solve the "carboxylic acids don't enolize" problem. This article works through the full catalytic cycle with explicit curved arrows. It covers acyl bromide formation, enolization of the acyl bromide, and electrophilic attack on bromine. It also covers the final exchange step that regenerates catalyst and releases the alpha-bromo acyl bromide. This intermediate hydrolyzes on aqueous workup to the alpha-bromo acid. Three fully worked examples anchor the mechanism in real transformations. These include a simple aliphatic acid, a synthetically useful branched substrate, and a multi-step exam-style problem culminating in amino acid synthesis.
- Carboxylic acids resist simple acid-catalyzed enolization; HVZ solves this by first converting a small amount of acid to the acyl bromide, which enolizes far more easily.
- (or catalytic red P + , which generates in situ) is used in catalytic amounts — typically 5–10 mol %.
- Bromine () is the stoichiometric halogen source; the enol of the acyl bromide attacks exactly as a ketone enol would.
- The product is initially the alpha-bromo acyl bromide; it exchanges with fresh carboxylic acid to regenerate acyl bromide catalyst and release the alpha-bromo acid (or its acyl bromide, hydrolyzed on workup).
- Only carboxylic acids with at least one alpha C–H react; the reaction is essentially unusable for tertiary-alpha-carbon-free or fully substituted acids and gives mixtures with acids possessing multiple acidic alpha positions unless controlled.
- Alpha-bromo acids from HVZ are gateway intermediates to alpha-amino acids, alpha-hydroxy acids, and acrylic (α,β-unsaturated) acids via or E2 follow-up chemistry.
- Key idea: HVZ brominates the alpha carbon of a carboxylic acid by routing the substrate, catalytically, through its far-more-enolizable acyl bromide tautomer.
Where this lives today
Alpha-halo carboxylic acids made by HVZ chemistry remain workhorse intermediates in fine chemical and pharmaceutical synthesis. Alpha-bromo esters and acids are common electrophiles for building alpha-amino acid analogs used in peptide mimetic and medicinal chemistry programs, exploiting the same displacement logic used to convert alpha-bromo acids into amino acids in Example 2. Alpha-halo acids are also key precursors to alpha,beta-unsaturated (acrylic-type) acids via base-mediated E2 elimination, feeding acrylate and methacrylate monomer chemistry used in polymer manufacturing. In biochemistry-adjacent research, alpha-halo carbonyl compounds (including those derived from HVZ-type chemistry, though many modern syntheses instead use enolate chemistry with NBS or related electrophilic halogen sources for milder, more selective control) serve as mechanism-based enzyme inhibitors and affinity-labeling reagents, because the activated carbon–halogen bond reacts irreversibly with active-site nucleophiles in enzymes whose mechanism involves a nucleophilic residue near the substrate's alpha carbon. The conceptual core of HVZ — that converting a carboxylic acid into a more reactive acyl derivative (acyl halide, mixed anhydride, or activated ester) dramatically increases its enol content and hence its alpha-carbon reactivity — also underlies modern enolate-generation strategies used throughout total synthesis, where chemists deliberately choose acyl halides, thioesters, or Weinreb amides specifically to access alpha-functionalization chemistry that the free carboxylic acid could never undergo directly. The catalytic phosphorus-halide activation strategy itself, independent of the alpha-halogenation application, is the same conceptual machinery used broadly in synthetic methodology: and remain standard reagents for converting alcohols to alkyl halides and carboxylic acids to acyl halides throughout the modern synthetic organic toolkit, making the mechanistic literacy built by studying HVZ transferable well beyond this one named reaction.
Ask the tutor: How does the mechanism change if you use NBS with a catalytic acid instead of Br₂/PBr₃ — is that still "HVZ," or a different pathway to the same product?
The physical picture
Ordinary carboxylic acids do undergo a slow, acid-catalyzed alpha-halogenation if you push hard enough (excess halogen, prolonged heating, strong acid), but the reaction is sluggish and low-yielding because the enol content of a carboxylic acid is vanishingly small compared to a ketone's. The reason traces to resonance. In a ketone enol, the enol OH's oxygen lone pair conjugates only with the alkene it is attached to. In a carboxylic acid, the carbonyl already has an -OH group feeding electron density into the carbonyl carbon by resonance; the "carboxylic acid enol" — really an enediol tautomer, pattern — is a high-energy, poorly stabilized species relative to the fully conjugated, resonance-stabilized carboxylic acid itself. Enolization of essentially never competes kinetically with direct halogenation pathways under mild conditions. The trick embedded in HVZ is to swap the -OH for -Br. An acyl bromide, , has no O–H to hyperconjugate or resonance-donate; the carbonyl is a much better electrophile, and — crucially for this reaction — the corresponding enol, , is thermodynamically far more accessible. Bromine, an electron-poor leaving group with modest π-donating ability (much weaker than OH), does not compete as effectively with the alpha carbon for electron density, so the enol tautomer of an acyl bromide is populated at a meaningfully higher (though still small) equilibrium fraction than that of the parent acid. That small increase in enol population, combined with the enol's very high nucleophilicity at the alpha carbon, is enough to make bromination fast on a laboratory timescale. The catalytic cycle is elegant because the acid itself never needs to be converted to the acyl bromide in bulk. Only a small, steady-state amount of needs to exist at any moment; it enolizes, attacks , and the resulting alpha-bromo acyl bromide then reacts with a fresh, unreacted molecule of the parent carboxylic acid in an acyl-exchange (mixed-anhydride-like) step. This exchange regenerates a new acyl bromide (now on the fresh acid molecule) and releases the alpha-bromo product as its acyl bromide, which upon aqueous workup hydrolyzes to the alpha-bromo carboxylic acid. Because the catalyst is regenerated every cycle, only 5–10 mol % of (or red phosphorus, which reacts with to generate in situ) is needed relative to the carboxylic acid substrate.
The core ideas
The reaction is governed by three linked equilibria/steps, each with its own driving force.
Acyl bromide formation (stoichiometrically minor, catalytic in effect):
Enolization equilibrium of the acyl bromide, governed by an equilibrium constant :
where: for an acyl bromide is larger than for the parent acid, though still (typically enol fractions in the – range for the acyl bromide versus far smaller, effectively negligible, for the free acid).
Rate law for the overall halogenation, exactly analogous to acid-catalyzed ketone halogenation:
where: the rate is independent of once enolization is rate-limiting — the classic hallmark shared with Alpha-Halogenation Under Acidic Conditions, because bromine trapping of the enol is fast compared to the slow enolization step. Reading these three relations together: the acyl bromide is generated in a small steady-state pool (first equation), a small fraction of that pool exists as the reactive enol (second equation), and the enol is consumed by at a rate set purely by how fast enol forms, not by how much is around (third equation). The overall transformation is therefore zero order in bromine and first order in acyl bromide — a signature that confirms the enolization, not the halogen-trapping step, is rate-determining.
Goal: show, with curved arrows, how converts into the acyl bromide, and how that acyl bromide tautomerizes to its enol — the species that actually reacts with bromine.
Step 1 (nucleophilic attack of carboxylic acid oxygen on phosphorus). The carbonyl oxygen of (or, more precisely, the hydroxyl oxygen after initial protonation of -derived electrophilic phosphorus) uses a lone pair to attack the electrophilic phosphorus of . Phosphorus is a good electrophile here because it bears three electronegative bromines and an empty low-lying orbital character; the oxygen lone pair flows into , displacing a bromide as it does (bromide leaves with the P–Br bonding pair). This produces an oxyphosphonium-bromide intermediate: .
Step 2 (bromide attacks the carbonyl carbon, tetrahedral intermediate). The bromide ion released in Step 1 (or a second equivalent of bromide from solution) attacks the carbonyl carbon of this activated species. The carbonyl π bond breaks heterolytically, pushing the electron pair onto oxygen, generating a tetrahedral alkoxide-like intermediate bearing both the new C–Br bond and the O–PBr₂ leaving group.
Step 3 (collapse of the tetrahedral intermediate, expulsion of the phosphorus leaving group). The tetrahedral intermediate collapses: the alkoxide oxygen's lone pair reforms the C=O π bond, and the C–O(PBr₂) bond breaks heterolytically, kicking out (which subsequently reacts with more /acid to give phosphorous acid derivatives — this byproduct chemistry is analogous to alcohol-to-alkyl-bromide conversion with ). The product is the acyl bromide, , with the P now carrying an oxygen substituent, priming it for further turnover with more carboxylic acid.
Step 4 (protonation of the acyl bromide carbonyl oxygen). A trace of generated in the byproduct chemistry (or simply adventitious acid) protonates the carbonyl oxygen of the acyl bromide. Protonation dramatically increases the electrophilicity of the carbonyl carbon and, more importantly for enolization, increases the acidity of the alpha C–H bonds by stabilizing the developing negative character on oxygen in the transition state for enolization.
Step 5 (enolization: alpha C–H bond breaks, enol forms). A base (often another molecule of carboxylic acid, or bromide, or trace water) removes one of the alpha C–H protons. As the C–H sigma bond breaks, its electron pair flows to form a new π bond between the alpha carbon and the carbonyl carbon; simultaneously the C=O π bond's electrons shift fully onto oxygen, which — having just been protonated — becomes a neutral enol –OH. The product is the enol of the acyl bromide, , a nucleophilic alkene with substantial electron density at the alpha (former carbonyl) carbon, exactly as in ketone enolization. This step is rate-limiting for the overall halogenation.
Go deeper · Derivation B · 2 minMechanism 2 — Electrophilic bromination of the enol and catalyst turnover
Goal: show how the enol formed above attacks , and how the resulting alpha-bromo acyl bromide exchanges with fresh substrate to close the catalytic cycle.
Step 1 (enol attacks Br–Br as a nucleophile). The electron-rich alpha carbon of the enol attacks one bromine atom of . The alkene π electrons flow into the empty orbital of the bond, forming a new C–Br sigma bond at the alpha carbon while the Br–Br bond breaks heterolytically, expelling bromide ion. This is mechanistically identical to a ketone enol's attack on bromine — an -type electrophilic substitution at an alkene carbon, proceeding through (or near) a bromonium-like transition state, though for simple terminal enols a direct open-cation/concerted pathway is typically invoked.
Step 2 (oxocarbenium formation and reprotonation loss). As the new C–Br bond forms at the alpha carbon, the developing positive charge is stabilized by the adjacent enol oxygen, which pushes a lone pair in to reform a C=O π bond — regenerating a protonated carbonyl (an oxocarbenium ion) now bearing the new alpha bromine: .
Step 3 (deprotonation restores the neutral carbonyl). The bromide ion released in Step 1 (or another base in solution) removes the proton from the oxocarbenium oxygen, regenerating a neutral carbonyl. The product of this stage is the alpha-bromo acyl bromide, — note both halogens are now present: one from the original activation (at the acyl carbon) and one freshly installed at the alpha carbon (from ).
Step 4 (acyl exchange with fresh, unreacted carboxylic acid — catalyst turnover). The alpha-bromo acyl bromide is itself a reactive acylating agent. A fresh molecule of the original (unreacted, non-alpha-brominated) carboxylic acid, , attacks the acyl bromide carbon of with its hydroxyl oxygen lone pair, exactly as in Mechanism 1 Step 1–3 (formation of a tetrahedral intermediate, then collapse). Bromide is expelled from the acyl carbon of the alpha-brominated species, generating a new acyl bromide on the original, unbrominated substrate — this is the species that continues the cycle — while the alpha-bromo product is released as (once its own oxygen picks up the proton from the tetrahedral collapse) or, more precisely, as a mixed-anhydride-like acyl-bromide/acid exchange product that hydrolyzes cleanly to on aqueous workup.
Step 5 (aqueous workup). Any remaining acyl bromide — whether on brominated or unbrominated substrate — is hydrolyzed by water added at the end of the reaction. Water's oxygen lone pair attacks the acyl carbonyl carbon, a tetrahedral intermediate collapses expelling bromide, and the final isolated product is the alpha-bromo carboxylic acid, , plus . Net result over the full cycle: one equivalent of is consumed per acid molecule brominated, is used catalytically (regenerated in effect via the acyl-bromide shuttle), and the overall transformation is
Worked examples
Example 1 — Foundational: propanoic acid to 2-bromopropanoic acid. Substrate: (propanoic acid), catalytic (~5 mol %), 1.0 equiv , heat. Only one type of alpha carbon exists (the between the methyl and the carboxyl), bearing two acidic hydrogens. Following Mechanism 1: converts a small fraction of the acid to ; this acyl bromide tautomerizes (rate-limiting step) to the enol . Following Mechanism 2: the enol's terminal alkene carbon (the former alpha carbon) attacks , installing bromine there and regenerating the carbonyl to give . This species exchanges with a fresh molecule of propanoic acid, releasing (2-bromopropanoic acid, after hydrolysis of any residual acyl bromide) and regenerating catalyst on the new substrate molecule. Since the alpha carbon in the product, , bears four different groups (, , , ), the product is chiral; because the enol intermediate is planar at the alpha carbon and bromine can approach either face with equal probability, the product 2-bromopropanoic acid is obtained as a racemate — a direct stereochemical consequence of the flat, sp²-hybridized enol intermediate, just as in ketone alpha-bromination.
Example 2 — Applied: synthesis of an alpha-amino acid precursor from isovaleric acid. Target: 2-bromo-3-methylbutanoic acid, en route to valine via subsequent ammonolysis. Substrate: isovaleric acid, . The alpha carbon here is the adjacent to the carbonyl (not the isopropyl methine, which is beta, not alpha, to the carbonyl — a common point of confusion). Applying HVZ: catalytic generates ; enolization gives ; bromination of this enol installs Br at the alpha carbon to give, after exchange and workup, 2-bromo-3-methylbutanoic acid, . This alpha-bromo acid is now poised for the classic follow-up: treatment with excess aqueous or liquid ammonia displaces bromide via an mechanism (ammonia's nitrogen lone pair attacks the alpha carbon backside to the C–Br bond, inverting configuration at that carbon as bromide departs), giving, after the ammonium carboxylate is neutralized, the amino acid valine, . This two-step sequence (HVZ, then ammonolysis) is one of the standard textbook routes to racemic alpha-amino acids from readily available carboxylic acids, and it illustrates why the alpha-halo acid intermediate is valuable precisely because the C–Br bond sits next to an electron-withdrawing carbonyl, which both promotes clean displacement (by stabilizing the developing negative charge in the transition state and by not offering competing elimination pathways as readily as, say, an isolated secondary alkyl bromide) and racemizes cleanly at the bromination step itself (so the amino acid is obtained racemic, requiring a resolution step for enantiopure product).
Example 3 — Exam-level: distinguishing mono- vs. dibromination and quantifying stoichiometry. A student treats 2-methylbutanoic acid, , with catalytic and exactly 1.05 equivalents of , and is asked to (a) identify the major product and its stereochemical outcome, and (b) predict what happens with excess (2.2 equiv) . Setting up the problem. The alpha carbon in 2-methylbutanoic acid is the carbon bearing the methyl branch: , attached to , , , and one . This is a single alpha C–H (a tertiary-like alpha position with only one abstractable hydrogen once you draw it out — note the parent acid already has a stereocenter at C2 if obtained enantiopure, but as typically supplied it is racemic). (a) With 1.05 equiv Br₂. Only one alpha C–H exists at this carbon, so only mono-bromination is chemically possible there — there is no second alpha C–H at C2 to remove for a further round of enolization/bromination at that same site. (The of the ethyl group is a beta carbon, not activated for enolization by the same mechanism, since the resulting "enol" would require breaking a bond two carbons from the carbonyl and is not accessible via simple keto–enol tautomerism of the acyl bromide.) Following Mechanisms 1 and 2: acyl bromide formation, enolization at C2 (removing the single remaining alpha H and forming ), then bromination of this trisubstituted enol installs Br at C2, destroying that stereocenter's original configuration (since the enol is planar there) and reforming it, giving racemic 2-bromo-2-methylbutanoic acid, , as the clean, single mono-brominated product. Because there is only one alpha hydrogen total, the reaction is intrinsically self-limiting at mono-substitution regardless of excess — once that hydrogen is replaced by Br, no further alpha C–H remains for the acyl bromide to enolize through, and enolization (hence further halogenation) simply cannot occur again at that carbon. (b) With excess Br₂ (2.2 equiv). Because the alpha carbon has already lost its only C–H after the first bromination, additional has no further alpha position to attack; the excess bromine remains largely unreacted (or engages in slow, non-mechanistically-relevant side reactions such as radical bromination of other C–H bonds under photochemical/thermal conditions, which is not part of the ionic HVZ pathway and is normally suppressed by running the reaction in the dark or under controlled mild heating). This example is a clean illustration of why substrates with only one alpha C–H — as opposed to acids like acetic acid (, three alpha H's) — are self-limiting to mono-halogenation, while acids with multiple alpha hydrogens (like acetic or propanoic acid) can in principle be pushed to di- or per-substitution if excess and prolonged reaction times are used, since each successive halogenation still leaves at least one alpha C–H available until full substitution is reached.
Limiting cases, scope & common traps
| Situation | What happens | Why |
|---|---|---|
| Acid with no alpha C–H (e.g., , pivalic acid) | No reaction at the alpha position | No C–H available to remove in the enolization step; acyl bromide still forms but cannot tautomerize to an enol |
| Acid with one alpha C–H (e.g., isobutyric acid) | Clean, self-limiting mono-bromination | Only one enolizable H; product has no remaining alpha C–H |
| Acid with multiple alpha C–H's + excess Br₂ | Progressive di-, tri-substitution possible | Each mono-brominated product still retains alpha C–H(s) until fully substituted |
| Using instead of | Analogous HVZ chlorination works but is less commonly used/less clean | Same mechanism; / + can substitute, though bromination is the classic textbook version |
| Attempting HVZ directly on esters or amides | Does not work by this mechanism | Esters/amides cannot be activated the same way by (no free to displace); different halogenation strategies (e.g., LDA enolate + electrophilic halogen source) are needed instead |
| Omitting /red phosphorus entirely | Reaction is extremely slow or fails | Without catalytic acyl bromide formation, the carboxylic acid's own enol content is too low to react with at a useful rate |
| Confusing alpha vs. beta carbon in branched acids | Wrong site predicted for bromination | Only the carbon directly attached to the carbonyl is "alpha"; enolization mechanistically requires removing an H from that specific carbon |
The chemist behind it
The reaction bears three names because it was independently developed and refined by three chemists working in close succession in the late nineteenth century. Carl Magnus von Hell, a German chemist, first reported alpha-halogenation of carboxylic acids using phosphorus and bromine in 1881. Jacob Volhard, also working in Germany and known independently for the Volhard method of quantitative silver/thiocyanate titration in analytical chemistry, extended and clarified the scope of the reaction shortly after. Nikolai Zelinsky, a Russian organic chemist who later became renowned for catalytic dehydrogenation chemistry and, separately, for inventing an early effective gas-mask charcoal filter used in World War I, further systematized the reaction's use for synthesizing alpha-amino acids via alpha-halo acid intermediates — a research direction motivated by the emerging importance of amino acid chemistry in early twentieth-century biochemistry.
Origins · 1 minNikolai Dmitrievich Zelinsky and how this was discovered
Zelinsky's career illustrates how "pure" mechanistic organic chemistry and urgent applied problems can share a single mind. His systematic studies of alpha-halogenation and its use in synthesizing amino acids fed directly into a broader research program on catalytic hydrogenation, dehydrogenation, and cyclization of hydrocarbons over metal catalysts — work that helped found modern petroleum reforming chemistry. During the First World War he designed a activated-charcoal gas mask that saved an enormous number of lives, applying the same rigorous physical-organic thinking about adsorption and reactivity that underpinned his laboratory bench chemistry.
Why doesn't a carboxylic acid just enolize and react with Br₂ directly, without needing PBr₃ at all?
It can, in principle, but the rate is far too slow to be useful. The carboxylic acid's own enol tautomer (an enediol-like species) is destabilized because the -OH oxygen already resonance-stabilizes the carbonyl in the acid form; converting to the enol gains little energetically and the enol population is exceedingly small. Under forcing conditions (excess halogen, high temperature, long times) direct halogenation of acids does occur slowly, but it is not synthetically practical. solves this by diverting a small fraction of the acid into the acyl bromide, whose enol is populated at a usefully higher level, making the overall process fast enough for laboratory use.
What role does bromide ion play beyond forming the C–Br bond?
Bromide ion is generated continuously as a byproduct at several steps (acyl bromide formation, enol bromination, tetrahedral intermediate collapse) and serves double duty: as the nucleophile that attacks acyl carbons in tetrahedral-intermediate-forming steps, and as a general base that can deprotonate oxocarbenium intermediates or assist proton transfers during enolization. Its constant regeneration and re-use throughout the catalytic cycle is part of why the overall process needs only a catalytic phosphorus source alongside stoichiometric molecular bromine.
Can HVZ be used to make alpha,alpha-dibromo or alpha,alpha,alpha-tribromo acids?
Yes, provided the substrate has enough alpha hydrogens and enough (and time) is supplied. Each successive alpha-bromination still leaves remaining alpha C–H bonds (until the alpha carbon is fully substituted with three halogens, if it started as a group), so acetic acid, for example, can in principle be carried through mono-, di-, and tri-bromoacetic acid stages with excess bromine. In practice, controlling the reaction to stop cleanly at mono-substitution requires careful stoichiometry (near 1.0 equivalent ) and monitoring, since the mono-brominated product retains reactive alpha C–H's and can react further.
How does HVZ compare to using LDA or NaOEt to form an ester enolate for alpha-halogenation?
The enolate route (deprotonating an ester with a strong, non-nucleophilic base like LDA, then quenching with an electrophilic halogen source such as NBS or ) is mechanistically distinct: it forms a fully deprotonated, highly nucleophilic enolate stoichiometrically and irreversibly, giving excellent control and often high yields under mild conditions, but it requires strong anhydrous base and low temperatures, and it operates on esters rather than free acids. HVZ instead relies on a small, continuously regenerated equilibrium population of a neutral enol under mildly acidic/thermal conditions, works directly on carboxylic acids without a separate esterification step, and is catalytic in the activating phosphorus reagent — but it offers less fine control over stoichiometry (risk of over-halogenation) and is essentially unusable for esters or amides by this specific mechanism.
Why does the alpha-bromo acyl bromide react preferentially with fresh acid rather than with water, if the reaction mixture isn't rigorously anhydrous?
In practice HVZ reactions are run under anhydrous or near-anhydrous conditions (using or red P + , both of which are moisture-sensitive) specifically to suppress premature hydrolysis of the reactive acyl bromide intermediates. Only after the halogenation chemistry is complete is water deliberately added for workup, at which point all remaining acyl bromide species (both catalytic and product-bound) are hydrolyzed cleanly to the corresponding carboxylic acids. If water were present throughout, it would compete with fresh carboxylic acid for reaction with the acyl bromide intermediates, short-circuiting the catalytic cycle and reducing conversion.
Does HVZ bromination proceed with any regioselectivity in acids with two different alpha positions, e.g., an unsymmetrical ketone-like acid chain?
Since only the carbon directly attached to the carboxyl carbon is the "alpha" carbon by definition, there is normally only one alpha position (unless the acid is branched in a way that itself is the alpha carbon, as in Example 3). There is no competition between "different alpha carbons" in a simple monocarboxylic acid, because a carboxylic acid has exactly one carbonyl and hence exactly one alpha carbon; regiochemical questions in HVZ concern only which of the (possibly several) hydrogens on that single alpha carbon are removed, not competition between multiple alpha sites.
Why is bromine (Br2), rather than chlorine or iodine, the classic HVZ halogen source?
Bromine offers a practical balance: the Br–Br bond is weak enough for facile heterolytic cleavage by the nucleophilic enol (unlike the stronger Cl–Cl bond, which reacts less cleanly under these mild ionic conditions and is more prone to radical side reactions), while the C–Br bond formed is still reactive enough for useful downstream chemistry (unlike a C–I bond, whose parent is a comparatively poor electrophile for this ionic addition and whose reactions can suffer from reversibility). Analogous chlorinations using / are known and used industrially, but bromine remains the textbook and most broadly reliable choice.