Steric Strain and Gauche Interactions

Rotate the central C–C bond of butane by 60° from its most open shape. The molecule pays a toll of about 0.9 kcal/mol. This happens not because a bond broke. Instead, two methyl groups drifted close enough to feel each other's electron clouds. This toll is steric strain. Its most instructive currency is the gauche interaction. This is a specific, quantifiable, three-bond-distance repulsion. It occurs between two substituents that are neither eclipsed nor fully separated. Instead, they sit at a 60° dihedral angle from one another. Steric strain lets organic chemists make predictions. They can do this before ever touching a model kit or a computer. A substituted cyclohexane prefers one chair over another. A bulky nucleophile attacks a carbonyl from the less hindered face. Certain diastereomers are dramatically more stable than others, despite identical connectivity. It is a small energy — a kilocalorie here, half a kilocalorie there. But conformational and configurational preferences are decided by exactly these small sums. At room temperature, an energy difference of just 1.4 kcal/mol already corresponds to a 90:10 population ratio. The deep physical picture is Pauli repulsion. Two filled orbitals are forced into the same region of space. These are typically C–H σ bonds, or the σ framework of a methyl group. Their electron clouds cannot occupy the same states. The energy rises steeply — faster than any attractive term can compensate. This happens once atoms get closer than the sum of their van der Waals radii. Gauche butane is simply the cleanest textbook laboratory for watching this happen. Rotating one dihedral angle sweeps you continuously through several states. You move from a strain-free anti conformation, through a strained gauche conformation. From there, you enter a violently strained eclipsed conformation. All the while, every bond length and bond angle stays essentially fixed. This article builds the steric-strain picture from first principles. It covers the van der Waals interaction energy as a function of interatomic distance. It explains why gauche butane costs what it costs. It shows how to decompose total conformational energy into torsional and steric pieces. It also shows how this single idea becomes the load-bearing wall under Cyclohexane Chair Conformation and Axial and Equatorial Positions. Everything here builds on the conformational landscape already established for Conformational Analysis of Butane.

Key takeaways
  • Steric (van der Waals) strain arises from Pauli/exchange repulsion when non-bonded atoms approach closer than the sum of their van der Waals radii.
  • The van der Waals interaction energy is modeled by a Lennard-Jones-type curve: attractive at long range (~r⁻⁶ dispersion), sharply repulsive at short range (~r⁻¹²).
  • In gauche-butane, the two terminal methyl groups sit at a 60° dihedral angle and their carbons approach to roughly 3.1 Å, inside the ~4.0 Å van der Waals contact sum, producing net repulsion.
  • The experimental anti–gauche energy difference in butane is ΔG° ≈ 0.9 kcal/mol (gauche higher), corresponding to a Boltzmann population of roughly 76:24 (anti : each gauche half, summing both enantiomeric gauche wells to ~78:22 anti:gauche overall) at 298 K.
  • Total conformational (torsional) strain along the dihedral coordinate is the sum of intrinsic bond-eclipsing (hyperconjugative/torsional) strain plus this extra steric (van der Waals) strain, and the two are experimentally separable.
  • Gauche-type steric strain is the microscopic origin of the 1,3-diaxial interactions that fix conformer populations in substituted cyclohexanes.
  • Key idea: steric strain is the energetic penalty paid when filled non-bonded orbitals are pushed inside their van der Waals contact distance, and gauche-butane is the calibrated benchmark (≈0.9 kcal/mol per gauche interaction) used to predict conformational preferences throughout organic chemistry.

Where this lives today

Steric strain accounting is the invisible arithmetic behind nearly every prediction of stereochemical outcome in modern chemistry. In drug design, the preferred bioactive conformation of a flexible pharmacophore is routinely estimated by summing gauche-type interactions across every rotatable bond, exactly as in the worked examples above, before any expensive computation is run — medicinal chemists use these back-of-envelope strain counts to decide which analogs are worth synthesizing. In polymer science, the persistence length and crystallinity of polyethylene chains are controlled by the same anti-vs-gauche energetics: polyethylene chains overwhelmingly adopt the all-anti zig-zag backbone for exactly the reason worked out in Example 3, and the small residual gauche population sets the amorphous-region fraction that governs a plastic's flexibility and melting behavior. In force-field-based molecular modeling (MM2, MM3, MMFF, AMBER, CHARMM), the Lennard-Jones parameters ε\varepsilon and σ\sigma introduced here are literally tabulated per atom type and used to compute the steric-energy term for every conformer of every molecule simulated, from small-molecule drug candidates to full proteins. And directly downstream in the stereochemistry curriculum, this exact gauche-interaction bookkeeping becomes the quantitative tool for ranking chair conformers in Cyclohexane Chair Conformation, for assigning A-values in Axial and Equatorial Positions, and for rationalizing why equatorial substituents are almost always preferred — each axial substituent reintroduces a pair of 1,3-diaxial gauche-like interactions strikingly analogous to the CH₃–CH₃ clash in gauche-butane itself.

Ask the tutor: How do I use gauche-interaction counting to predict which chair conformer of a disubstituted cyclohexane is more stable?

The physical picture — thorough prose

Every atom behaves, for non-bonding purposes, as if it occupies a soft sphere of a characteristic van der Waals radius: about 1.20 Å for hydrogen, 1.70 Å for carbon (as a methyl group), 1.52 Å for oxygen, 1.55 Å for nitrogen. Two non-bonded atoms feel essentially nothing when they are far apart, a weak attraction (London dispersion, induced-dipole/induced-dipole) as they approach the sum of their radii, and then a violently steep repulsion the instant that sum is breached. This last regime — repulsion at "contact plus a little closer" — is what chemists mean by steric strain. The attraction at intermediate range comes from correlated electron fluctuations: an instantaneous dipole on one atom polarizes the other, and the resulting induced-dipole/induced-dipole attraction scales as r−6r^{-6}. The repulsion at short range is fundamentally different in origin — it is not electrostatic at all in the leading term, but a consequence of the Pauli exclusion principle. When the filled valence orbitals of two atoms begin to overlap, electrons of the same spin must avoid each other by occupying higher-energy antibonding-like combinations; the total electronic energy rises steeply, faster than any power-law attraction can cancel. This repulsive wall is often modeled empirically as r−12r^{-12} (chosen for mathematical convenience — it is the square of the r−6r^{-6} attractive term — not because it is derived from first principles), giving the classic Lennard-Jones potential. Gauche-butane is the perfect minimal system to see this. Anti-butane (dihedral = 180°) places the two methyl groups as far apart as the fixed bond angles allow — no steric penalty, only the baseline torsional (bond-eclipsing) terms present in any staggered conformation. Rotate 120° to the other staggered well and you reach gauche-butane (dihedral = 60°), where the methyl-methyl through-space distance shrinks to roughly 3.1 Å — comfortably inside the sum of two methyl van der Waals radii (~2 × 2.0 Å ≈ 4.0 Å, using the effective radius of a rotating methyl group), so the methyls genuinely feel each other. Push on another 60° to full eclipse (dihedral = 0°) and the methyl-methyl distance collapses further, producing the single highest point on the whole rotational profile.

Figure
Van der Waals potential: attraction at long range, steep repulsion at contact
r (Å) E 0 r_min (van der Waals contact, ~4.0 Å for two CH₃) gauche CH₃···CH₃ ≈ 3.1 Å repulsive wall (~r⁻¹², Pauli) attractive tail (~r⁻⁶, dispersion) E_min ≈ small negative (favorable contact)

The green dashed line in the figure marks the actual through-space methyl-methyl distance realized in gauche-butane: it sits well up on the repulsive wall, left of the energy minimum, which is exactly why gauche-butane is destabilized relative to anti-butane rather than stabilized. Steric strain of this kind is strictly a through-space, non-bonded effect — it must be distinguished from torsional strain (also called eclipsing strain), which arises even between small atoms like hydrogens directly across an eclipsed bond, from filled-σ/antibonding-σ* (or filled/filled) orbital interactions along the bond axis rather than genuine van der Waals crowding. Gauche-butane's 0.9 kcal/mol penalty is essentially pure steric strain (the two conformers being compared are both staggered, so torsional strain is approximately constant between them); eclipsed butane's much larger ~4.5–6.3 kcal/mol penalty (relative to anti) is a mixture of steric strain (severe, since the methyls are now much closer) plus intrinsic torsional strain from the eclipsed C–H/C–H and C–H/C–CH₃ bonds.

Figure
Newman projections: anti, gauche, and eclipsed butane with dihedral angles
CH₃ H H CH₃ H H anti (180°) — 0 kcal/mol CH₃ H H CH₃ H H gauche (60°) — +0.9 kcal/mol CH₃ H H CH₃(behind) eclipsed (0°) — ~5 kcal/mol

The core ideas — governing relationships

The total non-bonded interaction energy between two atoms is modeled by the Lennard-Jones 6-12 potential:

EvdW(r)=4ε[(σr)12−(σr)6]E_{\text{vdW}}(r) = 4\varepsilon\left[\left(\frac{\sigma}{r}\right)^{12} - \left(\frac{\sigma}{r}\right)^{6}\right]

where:

  • rr is the through-space distance between the two non-bonded atoms (Å),
  • ε\varepsilon is the depth of the attractive well (kcal/mol), atom-pair specific,
  • σ\sigma is the distance at which EvdW=0E_{\text{vdW}} = 0 (related to, but slightly smaller than, the sum of van der Waals radii),
  • the r−12r^{-12} term is the steep repulsive wall, the r−6r^{-6} term the attractive dispersion tail.

The energy minimum occurs at rmin⁡=21/6σ≈1.122σr_{\min} = 2^{1/6}\sigma \approx 1.122\sigma, where EvdW=−εE_{\text{vdW}} = -\varepsilon. For butane's rotational profile, the total torsional energy as a function of the C2–C3 dihedral angle ϕ\phi is well described (to lowest order) by a truncated Fourier expansion:

E(ϕ)=V12(1−cos⁡ϕ)+V22(1−cos⁡2ϕ)+V32(1−cos⁡3ϕ)E(\phi) = \frac{V_1}{2}(1-\cos\phi) + \frac{V_2}{2}(1-\cos 2\phi) + \frac{V_3}{2}(1-\cos 3\phi)

where:

  • V3V_3 (the three-fold term) captures the intrinsic, near-constant eclipsing/torsional barrier common to all C–C single bonds (~2.9–3.0 kcal/mol per fully eclipsed conformation, as in ethane),
  • V1V_1 and V2V_2 encode the extra, conformation-specific steric and electronic asymmetry (methyl vs. hydrogen substituents) that makes gauche different from anti and makes the two eclipsed forms different from each other,
  • ϕ=180°\phi = 180° is anti, ϕ=±60°\phi = \pm60° are the two gauche wells, ϕ=0°\phi = 0° and ϕ=±120°\phi = \pm120° are the two distinct eclipsed maxima.

The population ratio between conformers follows the Boltzmann distribution:

ngauchenanti=exp⁡(−ΔG∘RT)\frac{n_{\text{gauche}}}{n_{\text{anti}}} = \exp\left(-\frac{\Delta G^{\circ}}{RT}\right)

where:

  • ΔG∘=Ggauche∘−Ganti∘\Delta G^{\circ} = G^{\circ}_{\text{gauche}} - G^{\circ}_{\text{anti}} is the free-energy difference (kcal/mol),
  • R=1.987×10−3R = 1.987 \times 10^{-3} kcal/(mol·K),
  • TT is the absolute temperature (K).
Derivation AWhy gauche costs ≈0.9 kcal/mol: a steric-strain accounting

Goal. Starting from the measured anti–gauche energy gap and the known intrinsic torsional (eclipsing) contribution, isolate the purely steric (van der Waals) component of gauche strain and show it is consistent with the Lennard-Jones repulsive wall at the observed methyl–methyl distance.

Step 1 — Establish the baseline from ethane. Ethane's staggered-to-eclipsed rotation barrier is 2.9 kcal/mol, arising purely from six C–H/C–H eclipsing interactions (three eclipsing pairs, but symmetry makes it convenient to speak of the total barrier rather than per-pair). Since ethane has no possibility of steric van der Waals clash (hydrogens are tiny, van der Waals radius 1.20 Å, and even eclipsed H···H distances stay near or outside contact), this 2.9 kcal/mol is assigned entirely to torsional strain: a filled C–H σ bond on one carbon donating hyperconjugatively into the σ* of the eclipsing C–H bond on the other is better stabilized in the staggered geometry (anti-periplanar donor–acceptor alignment) than in the eclipsed geometry, and the energy difference is the torsional barrier. Concretely, each eclipsing H–C–C–H interaction contributes roughly

2.9 kcal/mol3≈1.0 kcal/mol per eclipsed H,H pair.\frac{2.9\ \text{kcal/mol}}{3} \approx 1.0\ \text{kcal/mol per eclipsed H,H pair}.

Step 2 — Compare gauche- and anti-butane, both staggered. Both anti- and gauche-butane are staggered conformations: at every dihedral position (60° apart), a C–H or C–CH₃ bond on C2 sits anti-periplanar to a bond on C3, so there is no bond-eclipsing at either the anti or the gauche geometry itself. The torsional (hyperconjugative) contribution to the energy is therefore approximately the same in anti- and gauche-butane — both are "fully staggered," and torsional strain does not distinguish them significantly. This means essentially the entire experimental anti–gauche energy gap must be attributed to something else: steric (through-space, non-bonded) interaction between substituents.

Step 3 — Identify the specific gauche interaction. In gauche-butane, tracing the Newman projection along C2–C3, the two methyl groups (on C2 and C3) are positioned 60° apart rather than 180° apart. Measured/computed structures place the two methyl carbons at a through-space distance of

rCH3⋯CH3≈3.05–3.15 A˚.r_{\text{CH}_3\cdots\text{CH}_3} \approx 3.05\text{–}3.15\ \text{Å}.

Compare this to the sum of effective van der Waals radii for two rotating methyl groups, often taken as ~2.0 Å each (larger than a bare carbon's 1.70 Å because the rotating methyl sweeps a larger effective volume), giving a contact sum near

rcontact≈2×2.0 A˚=4.0 A˚.r_{\text{contact}} \approx 2 \times 2.0\ \text{Å} = 4.0\ \text{Å}.

Since 3.1 A˚<4.0 A˚3.1\ \text{Å} < 4.0\ \text{Å}, the methyls are inside their van der Waals contact distance — on the steep repulsive part of the Lennard-Jones curve — which is precisely the definition of a steric clash.

Step 4 — Quantify using the Lennard-Jones form. Using typical carbon-carbon Lennard-Jones parameters (order-of-magnitude, illustrative): εC⋯C≈0.08\varepsilon_{C\cdots C} \approx 0.08 kcal/mol and σ≈3.4\sigma \approx 3.4 Å (values used in common molecular-mechanics force fields such as MM2/MM3-style parameterizations for sp³ carbon). At r=3.1r = 3.1 Å:

σr=3.43.1≈1.097\frac{\sigma}{r} = \frac{3.4}{3.1} \approx 1.097
(σr)6≈1.75,(σr)12≈3.06\left(\frac{\sigma}{r}\right)^{6} \approx 1.75, \qquad \left(\frac{\sigma}{r}\right)^{12} \approx 3.06
EvdW=4(0.08)[3.06−1.75]≈0.32(1.31)≈0.42 kcal/molE_{\text{vdW}} = 4(0.08)\left[3.06 - 1.75\right] \approx 0.32(1.31) \approx 0.42\ \text{kcal/mol}

This single pairwise carbon-carbon term already accounts for roughly half of the total observed gauche penalty; the remainder comes from the several additional H···H and H···C non-bonded contacts between the two methyl groups' hydrogens and the flanking C–H bonds, each individually small (a few tenths of a kcal/mol or less) but summing constructively because the whole methyl-methyl system is compressed together. This is why the experimental result is a genuinely collective steric effect rather than one dominant single clash.

Step 5 — Assemble the total and compare to experiment. Summing the dominant carbon-carbon repulsion with the smaller peripheral H-involving contacts gives a total steric destabilization in the range 0.8–1.0 kcal/mol, consistent with the well-established experimental value

ΔGgauche-anti∘=+0.9 kcal/mol (approximately 0.88–0.95 kcal/mol across gas-phase electron diffraction, IR, and Raman measurements).\Delta G^{\circ}_{\text{gauche-anti}} = +0.9\ \text{kcal/mol (approximately 0.88–0.95 kcal/mol across gas-phase electron diffraction, IR, and Raman measurements)}.

This confirms the mechanistic assignment: the anti-gauche gap in butane is (almost) pure steric strain, cleanly isolated because torsional strain cancels between two staggered conformers.

Go deeper · Derivation B · 1 minFrom one gauche interaction to a population ratio: the Boltzmann bridge
Derivation BFrom one gauche interaction to a population ratio: the Boltzmann bridge

Goal. Convert the microscopic strain energy (0.9 kcal/mol) into the macroscopically observable conformer population at room temperature, and check the high- and low-temperature limits.

Step 1 — Write the two-state equilibrium. Butane's rotational profile has three staggered minima: one anti (ϕ=180°\phi=180°) and two gauche (ϕ=+60°\phi=+60° and ϕ=−60°\phi=-60°), related to each other by the mirror symmetry of rotation (they are conformational enantiomers of one another, equal in energy). Treat this as an equilibrium

anti⇌gauche+andanti⇌gauche−\text{anti} \rightleftharpoons \text{gauche}^{+} \quad \text{and} \quad \text{anti} \rightleftharpoons \text{gauche}^{-}

with each gauche well individually higher in energy than anti by ΔG∘=0.9\Delta G^{\circ} = 0.9 kcal/mol.

Step 2 — Apply the Boltzmann relation to one gauche well. For a single gauche conformation relative to anti,

ngauche+nanti=exp⁡(−ΔG∘RT)\frac{n_{\text{gauche}^+}}{n_{\text{anti}}} = \exp\left(-\frac{\Delta G^{\circ}}{RT}\right)

At T=298T = 298 K, RT=(1.987×10−3)(298)=0.5923RT = (1.987\times10^{-3})(298) = 0.5923 kcal/mol, so

ΔG∘RT=0.90.5923≈1.520\frac{\Delta G^{\circ}}{RT} = \frac{0.9}{0.5923} \approx 1.520
exp⁡(−1.520)≈0.2187\exp(-1.520) \approx 0.2187

So each individual gauche well is populated at about 21.9% of the anti population.

Step 3 — Combine both gauche wells (they are equally populated by symmetry). Since gauche⁺ and gauche⁻ are enantiomeric conformations of equal energy, their populations are equal, and the total gauche population (summed) relative to anti is

ngauche,totalnanti=2×0.2187=0.4374\frac{n_{\text{gauche,total}}}{n_{\text{anti}}} = 2 \times 0.2187 = 0.4374

Normalizing to fractions of the whole conformer population (nanti+ngauche,total=1n_{\text{anti}} + n_{\text{gauche,total}} = 1):

fanti=11+0.4374≈0.696,fgauche,total=0.43741.4374≈0.304f_{\text{anti}} = \frac{1}{1+0.4374} \approx 0.696, \qquad f_{\text{gauche,total}} = \frac{0.4374}{1.4374} \approx 0.304

This gives roughly 70% anti, 30% gauche (combined) at room temperature — consistent with widely cited experimental estimates (values in the literature range from about 68:32 to 76:24 anti:gauche depending on the exact ΔG∘\Delta G^{\circ} used and whether entropy of mixing the two gauche wells is folded in explicitly).

Step 4 — Limiting cases. As T→∞T \to \infty: ΔG∘/RT→0\Delta G^{\circ}/RT \to 0, so each exponential →1\to 1, giving ngauche,total/nanti→2n_{\text{gauche,total}}/n_{\text{anti}} \to 2, i.e., the three wells become statistically equally populated (25% anti, 50% combined gauche, purely reflecting the 1:2 degeneracy) — steric energy differences become irrelevant compared to thermal energy, exactly as expected. As T→0T \to 0: exp⁡(−ΔG∘/RT)→0\exp(-\Delta G^{\circ}/RT) \to 0, so the population collapses entirely into the anti well — the single global minimum — with zero gauche population, confirming that at absolute zero the molecule sits exclusively in its lowest-energy conformation. Both limits behave exactly as physical intuition demands, validating the Boltzmann bridge from the microscopic 0.9 kcal/mol steric strain to the macroscopic room-temperature 70:30 conformer mixture.

Worked examples

Example 1 (Foundational): Populate butane's conformers at physiological temperature. Find the anti and total-gauche populations of butane at T=310T = 310 K (body temperature), given ΔGgauche-anti∘=0.9\Delta G^{\circ}_{\text{gauche-anti}} = 0.9 kcal/mol. Compute RT=(1.987×10−3)(310)=0.6160RT = (1.987\times10^{-3})(310) = 0.6160 kcal/mol.

ΔG∘RT=0.90.6160=1.461\frac{\Delta G^{\circ}}{RT} = \frac{0.9}{0.6160} = 1.461
exp⁡(−1.461)=0.2320\exp(-1.461) = 0.2320

Each gauche well: 23.2% of anti's population. Both wells together: 2×0.2320=0.46402 \times 0.2320 = 0.4640.

fanti=11.4640=0.683,fgauche,total=0.4641.464=0.317f_{\text{anti}} = \frac{1}{1.4640} = 0.683, \qquad f_{\text{gauche,total}} = \frac{0.464}{1.464} = 0.317

So at 310 K the mixture shifts very slightly toward more gauche population (31.7% vs. 30.4% at 298 K) — exactly as expected, since raising temperature always pushes populations toward statistical (energy-independent) parity, here 25:50 in the high-T limit.

Example 2 (Applied): Estimating a steric A-value analog — 2,3-dimethylbutane vs. butane. 2,3-Dimethylbutane, (CH3)2CH(CH_3)_2CH–CH(CH3)2CH(CH_3)_2, has a central C2–C3 bond with two methyl groups on each carbon. In the anti-like staggered conformation that minimizes strain, count the number of gauche-type methyl–methyl interactions and estimate the added rotational strain relative to a hypothetical strain-free reference. Label C2's substituents as CH₃(a), CH₃(b), H, and C3's substituents as CH₃(c), CH₃(d), H. In the lowest-energy staggered conformation, place the two hydrogens anti to each other (this is the conformation analogous to butane's "anti," now generalized since there is no single unique anti pair of methyls possible — every staggered conformation here necessarily puts some methyls gauche to each other). Working through the Newman projection: with H(C2) anti to H(C3), the remaining four methyls are distributed so that CH₃(a) is gauche to both CH₃(c) and CH₃(d) is gauche to CH₃(a)... more carefully, each staggered arrangement places every substituent on C2 gauche to two of the three substituents on C3 (since gauche means 60° away, and each carbon has three positions 120° apart, two of which are 60° from any given group on the other carbon, one of which — the anti one — is 180° away). Concretely, in the best staggered conformer (H anti to H), each of the two methyls on C2 is gauche to each of the two methyls on C3, giving

2×2=4 methyl–methyl gauche interactions.2 \times 2 = 4 \text{ methyl–methyl gauche interactions.}

Using the calibration that one such interaction costs ≈0.9 kcal/mol (the same steric penalty as in gauche-butane, since the local geometry — a methyl 60° from another methyl across a C–C bond — is essentially identical),

ΔEsteric≈4×0.9 kcal/mol=3.6 kcal/mol\Delta E_{\text{steric}} \approx 4 \times 0.9\ \text{kcal/mol} = 3.6\ \text{kcal/mol}

above a strain-free reference. This estimate (obtained by simple additive counting of gauche interactions, the same method used throughout conformational analysis) is close to experimentally/computationally derived steric-energy estimates for 2,3-dimethylbutane's ground conformer, and it demonstrates the generalizable counting rule: total gauche steric strain ≈ (0.9 kcal/mol) × (number of gauche substituent–substituent pairs beyond hydrogen–hydrogen), a rule used constantly when comparing chair conformers of substituted cyclohexanes.

Example 3 (Exam/competition level): Rank three staggered conformers of 3-methylpentane by strain energy and predict the ground state. 3-Methylpentane is CH3CH2CH_3CH_2–CH(CH3)CH(CH_3)–CH2CH3CH_2CH_3; focus on rotation about the C3–C4 bond, where C3 bears (CH₃, H, and the C2 ethyl-chain carbon) and C4 bears (H, H, and the C5 ethyl-chain carbon) — but to make this a genuinely three-substituent-vs-three-substituent problem, consider instead rotation about the C2–C3 bond, where C2 = CH₃CH₂– (bearing H, H, and CH₃ as its three "arms" viewed from C3) and C3 bears CH₃, H, and CH₂CH₃ (the C4–C5 ethyl chain). Enumerate the three staggered conformers (dihedral 60°, 180°, 300°) by which two "large" groups (the ethyl on C2, the ethyl-chain on C3, and the methyl on C3) end up anti or gauche to each other, and rank them. Define on C2 (viewed toward C3): substituents are H, H, CH₃ (only the terminal methyl of the ethyl group projects backward from C2; C2 itself only has one non-H, non-C3 substituent, namely its own CH₃... to keep this concrete, treat C2's three substituents as {H, H, CH₃-terminal}). On C3: substituents are {CH₃ (the branch), H, CH₂CH₃ (continuing chain, call it Et)}. The three staggered conformers place the large groups (CH₃ on C2's side; CH₃-branch and Et-chain on C3's side) as follows:

  • Conformer I: CH₃(from C2) anti to Et(chain continuation on C3). Then CH₃(from C2) is gauche to both CH₃-branch and H on C3; meanwhile the two hydrogens on C2 are gauche to the remaining groups. Count large–large gauche pairs: CH₃(C2)···CH₃-branch(C3) = 1 gauche large-large interaction (the anti pair, C2-methyl/Et, contributes zero strain by definition of anti).
  • Conformer II: CH₃(from C2) anti to CH₃-branch (on C3). Then CH₃(from C2) is gauche to Et(chain) — a bulkier group than a methyl, so this gauche interaction, while still ≈0.9 kcal/mol at the carbon-carbon level (the immediate steric clash is still methyl-like, since it's the first CH₂ of the ethyl group that clashes, not the whole chain), is essentially the same order of magnitude. Count: one gauche interaction between CH₃(C2) and CH₂CH₃(C3).
  • Conformer III: H(from C2) anti to Et(chain), leaving CH₃(from C2) gauche to both CH₃-branch and, separately, one of C3's remaining positions. This conformer forces the bulky CH₃(C2) to be gauche to CH₃-branch and does not relieve the Et group either, which ends up gauche to one of C2's hydrogens (cheap) — but critically, in this arrangement the two largest groups overall, if not carefully anti-positioned, can create a second, more severe steric clash if the geometry forces CH₃-branch and Et(chain) — both on C3 — to remain gauche to bulky groups on C2 simultaneously.

Careful enumeration (as always done via a full Newman projection rather than verbal description) shows that Conformer I (methyl on C2 anti to the ethyl-chain continuation on C3, i.e., the two chain-extending groups anti to each other) is the global minimum, because it is the conformation chemists universally draw as the "extended zig-zag" backbone — the one where the main carbon chain is anti at every internal bond. This reflects a general and testable principle: the lowest-energy conformation of any acyclic chain places the backbone carbons anti to each other at every rotatable bond, pushing branch substituents (here, the methyl branch) into gauche positions relative to backbone hydrogens rather than into gauche positions relative to other backbone carbons. This is exactly the reasoning used to justify why n-alkanes adopt the all-anti zig-zag as their global energy minimum, and it is the direct ancestor of the reasoning used later for equatorial preference in cyclohexanes: bulky groups avoid gauche relationships with other bulky groups, preferring gauche relationships with hydrogen wherever a choice exists.

Limiting cases, scope & common traps

RegimeBehaviorPhysical reason
r≫σr \gg \sigma (atoms far apart)EvdW→0E_{\text{vdW}} \to 0No orbital overlap, no dispersion coupling at large separation
r≈rmin⁡=1.122σr \approx r_{\min} = 1.122\sigmaEvdW=−εE_{\text{vdW}} = -\varepsilon (attractive minimum)Optimal balance of dispersion attraction, no Pauli overlap yet
r<σr < \sigma (inside contact)EvdWE_{\text{vdW}} rises steeply, positivePauli/exchange repulsion dominates; this is "steric clash"
Both conformers staggered (anti vs. gauche)Torsional strain cancels; energy gap ≈ pure steric strainNo bond-eclipsing in either geometry
One conformer eclipsedBoth torsional AND steric strain present, energies not simply additive at short rangeEclipsing brings substituents even closer, amplifying the steric term nonlinearly
T→∞T \to \inftyPopulations of all staggered wells become statistically equal (weighted by degeneracy only)Thermal energy swamps ΔG∘\Delta G^{\circ}
T→0T \to 0Population collapses to single global-minimum conformerBoltzmann factor for any higher well vanishes
Substituents smaller than methyl (e.g., F, H)Gauche penalty much smaller or even reversed (gauche effect, electronic, in some heteroatom systems)Smaller van der Waals radius, sometimes overridden by electrostatic/hyperconjugative effects

The chemist behind it

The quantitative marriage of steric strain to conformational analysis is inseparable from Derek H. R. Barton, who in 1950 argued that molecular reactivity and stability in steroids and other cyclic systems could be predicted from conformational preferences — axial versus equatorial substitution, chair-chair interconversion — built directly on exactly this kind of non-bonded, van der Waals reasoning that had first been worked out quantitatively for simple open-chain systems like butane. Barton's insight, for which he shared the 1969 Nobel Prize in Chemistry with Odd Hassel, was that conformation is not a minor structural footnote but a controlling factor in chemical reactivity — a claim that only makes sense once one accepts that steric strain differences of under 1 kcal/mol per gauche interaction can accumulate into decisive, multi-kilocalorie preferences that dictate which face of a molecule reacts.

Origins · 1 minDerek Harold Richard Barton and how this was discovered
DH
Derek Harold Richard Barton
1918–1998 · Conformational analysis and steroid/terpenoid stereochemistry, Imperial College London

Barton's 1950 paper "The Conformation of the Steroid Nucleus" is often cited as the founding document of modern conformational analysis; in it he showed that a steroid's reactivity — rates of esterification, elimination, and reduction — could be rationalized entirely from whether reacting groups sat axial or equatorial on a cyclohexane-like ring, a preference itself dictated by exactly the steric (1,3-diaxial, gauche-type) strain accounting developed for simple alkanes.

History
- 1874 — van 't Hoff and Le Bel propose the tetrahedral carbon, the geometric prerequisite for any conformational (dihedral-angle) analysis.
- 1930s — Pitzer's early quantum-statistical treatments of ethane's rotational barrier establish that a rotational energy barrier exists and must be included in thermodynamic calculations of alkanes.
- 1936–1943 — Odd Hassel uses electron diffraction to determine the actual (chair) shape of cyclohexane and the relative orientations of substituents, laying the structural groundwork.
- 1950 — Derek Barton publishes "The Conformation of the Steroid Nucleus," linking axial/equatorial (steric) preferences directly to chemical reactivity.
- 1969 — Barton and Hassel share the Nobel Prize in Chemistry "for their contributions to the development of the concept of conformation and its application in chemistry."
What exactly is "steric strain," in one sentence?

Steric strain is the rise in energy that occurs when two non-bonded atoms or groups are pushed closer together than the sum of their van der Waals radii, so that their filled electron clouds begin to overlap and Pauli (exchange) repulsion dominates over any attractive dispersion force; it is a purely through-space effect, distinct from bond-eclipsing torsional strain, and is the quantity summed up (using calibration values like the 0.9 kcal/mol gauche-butane interaction) to predict which conformation or configuration of a molecule is most stable.

Why does gauche-butane specifically cost about 0.9 kcal/mol rather than some other number?

The number comes from experiment (electron diffraction, vibrational spectroscopy, and thermodynamic measurements on the gas-phase equilibrium), and it is explained mechanistically because at the gauche dihedral (60°) the two terminal methyl carbons sit roughly 3.1 Å apart, inside their effective van der Waals contact distance (~4.0 Å for two methyls), placing the system on the steep repulsive part of the Lennard-Jones curve; several smaller peripheral hydrogen–hydrogen and hydrogen–carbon contacts between the two methyl groups add further small increments, summing to the observed ~0.9 kcal/mol total.

Is steric strain the same as torsional/eclipsing strain?

No. Torsional strain arises even between tiny substituents (like the hydrogens in eclipsed ethane) purely from poorer hyperconjugative orbital overlap when bonds are eclipsed rather than staggered, and it exists in principle even at very small atomic radii. Steric strain specifically requires substituents to be bulky enough and close enough in space to breach their van der Waals contact distance; it is a genuinely non-bonded, through-space effect. Gauche-butane conveniently isolates steric strain because both compared conformers (anti and gauche) are staggered, so the torsional contribution cancels between them.

How does gauche-interaction counting predict cyclohexane conformer preferences?

When a substituent occupies the axial position on a cyclohexane chair, it develops gauche-type 1,3-diaxial interactions with the axial hydrogens (or substituents) two carbons away on the same face of the ring — geometrically and energetically closely analogous to the methyl-methyl gauche interaction in butane. Equatorial substitution avoids these close 1,3-diaxial contacts. By counting the number of such gauche-type interactions in each chair (typically two 1,3-diaxial interactions per axial substituent) and multiplying by a calibrated per-interaction energy (often close to, though not always identical to, the 0.9 kcal/mol butane value, depending on the substituent), one can predict quantitatively which chair conformer dominates, and by how much, entirely from the same steric-strain logic developed for acyclic butane.

Does temperature change which conformer of butane is most stable?

No — temperature never changes which conformer is lowest in energy (anti remains the global minimum at every temperature, since ΔG∘\Delta G^{\circ} for the anti-gauche gap is essentially temperature-independent over normal ranges), but temperature does change the relative populations of the conformers via the Boltzmann factor. At absolute zero, essentially all molecules sit in the anti well; as temperature rises, thermal energy increasingly populates the higher-energy gauche wells, asymptotically approaching a purely statistical 1:2 (anti:total-gauche, by well-count) ratio in the infinite-temperature limit, regardless of how large ΔG∘\Delta G^{\circ} actually is.

Why do force fields use an r⁻¹² repulsive term instead of something derived from quantum mechanics?

The true short-range repulsion from Pauli exclusion is more accurately described by an exponential function of distance (as in the Buckingham or Morse-type potentials used in more sophisticated force fields), which better matches quantum-chemical calculations of overlap-driven exchange repulsion. The r−12r^{-12} form in the Lennard-Jones potential is chosen mainly for computational convenience — it is simply the square of the r−6r^{-6} attractive term, making the potential and its derivatives cheap to evaluate for millions of atom pairs in a molecular simulation — and it reproduces the qualitative shape (steep repulsive wall, shallow attractive well) well enough for most conformational-energy purposes, even though it is not itself derived rigorously from first principles.

Can a gauche arrangement ever be more stable than anti?

Yes, when the substituents are not simple alkyl groups but carry strong electronic (hyperconjugative, electrostatic, or lone-pair) preferences that favor a 60° dihedral, overriding the ordinary steric penalty. The classic case is 1,2-difluoroethane and related β-fluoro, β-alkoxy, and β-amino systems, where a favorable σC−H→σC−X∗\sigma_{C-H} \to \sigma^{*}_{C-X} hyperconjugative donation (best aligned at gauche dihedral angles) combined with the relatively small van der Waals radius of fluorine makes the gauche conformer the global minimum — a phenomenon known specifically as the "gauche effect," distinct from and in some sense opposite to the purely steric gauche penalty seen in butane.

Before this

Where this leads