Radial Distribution Functions

Ask where the electron in a hydrogen atom actually is. The honest answer is a probability cloud. But clouds can still be measured, plotted, and compared. The radial distribution function P(r)=r2R2(r)P(r) = r^2R^2(r) turns the abstract radial wavefunction into a concrete, testable curve. It is a graph of "how much electron density lives at distance rr from the nucleus." This is summed over all directions. This single function explains why the 1s electron in hydrogen is most likely found at exactly the Bohr radius a0a_0. It also explains why 2s and 3s orbitals develop extra humps and nodes. 2p and 3d orbitals never show these features. And it explains why an electron in a higher shell can still spend real time closer to the nucleus than one in a lower shell. This is the physical seed of penetration and shielding. The core subtlety is that ∣R(r)∣2|R(r)|^2 alone — the radial probability density — is not what you want to plot. Density is largest exactly at the nucleus for every s orbital. This makes it look as though the electron piles up on top of the proton. That is misleading, because density must be weighted by the amount of space available at each radius. Thin shells near r=0r=0 contain almost no volume. The factor r2r^2, inherited from the spherical volume element r2 dr dΩr^2\,dr\,d\Omega, corrects this. It suppresses the region near the nucleus. It produces the honest, integrable probability curve chemists actually use. This article builds P(r)P(r) from the The Radial Equation and Radial Wavefunctions you already have. It shows how to locate radial nodes and the most-probable radius. This is done by straightforward calculus. It also works through the 1s, 2s, and 3p cases numerically. So every claim can be checked by hand. The payoff is a visual and quantitative vocabulary — nodes, humps, penetration. This vocabulary underlies everything from Effective Nuclear Charge and Shielding to the characteristic silhouettes described in Shapes of s, p, and d Orbitals. The big picture: quantum numbers nn and ℓ\ell, introduced in Principal, Angular, and Magnetic Quantum Numbers, are not just labels. They are counting instructions for how many times P(r)P(r) crosses zero. They also dictate how far its main peak sits from the nucleus. Once you can read a radial distribution plot, you can predict orbital energies, ionization trends. You can even predict parts of the periodic table's shape. This is possible without solving a single differential equation from scratch.

Key takeaways
  • P(r)=r2Rnℓ2(r)P(r) = r^2 R_{n\ell}^2(r) is the probability of finding the electron in a thin spherical shell at radius rr, per unit rr.
  • The r2r^2 factor comes from the volume of a spherical shell, 4πr2 dr4\pi r^2\,dr; it is what distinguishes P(r)P(r) from the raw density R2(r)R^2(r).
  • P(r)P(r) is normalized: ∫0∞P(r) dr=1\int_0^\infty P(r)\,dr = 1 for every hydrogen-like orbital.
  • Radial nodes = n−ℓ−1n - \ell - 1: 2s has one, 3s has two, 3p has one, 3d has zero.
  • The most-probable radius for 1s is exactly a0a_0; for higher n,ℓn,\ell it grows roughly as n2n^2, but inner humps let electrons "penetrate" toward the nucleus.
  • Key idea: probability lives in shells, not points — multiply density by shell volume, and the r2r^2 factor reshapes every orbital's radial story.

Where this lives today

Radial distribution functions remain the standard first picture chemists reach for whenever atomic size, shielding, or orbital energy ordering needs explaining. In inorganic and physical chemistry courses and research alike, plots of P(r)P(r) for valence ns, np, and (n−1)d orbitals are used to rationalize the anomalous stability of half-filled and filled subshells, the lanthanide contraction (where poor shielding by 4f electrons, visible as a compact, deeply penetrating radial distribution, pulls in the whole valence shell), and the relativistic contraction of s orbitals in heavy elements like gold and mercury, where relativistic effects further sharpen the inner hump of the 6s radial distribution. In spectroscopy and photoionization physics, the radial matrix elements that govern transition intensities and photoionization cross-sections are integrals over exactly this kind of radial density, weighted by additional powers of rr; the shape of P(r)P(r) — how much density sits at small versus large rr — directly controls how strongly an electron couples to incoming or outgoing radiation. In computational chemistry, radial distribution functions (and their multi-electron analogues obtained from self-consistent-field or density-functional calculations) are routinely plotted to check whether a basis set correctly reproduces core penetration, since basis-set errors near the nucleus can distort computed hyperfine couplings, NMR shielding constants, and core-ionization energies. Materials scientists use closely related radial concepts — atom-centered pair distribution functions from X-ray or neutron scattering — as the experimental, condensed-phase analogue of the same "probability by shell" logic introduced here for a single atom.

Ask the tutor: Can you show me how the radial distribution function for 2s develops its inner hump and node numerically, step by step from the wavefunction?

The physical picture

Start from a wavefunction you already trust: ψnℓm(r,θ,ϕ)=Rnℓ(r) Yℓm(θ,ϕ)\psi_{n\ell m}(r,\theta,\phi) = R_{n\ell}(r)\,Y_\ell^m(\theta,\phi). The full probability density is ∣ψ∣2=Rnℓ2(r) ∣Yℓm∣2|\psi|^2 = R_{n\ell}^2(r)\,|Y_\ell^m|^2, and because the spherical harmonics are themselves normalized over the angular variables, the probability of finding the electron in a differential volume element r2sin⁡θ dr dθ dϕr^2\sin\theta\,dr\,d\theta\,d\phi is ∣ψ∣2|\psi|^2 times that volume element. If you only care about distance from the nucleus — not direction — you integrate away the angles. Since ∫∣Yℓm∣2 dΩ=1\int |Y_\ell^m|^2\,d\Omega = 1, what survives is

P(r) dr=r2Rnℓ2(r) drP(r)\,dr = r^2 R_{n\ell}^2(r)\,dr

This is the probability of finding the electron anywhere in the thin spherical shell between rr and r+drr+dr, regardless of angle. It is a genuinely different object from R2(r)R^2(r): the radial density, which tells you the probability per unit volume at a point, versus P(r)P(r), the probability per unit radius summed over the whole shell. For every hydrogen 1s-type orbital, R2(r)R^2(r) is largest at r=0r=0 — the density is sharply peaked at the nucleus — yet P(r)P(r) vanishes at r=0r=0 because the shell volume 4πr24\pi r^2 vanishes there too. The competition between a decaying exponential (R2∼e−2Zr/na0R^2 \sim e^{-2Zr/na_0}) and a growing polynomial (r2r^2, or higher powers for larger ℓ\ell) is exactly what sculpts the characteristic single- or multi-humped shape of P(r)P(r). Two structural facts follow directly from the mathematical form of Rnℓ(r)R_{n\ell}(r), which contains an associated Laguerre polynomial of degree n−ℓ−1n-\ell-1 multiplied by rℓr^\ell and e−Zr/na0e^{-Zr/na_0}. First, the number of interior zeros of RnℓR_{n\ell} — and hence of P(r)P(r) — equals n−ℓ−1n-\ell-1; these are the radial nodes, spherical shells where the probability is exactly zero. Second, near the origin Rnℓ(r)∼rℓR_{n\ell}(r) \sim r^\ell, so P(r)∼r2ℓ+2P(r) \sim r^{2\ell+2} for small rr: higher angular momentum pushes the density away from the nucleus, while ss orbitals (ℓ=0\ell=0) are the only ones with any density directly at the nucleus itself (though even there P(0)=0P(0)=0 because of the r2r^2 factor — it is R2(0)R^2(0) that is nonzero for s states).

Figure
Density R2(r)R^2(r) versus radial distribution P(r)=r2R2(r)P(r)=r^2R^2(r) for hydrogen 1s
r value a₀ 2a₀ 3a₀ R²(r): density, max at nucleus P(r) = r²R²(r): peak at r = a₀ ●peak (a₀, P_max)

The 2s orbital is the simplest case that shows a radial node, and it is worth visualizing before any algebra, because the node is what distinguishes "an electron that is sometimes far away" from "an electron with genuinely zero probability at one particular radius, and two separated humps of probability on either side."

Figure
Radial distribution P(r)P(r) for hydrogen 2s: one radial node
r / a₀ P(r) 2 4 6 (node) 8 small inner hump dominant outer hump (most-probable r) node: P(r)=0

The small inner hump matters chemically far more than its modest area suggests: it represents the ability of a 2s electron to penetrate underneath the 1s shell and feel a larger effective nuclear charge, part of why 2s lies lower in energy than 2p in multi-electron atoms — the physical seed of Effective Nuclear Charge and Shielding.

The core ideas

The governing definitions and results are compact; each is worth committing to memory alongside its meaning.

P(r)=r2 Rnℓ2(r)P(r) = r^2\,R_{n\ell}^2(r)

where: Rnℓ(r)R_{n\ell}(r) is the (real, normalized) radial wavefunction for quantum numbers n,ℓn,\ell; P(r)P(r) has units of inverse length so that P(r) drP(r)\,dr is a dimensionless probability. Reading: P(r)P(r) answers "if I could measure the electron's distance from the nucleus many times, what histogram would I get?" — it is the physically measurable radial profile.

∫0∞P(r) dr=∫0∞r2Rnℓ2(r) dr=1\int_0^\infty P(r)\,dr = \int_0^\infty r^2 R_{n\ell}^2(r)\,dr = 1

where: the integral runs over all radii from the nucleus to infinity. Reading: this is just the normalization of RnℓR_{n\ell} itself, restated with the r2r^2 weight made explicit — it guarantees P(r)P(r) is a true probability density in rr.

number of radial nodes=n−ℓ−1\text{number of radial nodes} = n - \ell - 1

where: nn is the principal quantum number, ℓ\ell the azimuthal (angular momentum) quantum number. Reading: radial nodes are spheres of zero probability; this count follows purely from the degree of the associated Laguerre polynomial inside RnℓR_{n\ell}, and it is exactly what remains once you subtract the ℓ\ell angular nodes (nodal planes/cones) from the total n−1n-1 nodes of the full orbital.

dPdr∣r=rmp=0,d2Pdr2∣r=rmp<0\left.\frac{dP}{dr}\right|_{r=r_{mp}} = 0, \qquad \left.\frac{d^2P}{dr^2}\right|_{r=r_{mp}} < 0

where: rmpr_{mp} is the most-probable radius, the location of a maximum (not necessarily the global one for multi-humped functions) in P(r)P(r). Reading: standard calculus — differentiate P(r)P(r), set it to zero, discard trivial or minimum roots, and check the sign of the second derivative or simply compare peak heights when several maxima exist.

⟨r⟩=∫0∞r P(r) dr=∫0∞r3Rnℓ2(r) dr\langle r \rangle = \int_0^\infty r\,P(r)\,dr = \int_0^\infty r^3 R_{n\ell}^2(r)\,dr

where: ⟨r⟩\langle r \rangle is the mean radius, an expectation value — generally not equal to rmpr_{mp}, because P(r)P(r) is not symmetric about its peak. Reading: chemists often conflate "most likely distance" and "average distance"; for hydrogen 1s these differ by 50%, a gap you can verify directly.

Derivation AMost-probable radius of the 1s orbital

Goal. Starting from the normalized hydrogen-like 1s radial wavefunction, find the radius at which the radial distribution function P(r)P(r) is maximal, and show it equals a0/Za_0/Z.

Step 1 — write down R1sR_{1s}. The normalized 1s radial function for a one-electron atom of nuclear charge ZZ is

R1s(r)=2(Za0)3/2e−Zr/a0R_{1s}(r) = 2\left(\frac{Z}{a_0}\right)^{3/2} e^{-Zr/a_0}

This satisfies ∫0∞R1s2(r) r2 dr=1\int_0^\infty R_{1s}^2(r)\,r^2\,dr = 1, which you can confirm using the standard integral ∫0∞x2e−2x dx=1/4\int_0^\infty x^2 e^{-2x}\,dx = 1/4 after substituting x=Zr/a0x = Zr/a_0.

Step 2 — build P(r)P(r). Multiply by r2r^2:

P(r)=r2R1s2(r)=4(Za0)3r2e−2Zr/a0P(r) = r^2 R_{1s}^2(r) = 4\left(\frac{Z}{a_0}\right)^3 r^2 e^{-2Zr/a_0}

This is a competition between the growing polynomial r2r^2 and the decaying exponential e−2Zr/a0e^{-2Zr/a_0}; the product must have an interior maximum since it vanishes at both r=0r=0 and r→∞r\to\infty.

Step 3 — differentiate and set to zero. Let k=2Z/a0k = 2Z/a_0 for brevity, so P(r)∝r2e−krP(r) \propto r^2 e^{-kr}. Then

dPdr∝2r e−kr−kr2e−kr=r e−kr(2−kr)\frac{dP}{dr} \propto 2r\,e^{-kr} - k r^2 e^{-kr} = r\,e^{-kr}\left(2 - kr\right)

Setting this to zero gives r=0r=0 (a minimum, since P(0)=0P(0)=0 and PP rises just after) or 2−kr=02-kr=0.

Step 4 — solve for rmpr_{mp}. From 2−kr=02 - kr = 0,

rmp=2k=22Z/a0=a0Zr_{mp} = \frac{2}{k} = \frac{2}{2Z/a_0} = \frac{a_0}{Z}

For hydrogen, Z=1Z=1, giving the celebrated result rmp=a0r_{mp} = a_0: the most probable distance of the electron from the nucleus in the ground state is exactly the Bohr radius. This is a striking piece of consistency between the (structurally naive) Bohr model and the full quantum treatment — the "orbit radius" of the old theory reappears as the peak of a genuine probability distribution, not as a literal trajectory.

Step 5 — confirm it is a maximum. The second derivative of r2e−krr^2 e^{-kr} at r=2/kr=2/k is negative (the function rises from zero, peaks, then falls monotonically toward zero as r→∞r\to\infty, and there is only one nonzero critical point), so rmp=a0/Zr_{mp}=a_0/Z is indeed the unique interior maximum — there are no radial nodes for 1s (n−ℓ−1=1−0−1=0n-\ell-1 = 1-0-1=0), consistent with a single hump.

Go deeper · Derivation B · 1 minMean radius ⟨r⟩\langle r \rangle for 1s, and why it exceeds rmpr_{mp}
Derivation BMean radius ⟨r⟩\langle r \rangle for 1s, and why it exceeds rmpr_{mp}

Goal. Compute ⟨r⟩\langle r \rangle for the 1s orbital directly from P(r)P(r), and show explicitly that the average distance differs from the most-probable distance — a common point of confusion.

Step 1 — set up the integral. Using P(r)=4(Z/a0)3r2e−2Zr/a0P(r) = 4(Z/a_0)^3 r^2 e^{-2Zr/a_0} from the previous derivation,

⟨r⟩=∫0∞r P(r) dr=4(Za0)3∫0∞r3e−2Zr/a0 dr\langle r \rangle = \int_0^\infty r\,P(r)\,dr = 4\left(\frac{Z}{a_0}\right)^3 \int_0^\infty r^3 e^{-2Zr/a_0}\,dr

Step 2 — apply the standard Gamma-function integral. Using ∫0∞xne−αx dx=n!/αn+1\int_0^\infty x^n e^{-\alpha x}\,dx = n!/\alpha^{n+1} with n=3n=3 and α=2Z/a0\alpha = 2Z/a_0,

∫0∞r3e−2Zr/a0 dr=3!(2Z/a0)4=6 a0416 Z4=3 a048 Z4\int_0^\infty r^3 e^{-2Zr/a_0}\,dr = \frac{3!}{(2Z/a_0)^4} = \frac{6\,a_0^4}{16\,Z^4} = \frac{3\,a_0^4}{8\,Z^4}

Step 3 — combine.

⟨r⟩=4(Za0)3⋅3 a048 Z4=12 a08 Z=32⋅a0Z\langle r \rangle = 4\left(\frac{Z}{a_0}\right)^3 \cdot \frac{3\,a_0^4}{8\,Z^4} = \frac{12\,a_0}{8\,Z} = \frac{3}{2}\cdot\frac{a_0}{Z}

Step 4 — compare to rmpr_{mp}. Since rmp=a0/Zr_{mp} = a_0/Z (Step 4 of the first derivation), the ratio is

⟨r⟩rmp=3/21=1.5\frac{\langle r \rangle}{r_{mp}} = \frac{3/2}{1} = 1.5

The mean radius is 50% larger than the most-probable radius. This is not a paradox: P(r)P(r) has a long exponential tail toward large rr, which drags the mean — an integral weighted equally over the whole tail — well past the peak. It is the same asymmetric-distribution effect familiar from any right-skewed histogram in statistics, and it is the reason chemists must specify which "size of the atom" they mean.

Step 5 — limiting-case check. As Z→∞Z\to\infty (a very highly charged nucleus, e.g. a hydrogen-like ion such as Fe25+^{25+}), both rmp=a0/Zr_{mp}=a_0/Z and ⟨r⟩=1.5 a0/Z\langle r\rangle = 1.5\,a_0/Z shrink toward zero, and their ratio stays fixed at exactly 1.51.5 regardless of ZZ — the shape of P(r)P(r) is universal for all hydrogen-like 1s orbitals; only its overall length scale changes with ZZ.

Worked examples

Example 1 — Foundational: locating the most-probable radius and node count for hydrogen 3p. The normalized 3p radial function (with Z=1Z=1, hydrogen, in units where ρ=r/a0\rho = r/a_0) is

R3p(r)=42813(1a0)3/2(6−ρ)ρ e−ρ/3,ρ=ra0R_{3p}(r) = \frac{4\sqrt{2}}{81\sqrt{3}}\left(\frac{1}{a_0}\right)^{3/2}\left(6 - \rho\right)\rho\, e^{-\rho/3}, \qquad \rho = \frac{r}{a_0}

First, count radial nodes using n−ℓ−1=3−1−1=1n-\ell-1 = 3-1-1=1: there should be exactly one radial node, and indeed the factor (6−ρ)(6-\rho) vanishes once, at ρ=6\rho = 6, i.e. r=6a0r = 6a_0. Everything between r=0r=0 and r=6a0r=6a_0 is one sign of R3pR_{3p}; everything beyond is the opposite sign (irrelevant once squared, but it confirms the node is a genuine sign change, not just a flattening). To build P(r)P(r), square and multiply by r2=a02ρ2r^2 = a_0^2\rho^2:

P(r) dr∝ρ2⋅(6−ρ)2ρ2 e−2ρ/3 dρ=ρ4(6−ρ)2e−2ρ/3 dρP(r)\,dr \propto \rho^2 \cdot (6-\rho)^2 \rho^2\, e^{-2\rho/3}\,d\rho = \rho^4(6-\rho)^2 e^{-2\rho/3}\,d\rho

This function is zero at ρ=0\rho=0 (fourth-order contact — very strongly suppressed near the nucleus, consistent with P(r)∼r2ℓ+2=r4P(r)\sim r^{2\ell+2}=r^4 for ℓ=1\ell=1), zero again at ρ=6\rho=6 (the radial node), and must therefore have (at least) two humps: a smaller inner one between 00 and 66, and a larger outer one beyond 66. Differentiating f(ρ)=ρ4(6−ρ)2e−2ρ/3f(\rho) = \rho^4(6-\rho)^2 e^{-2\rho/3} and setting f′(ρ)=0f'(\rho)=0 leads to a quartic in ρ\rho after factoring out e−2ρ/3e^{-2\rho/3} and ρ3(6−ρ)\rho^3(6-\rho) (common factors giving trivial roots at ρ=0,6\rho=0,6):

4(6−ρ)−2ρ−23ρ(6−ρ)=04(6-\rho) - 2\rho - \frac{2}{3}\rho(6-\rho) = 0

Expanding: 24−4ρ−2ρ−23(6ρ−ρ2)=0⇒24−6ρ−4ρ+23ρ2=024 - 4\rho - 2\rho - \frac{2}{3}(6\rho - \rho^2) = 0 \Rightarrow 24 - 6\rho - 4\rho + \frac{2}{3}\rho^2 = 0, i.e.

23ρ2−10ρ+24=0⟹ρ2−15ρ+36=0\frac{2}{3}\rho^2 - 10\rho + 24 = 0 \quad\Longrightarrow\quad \rho^2 - 15\rho + 36 = 0

Solving the quadratic:

ρ=15±225−1442=15±92\rho = \frac{15 \pm \sqrt{225 - 144}}{2} = \frac{15 \pm 9}{2}

giving ρ=3\rho = 3 or ρ=12\rho = 12. The root ρ=3\rho=3 lies inside the node (0<3<60<3<6) and is the smaller, inner-hump maximum; ρ=12\rho=12 lies beyond the node and is the dominant outer-hump maximum, the conventionally quoted "most-probable radius" of 3p, rmp≈12 a0r_{mp} \approx 12\,a_0. (Comparing f(3)f(3) and f(12)f(12) numerically confirms the outer peak is the taller of the two, as expected since the outer lobe of an n=3n=3 orbital carries most of the probability.)

Example 2 — Applied: penetration and the 2s/2p energy split in lithium. In hydrogen, all orbitals with the same nn are degenerate — 2s and 2p have identical energy. In real multi-electron atoms like lithium (Z=3, configuration 1s22s11s^2 2s^1), they are not, and radial distribution functions explain why. Compare the radial distribution functions (using hydrogen-like shapes as a first approximation, with an effective charge) for 2s and 2p:

P2s(r)∝(2−ρ)2ρ2e−ρ,P2p(r)∝ρ4e−ρ,ρ=Zr/a0P_{2s}(r) \propto (2-\rho)^2 \rho^2 e^{-\rho}, \qquad P_{2p}(r) \propto \rho^4 e^{-\rho}, \qquad \rho = Zr/a_0

The 2s function has a node at ρ=2\rho=2 and a small inner hump for 0<ρ<20<\rho<2 — probability density that sits inside the 1s core, where the two 1s electrons only partially cancel the nuclear charge. That inner hump means a 2s electron spends part of its time much closer to the +3 nucleus than a 2p electron ever does, since P2p∝ρ4P_{2p}\propto \rho^4 vanishes to fourth order at the origin and has no separate inner hump at all — it must build up smoothly from zero with no chance to poke through the core. Because the 2s electron partially penetrates the 1s shielding cloud, it feels a larger effective nuclear charge on average and is therefore more tightly bound (lower in energy) than the 2p electron, even though both have n=2n=2. This is precisely why the lithium ground-state configuration is 1s2 2s11s^2\,2s^1 rather than 1s2 2p11s^2\,2p^1, and it generalizes into the familiar ns<np<nd<nfns < np < nd < nf energy ordering within a shell for many-electron atoms — the qualitative content of Effective Nuclear Charge and Shielding, derived here purely from the shapes of P(r)P(r).

Example 3 — Competition-level: mean radius of a general hydrogen-like orbital, and a numerical check for n=4,ℓ=2n=4,\ell=2 (4d). A standard closed-form result (derivable via the same Gamma-function machinery as above, using the full associated-Laguerre normalization) gives the general expectation value

⟨r⟩nℓ=a0Z[3n2−ℓ(ℓ+1)2]\langle r \rangle_{n\ell} = \frac{a_0}{Z}\left[\frac{3n^2 - \ell(\ell+1)}{2}\right]

Apply this to n=4,ℓ=2n=4,\ell=2 (a 4d orbital) in a hydrogen-like ion with Z=3Z=3 (doubly-ionized... actually take Li2+\text{Li}^{2+}, a genuine one-electron ion with Z=3Z=3, so the formula applies exactly, no shielding approximations needed):

⟨r⟩4,2=a03[3(16)−2(3)2]=a03[48−62]=a03⋅21=7 a0\langle r \rangle_{4,2} = \frac{a_0}{3}\left[\frac{3(16) - 2(3)}{2}\right] = \frac{a_0}{3}\left[\frac{48-6}{2}\right] = \frac{a_0}{3}\cdot 21 = 7\,a_0

Now find the number of radial nodes and estimate whether the outermost peak of P(r)P(r) lies near this mean. Radial nodes: n−ℓ−1=4−2−1=1n-\ell-1 = 4-2-1=1, so 4d has exactly one radial node — one inner hump, one dominant outer hump. Because there is only a single subordinate inner hump (not two, as there would be for 4s with n−ℓ−1=3n-\ell-1=3 nodes), the mean ⟨r⟩=7a0\langle r\rangle = 7a_0 should lie reasonably close to, but somewhat larger than, the outer peak rmpr_{mp} — exactly the same qualitative skew seen for 1s (where ⟨r⟩/rmp=1.5\langle r\rangle/r_{mp}=1.5), just less pronounced because higher-ℓ\ell orbitals for a given nn have radial distributions concentrated in a narrower band (less inner-hump probability to skew the mean). As a limiting-case sanity check, set ℓ=n−1\ell = n-1 (the maximum possible angular momentum for given nn — no radial nodes at all, a single clean hump, e.g. 1s, 2p, 3d, 4f). Then

⟨r⟩n,n−1=a0Z[3n2−(n−1)n2]=a0Z[n(3n−(n−1))2]=a0Z⋅n(2n+1)2\langle r \rangle_{n,n-1} = \frac{a_0}{Z}\left[\frac{3n^2 - (n-1)n}{2}\right] = \frac{a_0}{Z}\left[\frac{n(3n-(n-1))}{2}\right] = \frac{a_0}{Z}\cdot\frac{n(2n+1)}{2}

For n=1,ℓ=0n=1,\ell=0 this gives ⟨r⟩=a0Z⋅1⋅32=32a0Z\langle r\rangle = \dfrac{a_0}{Z}\cdot\dfrac{1\cdot 3}{2} = \dfrac{3}{2}\dfrac{a_0}{Z} — exactly the 1s result derived above by direct integration, confirming the general formula reduces correctly to the special case already checked independently.

Limiting cases, scope & common traps

Regime / questionWhat happens to P(r)P(r)Why
r→0r \to 0 (any orbital)P(r)→0P(r) \to 0 always, even though R2(r)R^2(r) may be large (s states)the r2r^2 (or r2ℓ+2r^{2\ell+2}) factor kills the shell volume at the origin
ℓ=n−1\ell = n-1 (max angular momentum for given nn)zero radial nodes, single clean hump, peak near n2a0/Zn^2 a_0/ZLaguerre polynomial degree n−ℓ−1=0n-\ell-1=0
Fixed nn, increasing ℓ\ellouter peak position roughly similar, but inner humps disappearhigher ℓ\ell suppresses density near nucleus more strongly (r2ℓ+2r^{2\ell+2})
Z→∞Z \to \inftyentire P(r)P(r) shrinks in scale as 1/Z1/Z, shape (ratios like ⟨r⟩/rmp\langle r\rangle/r_{mp}) unchangeda0/Za_0/Z sets the only length scale in a hydrogen-like problem
Comparing rmpr_{mp} vs ⟨r⟩\langle r \rangle⟨r⟩>rmp\langle r\rangle > r_{mp} always, by a factor that shrinks as ℓ→n−1\ell\to n-1exponential tail skews the mean; skew is largest for s states
Multi-electron atomstrue P(r)P(r) is not hydrogen-like; nodes persist qualitatively but energies split by ℓ\ellelectron-electron repulsion and penetration break the nn-only degeneracy

The chemist behind it

The radial distribution function as a chemically usable object emerged from the marriage of Erwin Schrödinger's wave mechanics with the practical need, pressed hardest by chemists and spectroscopists, to translate abstract ψ\psi functions into pictures of "where the electron is." Schrödinger himself, in his 1926 papers solving the hydrogen atom, obtained the radial functions Rnℓ(r)R_{n\ell}(r) directly; it was the broader community of atomic physicists and chemists — including Linus Pauling and E. Bright Wilson, whose 1935 textbook Introduction to Quantum Mechanics with Applications to Chemistry popularized plots of r2R2r^2R^2 for exactly the pedagogical reasons developed here — who established the radial distribution plot as the standard chemist's window into atomic structure.

Origins · 1 minErwin Schrödinger and how this was discovered
ES
Erwin Schrödinger
1887–1961 · Vienna and Zurich, 1926

Schrödinger derived the wave equation bearing his name in early 1926 and, within months, applied it to the hydrogen atom, obtaining radial functions built from associated Laguerre polynomials — the same functions whose square, weighted by r2r^2, gives every radial distribution plot in this article. He shared the 1933 Nobel Prize in Physics with Paul Dirac. Schrödinger's own preference was for a continuous, wave-mechanical picture of the electron as literally a smeared-out charge density ∣ψ∣2|\psi|^2; the probabilistic (Born) interpretation that underlies the "probability of finding the electron in a shell" language used throughout this topic was in fact due to Max Born, and Schrödinger himself never fully embraced it, favoring instead his original charge-density reading of ψ\psi.

History
1913
— Niels Bohr's model assigns hydrogen's ground state a fixed orbital radius a0a_0, with no probabilistic content.
1926
— Erwin Schrödinger solves the hydrogen atom via wave mechanics, producing Rnℓ(r)R_{n\ell}(r) and recovering a0a_0 as the most-probable radius of 1s, not a literal orbit.
1926
— Max Born proposes the probabilistic interpretation of ∣ψ∣2|\psi|^2, giving physical meaning to R2(r)R^2(r) and, by extension, to P(r)=r2R2(r)P(r)=r^2R^2(r).
1935
— Linus Pauling and E. Bright Wilson's textbook presents radial distribution plots as a standard pedagogical and research tool for visualizing atomic electron distributions.
1960
s onward — Radial distribution functions become a routine diagnostic in computational and inorganic chemistry for rationalizing shielding, penetration, and periodic trends.
What is the difference between R(r)R(r), R2(r)R^2(r), and P(r)P(r)?

R(r)R(r) is the radial wavefunction itself, obtained by solving the The Radial Equation and Radial Wavefunctions; it can be positive, negative, or zero, and by itself has no direct probabilistic meaning. R2(r)R^2(r) is the radial probability density — the probability per unit volume at a given point, largest at the nucleus for every s orbital. P(r)=r2R2(r)P(r)=r^2R^2(r) is the radial probability distribution — the probability per unit radius, obtained by multiplying the density by the volume 4πr24\pi r^2 of the spherical shell (dropping the constant 4π4\pi, which is absorbed into normalization). P(r)P(r) is the function chemists actually plot and interpret, because it correctly accounts for the fact that shells at larger rr contain far more volume than shells near the nucleus.

Why does the most-probable radius for hydrogen 1s equal exactly the Bohr radius a0a_0?

This is a genuine, if somewhat coincidental-looking, agreement between the old Bohr model and full quantum mechanics. Bohr's 1913 model assumed the electron travels on a fixed circular orbit of radius a0a_0 with no uncertainty at all. Schrödinger's 1926 solution replaces that orbit with a spread-out probability cloud described by P(r)P(r), and when you maximize P(r)P(r) for the ground state, the peak lands exactly at r=a0r=a_0. The agreement is a special feature of the 1s state's particular exponential form, not a deep necessity — for other orbitals, the most-probable radius is not simply n2a0n^2a_0 but is shifted by the shape of the polynomial factor multiplying the exponential.

Do radial nodes mean the electron can never be exactly at that radius?

Yes, in the sense that the probability of finding the electron in an infinitesimally thin shell exactly at the node radius is precisely zero, just as it is exactly zero at r=0r=0 for any orbital. This does not mean the electron is somehow prohibited from crossing that radius over time — quantum particles do not follow continuous classical trajectories that would need to "cross" anything. It only means that if you performed a measurement of position, obtaining a value at exactly the nodal radius has zero probability, exactly analogous to how a plucked guitar string has points (nodes) that never move even though the string vibrates continuously on either side.

How does the radial distribution function relate to atomic size trends down a group or across a period?

Down a group, adding shells shifts the outermost hump of P(r)P(r) to progressively larger rr, roughly tracking the n2n^2 scaling visible in rmp∼n2a0/Zeffr_{mp}\sim n^2 a_0/Z_{\text{eff}}, which is why atomic radius generally increases down a group. Across a period, nn stays fixed but nuclear charge ZZ increases faster than shielding compensates, so the effective ZZ felt by valence electrons rises and the outer hump of P(r)P(r) contracts inward — the radial-distribution picture behind the general decrease in atomic radius across a period, refined further once effective nuclear charge is treated quantitatively in Effective Nuclear Charge and Shielding.

Why do chemists care about the small inner hump of an ns orbital's radial distribution rather than just its dominant outer peak?

The dominant outer hump contains most of the probability and sets the overall "size" of the orbital, but the small inner hump is what determines penetration — the degree to which an electron can slip past inner-shell electrons and feel more of the bare nuclear charge. Even though it holds a small fraction of the total probability, that inner hump lowers the energy of ns relative to np and nd within the same shell, which is the entire origin of subshell energy splitting in multi-electron atoms and, ultimately, of the block structure (s, p, d, f) of the periodic table.

Is the radial distribution function the same as an experimentally observable quantity?

Not directly as a single-atom curve — you cannot point an instrument at one hydrogen atom and trace out P(r)P(r) in real time — but its consequences are measurable in aggregate. Electron diffraction, X-ray scattering, and spectroscopic transition intensities all depend on integrals over the same underlying radial density, and pair distribution function analysis in condensed-matter and materials science is a direct experimental analogue: it measures the probability of finding one atom at distance rr from another, built from exactly the same "count probability by shell" logic used here for an electron around a nucleus.

Does the radial distribution function change if you use a different atomic orbital basis set in a calculation?

The exact hydrogen-like P(r)P(r) is fixed by the analytic solution and does not depend on any computational choices. For multi-electron atoms, however, where exact radial wavefunctions are not available, the shape of a computed P(r)P(r) can depend noticeably on the basis set or numerical method used, particularly near the nucleus (core region) where the true wavefunction has a cusp. Poorly chosen basis sets can smear out or misplace radial nodes and the inner penetration hump, which is why properties sensitive to the electron density at short range — hyperfine coupling constants, NMR shielding, core-level binding energies — are especially demanding tests of basis-set quality.

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