Walsh Diagrams and Molecular Shape
Why is water bent at 104.5° while beryllium hydride is perfectly linear? Both are simple AH₂ molecules. Both are built from an s/p-block central atom and two hydrogens. The answer cannot come from counting valence electrons alone. BeH₂ and H₂O have different electron counts. But CH₂ and NH₂⁺ both have six valence electrons. Yet one is bent and the other is linear-ish. The real puzzle is why CH₂ itself switches between bent and linear character. This depends on its electronic state. The tool that resolves all of this in one picture is the Walsh diagram. It is a plot of molecular orbital energies as a continuous function of a bending or bond angle. It is built by watching how each MO of the linear (or planar) geometry deforms as the molecule bends. Walsh diagrams matter because they convert a qualitative slogan into a quantitative orbital argument. The slogan is "count the electrons, apply VSEPR." The argument is grounded in symmetry-adapted linear combinations of atomic orbitals. This is the same machinery used to build Molecular Orbitals of Polyatomic Molecules. Instead of memorizing shapes, you track how each orbital's energy responds to bending. Bending mixes and re-hybridizes the central atom's s and p orbitals differently. This stabilizes some MOs and destabilizes others. The molecule then adopts whatever angle minimizes the sum of occupied orbital energies. This is Walsh's rule in its purest form. It is the first genuinely predictive geometry rule that comes directly out of MO theory. It does not come from electron-pair repulsion bookkeeping. The big picture is a single correlation diagram. It spans bond angle from 90° to 180° (for AH₂). Or it spans pyramidalization angle (for AH₃). Each orbital is drawn as a curve. Its slope encodes whether that orbital favors bending or favors linearity/planarity. Walsh diagrams were originally built from qualitative perturbation-theoretic arguments about orbital overlap. They have since been validated by decades of ab initio calculations. These calculations cover ground and excited states of AH₂ and AH₃ radicals, cations, and anions. They remain a staple of physical organic and inorganic reasoning. They help predict whether a carbene is a singlet or triplet. They explain why NH₃ is pyramidal but BH₃ is planar. They explain why photoexcitation can straighten or bend a molecule. This article builds the Walsh diagrams for AH₂ and AH₃ from scratch. It starts from the symmetry-adapted MOs of the linear and planar reference geometries. It derives the orbital-correlation rules using second-order perturbation theory in the bending angle. It then applies Walsh's rule to predict and rationalize the shapes of BeH₂, CH₂, NH₂, H₂O, BH₃, CH₃, NH₃, and their ions.
- A Walsh diagram plots MO energies of an AHₙ molecule as a continuous function of bond angle, linear/planar (0) to bent/pyramidal.
- Bending mixes central-atom s and p character into orbitals that were pure s or pure p at the high-symmetry geometry, via second-order vibronic coupling.
- Walsh's rule: the equilibrium shape is whichever angle minimizes the sum of one-electron orbital energies of all occupied MOs.
- For AH₂: 1σg, 1σu, 2σg stay low in energy; the key orbital is 1πu, which splits into b₁ (stays flat) and a₁ (drops steeply on bending) — occupying a₁ favors bending.
- For AH₃: the degenerate e′ set (planar) splits into a₁ + e (pyramidal); filling the a₁ level favors pyramidalization, matching NH₃ over BH₃.
- Key idea: molecular shape is decided by which frontier orbital is occupied — draw the correlation diagram, drop in the electrons, and read off the angle that minimizes total orbital energy.
Where this lives today
Walsh diagrams remain the fastest qualitative route to predicting whether a reactive intermediate is bent or linear, planar or pyramidal — a question that matters enormously in mechanistic organic and organometallic chemistry. Carbene chemistry leans directly on the CH₂ Walsh analysis: whether a carbene reacts as a singlet (concerted, stereospecific cyclopropanation via the filled -like lone pair acting as both nucleophile and, through the empty -like p orbital, electrophile) or as a triplet (stepwise, radical-like, non-stereospecific) is controlled by the same singlet–triplet gap that the Walsh diagram rationalizes, and synthetic chemists routinely tune substituents to stabilize one spin state over the other for exactly this reason (electronegative substituents like halogens stabilize the filled -derived lone pair and favor singlet carbenes, as seen in :CCl₂ and :CF₂). The same logic underlies why silylenes (:SiH₂ and its substituted analogs) are almost universally ground-state singlets, in contrast to :CH₂'s triplet ground state — silicon's larger 3s–3p energy gap shifts the relative stabilization of the Walsh orbitals. In main-group and organometallic chemistry, the AH₃ pyramidalization diagram directly explains the geometry and reactivity of amine versus borane fragments used as ligands: NH₃'s pyramidal, lone-pair-bearing nitrogen makes it an excellent σ-donor ligand for Lewis acids and transition metals, while BH₃'s planarity (and consequent empty p orbital) makes it the archetypal Lewis acid, forming adducts like H₃N–BH₃ whose stability is a textbook example of donor–acceptor bonding built from exactly the frontier orbitals the Walsh diagram identifies. Phosphine (PH₃) and its heavier congeners follow the same pyramidal pattern with even smaller bond angles, directly relevant to ligand design in homogeneous catalysis, where the "cone angle" and pyramidalization of phosphine ligands around a metal center governs steric and electronic properties central to catalyst tuning. In photochemistry and atmospheric chemistry, Walsh-diagram thinking predicts geometry changes upon electronic excitation or ionization — essential for interpreting UV/vis absorption band shapes (vibrational progressions reveal how much the equilibrium angle shifts between ground and excited state) in species from water photolysis products (OH, forming from H₂O photodissociation) to interstellar and cometary radicals (CH₂, NH₂, and related species detected by rotational and electronic spectroscopy in astrochemical environments). The same framework extends, with appropriate generalization to more atoms and more symmetry elements, to understanding pseudorotation and geometry preferences in larger main-group clusters, and its logical descendant — full ab initio potential energy surfaces correlated with orbital symmetry — underlies modern computational predictions of reactive intermediate geometries used throughout mechanistic organic chemistry and computational catalyst design. Understanding Walsh diagrams also deepens appreciation of the symmetry-adapted linear combination machinery central to Molecular Orbitals of Polyatomic Molecules, and connects naturally to the vibronic coupling ideas used in treating the Jahn-Teller Effect and to frontier-orbital arguments used throughout Woodward-Hoffmann Rules for pericyclic reactions.
Ask the tutor: How would the Walsh diagram change for an AH₂ molecule where A is a heavier atom with a much larger ns–np energy gap, like SiH₂ compared to CH₂?
The physical picture — thorough prose
Consider a generic AH₂ molecule, H–A–H, and parametrize its geometry by the H–A–H bond angle θ, running from 180° (linear, point group D∞h) down to something like 90–100° (bent, point group C2v). At θ = 180°, the central atom A contributes a 2s orbital (σg symmetry), a 2pz orbital along the molecular axis (σu symmetry, taking z as the H–A–H axis), and a degenerate pair of 2px, 2py orbitals perpendicular to that axis (πu symmetry). The two hydrogen 1s orbitals combine into a symmetric SALC (σg symmetry) and an antisymmetric SALC (σu symmetry); they have no component that can match πu, so the πu pair on A remains strictly nonbonding at linear geometry — it simply does not see the hydrogens at all when the molecule is perfectly linear. Four MOs matter for a first-row AH₂ hydride with a light central atom: 1σg (bonding combination of A 2s and the symmetric H SALC), 1σu (bonding combination of A 2pz and the antisymmetric H SALC), the nonbonding 1πu pair (pure A 2px, 2py, doubly degenerate), and 2σg (the antibonding partner of 1σg, mixing A 2s and H SALC out of phase). As θ decreases from 180°, the molecular symmetry drops to C2v, and every degeneracy tied to the linear axis is broken. In C2v (with the molecule kept in the yz-plane and z bisecting the H–A–H angle), the labels become a1, b2, b1, a1 for these same four orbitals in order, and the crucial event is what happens to the formerly degenerate πu pair: the in-plane component (the one that can point toward the hydrogens as the angle closes) becomes a1 and is allowed by symmetry to mix with the A 2s orbital and with the H2 SALC, while the out-of-plane component remains b1 and stays essentially a pure, nonbonding 2p orbital on A throughout the whole bending motion. That single symmetry-driven split is the entire content of the Walsh diagram for AH₂. The b1 orbital, having no in-plane hydrogen partner to mix with, is nearly flat as a function of θ. The 2a1 orbital (the bent-geometry descendant of 1πu's in-plane lobe) drops sharply in energy as θ decreases from 180° toward 90°, because bending allows it to rehybridize with A's 2s character and to develop bonding overlap with both hydrogens simultaneously — geometrically, an sp-like hybrid pointing into the H–A–H bite angle overlaps far better with both H 1s orbitals at 90–104° than a pure unhybridized p orbital does at 180°. Meanwhile 1a1 (built from 1σg) rises gently on bending because the symmetric H2 combination loses some bonding overlap with A's 2s orbital as the H–H distance shrinks and the H 1s lobes begin to repel each other, and 1b2 (from 1σu) also rises somewhat because bending reduces the effective overlap of the antisymmetric hydrogen combination with A's pz-derived orbital. The higher-lying 3a1 (the antibonding partner) falls slightly as θ decreases. All four curves together constitute the classic Walsh AH₂ diagram; its single decisive feature is the steep downward slope of 2a1 with decreasing angle. The analogous story for planar AH₃ (D3h, point group with a threefold axis) versus pyramidal AH₃ (C3v) runs in parallel. At D3h the central atom's valence set is 2s (a1′), the in-plane pair 2px, 2py (e′), and the out-of-plane 2pz (a2″); the three hydrogen 1s orbitals form SALCs of symmetry a1′ + e′. The a1′ hydrogen combination bonds with A's 2s to give 1a1′ (strongly bonding) and 2a1′ (antibonding); the e′ hydrogen combination bonds with A's in-plane 2p pair to give a bonding e′ pair and an antibonding e′* pair; and A's 2pz (a2″) is left with no planar partner, so it is nonbonding in the D3h reference and becomes the LUMO of a closed-shell planar AH₃ system (or the frontier orbital that a radical or anion must occupy). As the molecule pyramidalizes toward C3v, the a2″ orbital drops in energy — it mixes in A 2s character and gains bonding overlap with the hydrogen a1 SALC as the pyramid folds up — while the formerly nonbonding a2″ orbital and one component of the bonding manifold reorganize into the C3v labels 1a1, 1e, 2a1, 2e. The key downward-sloping curve on pyramidalization is again the orbital derived from a2″, now labeled 2a1 in C3v; occupying it drives the molecule toward a pyramidal shape exactly as occupying the bent-favoring 2a1 orbital drives AH₂ toward a bent shape.
The core ideas — the governing equations/relationships
The organizing quantity is the total electronic energy at the one-electron level, written as a sum over occupied MOs:
where: is the energy of MO as a function of bond angle (the Walsh-diagram curve for that orbital), is its occupation number (0, 1, or 2), and the sum runs over all occupied orbitals.
Reading: the equilibrium angle is the value of that minimizes ; since the core-like orbitals change slowly and roughly cancel between different molecules with the same skeleton, the frontier (HOMO) orbital's slope usually decides the answer — this is Walsh's rule. The angle-dependence of each orbital energy is captured, to leading (second) order in the bending distortion, by vibronic perturbation theory. Let be a bending coordinate (proportional to , i.e. at the linear/planar reference geometry) and let be the electronic Hamiltonian at with eigenstates , energies . Expanding the one-electron Hamiltonian in ,
where: the first-order term is the linear vibronic coupling operator and the second-order term contains the direct curvature (geometric) contribution to the orbital energy. Standard non-degenerate perturbation theory applied orbital-by-orbital gives, to second order,
where: the linear term vanishes by symmetry whenever belongs to a nondegenerate irreducible representation at the reference (high-symmetry) geometry — true for in D∞h and for in D3h — the sum over is the vibronic (pseudo-Jahn–Teller-type) mixing term, and the last term is the direct force-constant-like contribution.
Reading: every Walsh curve is, to lowest order, a parabola in the bending coordinate; whether it curves up or down is set by the sign and size of the vibronic coupling matrix element to nearby orbitals of the correct symmetry — this is precisely why the πu-derived 1b1/2a1 split shows one flat and one steep member: only the in-plane member has a nonzero, large coupling matrix element to A's 2s orbital through the bending motion.
Derivations
Goal. Show explicitly, from symmetry and a two-level vibronic model, why one member of the linear molecule's degenerate πu pair stays essentially flat while the other drops steeply in energy as the H–A–H angle closes from 180°.
Step 1 — set up the linear-geometry basis. At θ = 180° (D∞h), take z as the molecular axis. The central atom's relevant valence orbitals are 2s (σg), 2pz (σu), and the degenerate pair 2px, 2py (πu). Place the molecule so that at the bent geometry the two H atoms lie in the yz-plane. Then, of the πu pair, 2py lies in the plane containing both hydrogens as the angle closes (call this component πu,in-plane) and 2px lies perpendicular to that plane (πu,out-of-plane). The hydrogen SALCs are and , both of which lie in the yz-plane by construction and have zero net overlap with 2px at any bond angle by odd/even symmetry perpendicular to the plane.
Step 2 — identify the bending coordinate and its symmetry. The bending motion is described by an angle coordinate that moves both hydrogens symmetrically within the yz-plane; in D∞h, this bending mode transforms as πu (it is the doubly degenerate bending vibration of a linear triatomic, familiar from CO2's ν2 mode). Only the in-plane bending component, transforming as the same in-plane πu partner, has nonzero matrix elements , because the bending distortion literally moves the hydrogens toward or away from the 2py lobe while leaving 2px completely unaffected by an in-plane displacement — the overlap of 2px with any in-plane hydrogen motion is zero by mirror symmetry through the plane at every value of .
Step 3 — write the two-level vibronic Hamiltonian for the in-plane block. Restrict to the two orbitals that can mix as the angle changes: (essentially A 2s + H2 bonding SALC) and (A 2py). Their coupling through bending is linear in by symmetry (bending transforms as πu, and , matching the symmetry of ), so to lowest order
where: is the vibronic coupling constant, nonzero because bending literally rehybridizes 2s and 2py character on A.
Step 4 — diagonalize and expand to second order in Q. The eigenvalues of this 2×2 matrix are
Expanding the square root for small (valid near the linear reference geometry) gives
Since (1σg, the strongly bonding H–A–H combination) lies well below in energy, the denominator , and this second-order term is negative once one tracks which root correlates with which orbital: the upper root, which becomes the bent-molecule 2a1 orbital, is pushed down from as grows, i.e. as the molecule bends further from linear. Concretely, the level that starts as and mixes in bonding character is stabilized quadratically in the bending angle.
Step 5 — contrast with the out-of-plane component. For (A 2px), the coupling matrix element exactly, by the mirror-plane argument in Step 2, and there is no other low-lying orbital of matching symmetry to mix with it either (the H2 antisymmetric SALC also cannot couple to an out-of-plane p orbital by the same mirror argument). Hence has no second-order stabilization and remains essentially flat as increases — this is the surviving b1 (nonbonding) orbital of the bent Walsh diagram.
Conclusion. The degenerate πu pair of the linear molecule splits into a steeply stabilized a1 orbital (built from in-plane p mixing with bonding s character) and a flat, nonbonding b1 orbital (the untouched out-of-plane p orbital) — exactly the two curves drawn in the AH₂ Walsh diagram, and the physical origin of Walsh's rule for AH₂: any electron configuration that occupies the steeply-falling a1 orbital gains energy by bending, while configurations that leave it empty (or put the electron only in b1 and lower orbitals) have no driving force to bend and stay linear.
Go deeper · Derivation B · 3 minApplying Walsh's rule to predict AH₂ and AH₃ shapes from electron count
Goal. Turn the correlation diagram into a concrete rule: given the number of valence electrons in an AH₂ or AH₃ species, predict bent vs. linear (or pyramidal vs. planar) and rank multiple species.
Step 1 — order and fill the AH₂ Walsh orbitals by valence electron count. From the diagram, the ordering (at the bent geometry, which is where you should place electrons whenever bending is favorable) is
with and essentially always doubly filled as core/strongly-bonding orbitals in any AH₂ species with at least 4 valence electrons (they correspond to the two A–H bonding pairs). The variable, shape-determining electrons are those beyond the first 4 valence electrons: they populate (bending-favoring) and then (angle-insensitive, nonbonding) in turn, following the aufbau ordering appropriate to the bent geometry once bending has already begun to lower .
Step 2 — count valence electrons for representative species. BeH₂: Be contributes 2 valence electrons, each H contributes 1, total 4. CH₂ (singlet or triplet): C contributes 4, total 6. NH₂ (radical): N contributes 5, total 7. H₂O: O contributes 6, total 8. BH₂⁻: total 6 (isoelectronic with CH₂). NH₂⁺: isoelectronic with CH₂ as well (4+1+1 = 6 for NH2+, since N loses one electron: 5 − 1 + 1 + 1 = wait, recompute carefully below in Step 3.
Step 3 — fill orbitals and read the geometry for each valence count. For 4 valence electrons (BeH₂, BH₂⁺): both electrons pairs go into and only; and are empty. Since the bending-favoring orbital is unoccupied, there is no electronic driving force to bend, and the repulsive rise of on bending (however small) dominates: the molecule is linear. This matches BeH₂ (linear, D∞h, experimentally confirmed by its lack of a permanent dipole and by its infrared spectrum). For 6 valence electrons (CH₂, NH₂⁺, BH₂⁻): four electrons fill as before, and two more electrons must be placed in the manifold. Two possibilities exist: (i) both electrons pair up in (singlet, strongly bent, since is steeply stabilized by bending) or (ii) one electron in and one in with parallel spins (triplet, by Hund's rule, less bent because only half of the bending-favoring orbital is occupied and the exchange energy of the triplet favors a more open angle where and are closer in energy). This is exactly the CH₂ story: singlet CH₂ is strongly bent (~102°) while triplet CH₂ (its ground state) is bent but at a wider angle (~134°), and NH₂⁺ mirrors this pattern. For 7 valence electrons (NH₂, CH₃ is a different symmetry class — use NH₂ here as AH₂ example, and BeH₂⁻... use NH2): four electrons fill ; three more electrons go: two into (now doubly occupied) and one unpaired electron into . Because is fully occupied and strongly bending-favoring, NH₂ is bent, with an experimental angle of about 103°, intermediate between CH₂ singlet and H₂O. For 8 valence electrons (H₂O, NH₃⁻ not relevant here): four electrons fill ; four more fill (doubly) and (doubly). fully occupied strongly favors bending, and the molecule is bent at 104.5°, one of the best-known bond angles in chemistry.
Step 4 — repeat the logic for AH₃, using the pyramidalization diagram. The planar D3h ordering is (nonbonding p, becomes steeply stabilizing upon pyramidalization) (antibonding). For BH₃ (6 valence electrons: B contributes 3, three H contribute 3), the first 6 electrons exactly fill and (the two bonding sets), leaving the pyramidalization-favoring orbital empty — so there is no electronic drive to pyramidalize, and BH₃ is planar (D3h), as observed. For CH₃ (7 valence electrons: C contributes 4, three H contribute 3), the 7th electron must go into the pyramidalization-favoring orbital (call it once pyramidalized), giving CH₃ a shallow, dynamically inverting pyramidal preference — consistent with its known near-planar but slightly pyramidalizable structure and extremely low inversion barrier. For NH₃ (8 valence electrons: N contributes 5, three H contribute 3), two electrons fully occupy the pyramidalization-favoring orbital, and NH₃ is robustly pyramidal (∠H–N–H ≈ 106.7°), with a real but low (~2000 cm⁻¹) inversion barrier reflecting the modest energy gain from double occupation of that orbital relative to BH₃'s zero occupation.
Conclusion. Walsh's rule reduces to a simple electron-counting recipe once the diagram is built: count valence electrons, fill the correlation-diagram orbitals from the bottom, and read the angle at which the highest-occupied orbital sits at its energy minimum — 4-valence-electron AH₂ species are linear, 6–8-valence-electron AH₂ species are bent with the bend deepening as more electrons enter the steep /1b1 manifold; 6-valence-electron AH₃ is planar, 7–8-valence-electron AH₃ is pyramidal.
Worked examples
Example 1 — Foundational: locating BeH₂ and H₂O on the same Walsh diagram and rationalizing 180° vs. 104.5°. Valence electron count for BeH₂: Be (1s²2s²) contributes 2 valence electrons from 2s; each H contributes 1; total . These 4 electrons fill (2 electrons, the strongly bonding combination of Be 2s + H₂ symmetric SALC) and (2 electrons, Be 2pz + H₂ antisymmetric SALC). Both are bonding, both are already used at 4 electrons, and the shape-determining orbital is empty. Since and both rise slightly upon bending (their bonding overlaps degrade as the H⋯H distance shrinks and as the σg/σu bonding character is disrupted), the total energy is minimized at : BeH₂ is linear. This is confirmed spectroscopically — gas-phase BeH₂ (observed by matrix isolation and high-temperature spectroscopy) shows no permanent dipole moment and IR/Raman patterns consistent with D∞h symmetry, and modern coupled-cluster calculations place its equilibrium angle at 180° to within computational precision. Valence electron count for H₂O: O (2s²2p⁴) contributes 6 valence electrons; each H contributes 1; total . Filling from the bottom: (2), (2), (2), (2) — all four Walsh orbitals doubly occupied. The decisive orbital , which drops steeply with decreasing angle, is fully occupied, contributing strongly to bending. The competing rise of and on bending is smaller in magnitude than the fall of (this asymmetry is what ab initio Walsh-diagram calculations on H₂O consistently show — the curve has by far the largest curvature of the four), so the energy minimum sits well off 180°.
Minimizing this sum places the equilibrium angle at , the experimentally measured H–O–H angle in gaseous water (microwave spectroscopy value: 104.48°). The limiting case check: if the 2 electrons that would occupy were instead removed (as in the hypothetical 6-valence-electron species, isoelectronic with BeH₂-like filling), Walsh's rule predicts a return toward linearity — and this is exactly the trend observed experimentally: BeH₂ (4 e⁻, linear) → CH₂ triplet (6 e⁻, bent ~134°, only partial occupation) → H₂O (8 e⁻, bent 104.5°, full occupation) shows the bond angle closing monotonically as occupation increases from 0 to 2, exactly as the orbital-filling argument demands.
Example 2 — Applied: predicting and explaining the singlet–triplet gap's effect on CH₂'s geometry, and comparing to isoelectronic NH₂⁺. Methylene, CH₂, has 6 valence electrons (C: 4, two H: 1 each). Its ground state is a triplet, ³B₁, with electron configuration (in the bent, C2v labeling) , the two "extra" electrons beyond the BeH₂-like 4-electron core occupying and singly with parallel spins (Hund's rule maximizes exchange stabilization for two electrons in near-degenerate orbitals). Its lowest singlet state, ¹A₁, instead pairs both extra electrons into : configuration . Applying Walsh's rule to each configuration separately: in the triplet, only one electron occupies the steeply bending-favoring orbital, while the other sits in the angle-insensitive ; the net bending force is roughly half what it would be with doubly occupied, so the triplet's equilibrium angle is pulled only modestly away from 180°. In the singlet, both extra electrons occupy , doubling the bending stabilization relative to a single-electron occupation, and the singlet bends much further. Experimental and high-level ab initio values bear this out precisely: triplet CH₂ (³B₁) has an equilibrium bond angle of about 133.8°, while singlet CH₂ (¹A₁) has an equilibrium bond angle of about 102.4° — a difference of roughly 31°, entirely rationalized by whether holds one or two electrons. The singlet–triplet energy gap itself is small (about 9 kcal/mol, or ≈ 3140 cm⁻¹, with the triplet lower), which is why both states are experimentally accessible and both angles have been measured by electronic spectroscopy. Now compare to the isoelectronic cation NH₂⁺ (N contributes 5 valence electrons, loses 1 for the +1 charge, plus 2 H at 1 each: , same valence count as CH₂). Because NH₂⁺ is isoelectronic with CH₂, Walsh's rule predicts the same qualitative behavior: a triplet ground state bent near 180° minus a modest deflection, and a low-lying singlet bent more sharply. Experimentally, ground-state NH₂⁺ is indeed a ³B₁ triplet with a bond angle near 145–150° (somewhat more open than CH₂'s triplet, consistent with nitrogen's higher electronegativity slightly altering the s/p mixing energetics but not the qualitative Walsh-diagram topology), and its excited singlet state is substantially more bent, around 115–120°. The Walsh framework correctly predicts the ordering and direction of the angle change between spin states across an entire isoelectronic series, even though it does not, by itself, pin down the precise numerical angle without a real calculation of the orbital-energy curves.
Example 3 — Exam/competition level: ranking the pyramidalization angle of BH₃, CH₃, NH₃, and predicting the effect of removing an electron from NH₃⁺. Valence electron counts: BH₃ has ; CH₃ has ; NH₃ has ; the radical cation NH₃⁺ has . Using the AH₃ Walsh diagram (planar , correlating to pyramidal ): the first 6 electrons always fill and (the two A–H bonding sets, present in all four species). The decisive orbital is the one descending from — call it at pyramidal geometry. BH₃ has zero electrons in this orbital: no pyramidalization driving force, planar, D3h, confirmed experimentally (BH₃ itself is unstable as a monomer and dimerizes to B₂H₆, but isoelectronic BF₃ and the transient BH₃ fragment observed spectroscopically are both planar). CH₃ has one electron in this orbital (: partial pyramidalization drive, and indeed the methyl radical is known to be very shallowly pyramidal with an extremely low inversion barrier (essentially planar on the vibrationally averaged structure, with an sp² framework only slightly puckered — early Walsh-diagram treatments correctly flagged CH₃ as intermediate). NH₃ has two electrons in this orbital, : full pyramidalization drive, and NH�3 is robustly pyramidal with ∠HNH = 106.7° and an inversion barrier of about 2076 cm⁻¹ (≈ 5.8 kcal/mol), large enough to give a well-defined pyramidal equilibrium structure while still allowing quantum-mechanical tunneling inversion (the basis of the ammonia maser). Now predict NH₃⁺: removing one electron from neutral NH�3's configuration removes it from the highest-occupied, pyramidalization-favoring orbital (ionization from a nonbonding-ish, largely N-lone-pair-derived orbital is energetically the easiest route, consistent with NH3's low first ionization energy of 10.07 eV corresponding almost entirely to lone-pair character). This leaves NH₃⁺ with configuration — the same orbital occupation pattern as neutral CH₃. Walsh's rule therefore predicts NH₃⁺ should be substantially less pyramidal than neutral NH₃, closer to CH₃'s shallow pyramidalization or even nearly planar. This prediction is borne out: photoelectron spectroscopy of NH₃ shows a long vibrational progression in the ν₂ (umbrella) mode upon ionization to NH₃⁺, the classic signature of a large geometry change along that coordinate — direct spectroscopic proof that removing the electron flattens the pyramid substantially, exactly as the correlation diagram demands.
Limiting cases, scope & common traps
| Situation | What Walsh's rule predicts | Caveat / limiting behavior |
|---|---|---|
| AH₂, 4 valence e⁻ (BeH₂, BH₂⁺) | Linear (D∞h) | Holds robustly; no occupied bending orbital |
| AH₂, 6 valence e⁻, triplet (CH₂, NH₂⁺) | Bent, wide angle (~130–150°) | Angle set by Hund's-rule half-filling of 2a1/1b1 |
| AH₂, 6 valence e⁻, singlet (CH₂, SiH₂) | Bent, sharp angle (~90–103°) | Full 2a1 occupation; singlet always more bent than triplet for same skeleton |
| AH₂, 8 valence e⁻ (H₂O, H₂S) | Bent, ~104–109° | Heavier central atoms (H₂S, ∠HSH ≈ 92°) show reduced s/p mixing — Walsh's rule gives correct trend but the diagram's curvature must come from real calculation for absolute angles |
| AH₃, 6 valence e⁻ (BH₃, BF₃) | Planar (D3h) | Robust; no occupied a2″-derived orbital |
| AH₃, 7 valence e⁻ (CH₃) | Weakly pyramidal / near-planar | Small barrier; large-amplitude inversion motion, diagram gives only qualitative direction |
| AH₃, 8 valence e⁻ (NH₃, PH₃) | Pyramidal | PH₃ far more pyramidal (∠HPH ≈ 93.5°) than NH₃ despite same electron count — again a curvature/energetics issue beyond the topological diagram |
| n = ∞ / heavy central atom limit | Diagram topology unchanged | Absolute angle strongly modulated by the energy gap between central-atom ns and np orbitals — larger gap (heavier atom) suppresses s/p mixing and often gives smaller bond angles for the pyramidal/bent case, the opposite of naive electronegativity arguments |
The chemist behind it
Arthur Donald Walsh (1916–1977) was a British physical chemist whose formative work, published as a landmark series of papers in the Journal of the Chemical Society in 1953, laid out correlation diagrams for AH₂, AH₃, AB₂, and other small polyatomics as a function of bond angle. Walsh worked at the time within the tradition of British spectroscopic chemistry — closely tied to the electronic-spectroscopy programs that were mapping out excited states of small radicals and hydrides by UV absorption — and his diagrams were explicitly built to explain why the excited electronic states of molecules like BH₂, CH₂, and NH₂ showed dramatically different rotational constants (hence different equilibrium geometries) from their ground states. He derived the orbital correlations using qualitative LCAO and perturbation arguments long before large-scale ab initio calculations were feasible, and the predictive power of his diagrams — later fully vindicated by configuration-interaction and coupled-cluster calculations across the periodic table — made "Walsh diagram" and "Walsh's rules" permanent fixtures of inorganic and physical-organic pedagogy.
Origins · 1 minArthur Donald Walsh and how this was discovered
Walsh built his correlation diagrams to rationalize the electronic spectra of small hydride radicals and their ions — species observed in flames, discharges, and interstellar and cometary spectra — connecting each electronic transition's rotational structure to a specific predicted change in bond angle. His approach exemplified a broader mid-century style of British spectroscopic chemistry in which qualitative MO correlation arguments, built by hand from symmetry and overlap reasoning, anticipated results that would only later be confirmed by high-level computation.
What exactly is being plotted on the vertical axis of a Walsh diagram?
The vertical axis is one-electron molecular orbital energy, , essentially the negative of an orbital's ionization energy in a Koopmans'-theorem sense, computed (in practice, via ab initio SCF or higher-level calculations) at a series of fixed bond angles while other geometric parameters like bond length are typically held near their optimal value for each angle. Each curve traces one MO, correlated by symmetry across the whole angle range from the linear/planar reference geometry down to the most-bent/most-pyramidal geometry considered. The diagram is not a total-energy potential curve; you must sum the occupied orbital energies (weighted by occupation number) to get an approximate total electronic energy curve, which is the quantity Walsh's rule actually minimizes.
Does Walsh's rule ever fail to predict the correct geometry?
Yes — it is a one-electron, qualitative argument, and it can fail when electron correlation effects, strong configuration mixing, or unusually small orbital-energy gaps make the one-electron picture a poor approximation to the true multi-electron ground state. It also cannot predict quantitative bond angles, only trends and qualitative shape (bent vs. linear, pyramidal vs. planar), and comparisons across different central-atom rows (e.g., H₂O vs. H₂S) require care because the underlying s–p energy gaps and hybridization tendencies change substantially down a group even though the electron count and orbital symmetry labels stay the same.
How does the Walsh diagram relate to VSEPR theory, and which should I trust more?
VSEPR is a fast, electron-pair-repulsion heuristic that gets the right answer for most closed-shell main-group molecules by counting bonding pairs and lone pairs around the central atom. Walsh diagrams are the underlying orbital-based justification, built from actual symmetry-adapted MOs and their angle-dependence, and they succeed in cases VSEPR handles awkwardly — most notably distinguishing singlet from triplet CH₂, or explaining why radical or ionized species (NH₃⁺, CH₃) have geometries intermediate between their neutral closed-shell relatives. For quick predictions on ordinary closed-shell molecules, VSEPR is faster; for radicals, excited states, ions, or any situation where electron count changes by one, the Walsh diagram is the more reliable and more rigorously grounded tool.
Why is the bending mode specifically what couples the σg orbital to the in-plane π orbital?
Group theory requires that the direct product of the bending mode's symmetry species and the ground-state orbital's symmetry species must contain the symmetry of the orbital being mixed into it, for the vibronic coupling matrix element to be nonzero. In linear AH₂ (D∞h), the doubly degenerate bending vibration transforms as πu, and the product exactly matches the symmetry of the in-plane p orbital component, guaranteeing a nonzero coupling matrix element. The out-of-plane p component, by contrast, is orthogonal to the bending displacement in a way that keeps this matrix element exactly zero at every order of the bending coordinate consistent with the molecule's remaining planar symmetry (the mirror plane containing the linear axis and perpendicular to the bending direction).
How do Walsh diagrams handle molecules bigger than AH2 or AH3, like AB2 or larger polyatomics?
The same logic generalizes: build symmetry-adapted MOs at a high-symmetry reference geometry (linear, planar, or otherwise), identify a bending/deformation coordinate and its irreducible representation, and track which orbitals gain stabilization by mixing with nearby-energy orbitals of compatible symmetry as the coordinate is switched on. Walsh's original 1953 papers covered AB2 (e.g., CO2-type) and AH3 explicitly, and later workers extended correlation-diagram methods to ABn systems, five-atom hydrides, and even transition-metal fragment orbitals in organometallic chemistry, though the diagrams become more complex as more coordinates and more orbitals must be tracked simultaneously.
Why does H2S have a much smaller bond angle (92°) than H2O (104.5°) despite identical valence electron count?
Both molecules have 8 valence electrons and identical Walsh-orbital occupation patterns, so the qualitative prediction (bent) is identical, but the quantitative angle depends on how strongly the central atom's ns and np orbitals mix upon bending, which is exactly the vibronic coupling constant from the two-level model. Sulfur's 3s orbital lies much lower in energy relative to its 3p orbitals than oxygen's 2s does relative to its 2p orbitals (the s–p gap grows down a group due to poor radial overlap and increasing core penetration effects), suppressing effective s/p hybridization and reducing the driving force toward wide bond angles; H₂S instead sits close to the "pure p-orbital bonding" limit, which favors a 90° angle, consistent with its measured 92.1°.
Can Walsh diagrams predict inversion barriers quantitatively, like ammonia's famous barrier used in the ammonia maser?
Not on their own — the diagram tells you that NH₃ should be pyramidal (because the pyramidalization-favoring orbital is doubly occupied) and gives a qualitative sense that the barrier should be modest (since only two electrons, not four, occupy that stabilizing orbital, unlike a case with even stronger stabilization), but the actual barrier height (about 2076 cm⁻¹, or roughly 5.8 kcal/mol, for NH₃) requires a full potential-energy-surface calculation including nuclear motion and tunneling, which is a quantitative electronic-structure and vibrational problem beyond the one-electron correlation-diagram picture.