Potential energy

A raised hammer hangs still, a stretched bow sits motionless in the archer's hand, water waits behind a dam — none of these bodies are moving, yet each is a coiled spring of energy, ready to do work the instant it is released. That stored capacity is potential energy: energy a body possesses because of its position, not its motion. At ICSE Class 10 level the syllabus keeps this idea tightly focused on one case — gravitational potential energy, the energy a body gains simply by being raised to a height, given by the compact formula PE=mghPE = mgh. The same chapter also introduces mechanical energy, the sum of a body's kinetic and potential energy, which sets up the conservation-of-energy idea that follows this topic. This article stays inside that syllabus scope: one formula, worked carefully, with the reasoning behind it and the traps that catch students in exams.

The core insight

A body raised through a height hh above a chosen reference level stores gravitational potential energy PE=mghPE = mgh, which converts to kinetic energy as the body falls, keeping their sum — mechanical energy — constant.

The core idea

Potential energy (PE) is energy stored in a body by virtue of its position (relative to a reference level) or its state (compressed, stretched). ICSE Class 10 restricts the quantitative treatment to one form only: gravitational PE, the energy a raised body holds because of its height.

  • Raising a body of mass mm through a height hh requires doing work against gravity. That work does not disappear — it is stored in the body as potential energy, which it can later give back.
  • The stored energy equals the work done in the lift, W=mghW = mgh, so the formula for gravitational potential energy follows directly:
PE=mghPE = mgh

where: mm is the mass of the body (kg), gg is the acceleration due to gravity (9.8 m/s29.8\ \text{m/s}^2), hh is the height above the chosen reference level (m), and PEPE comes out in joules (J), the SI unit of all forms of energy.

  • PE is never an absolute number — it is always measured relative to a reference level that you choose (the floor, a table top, the lowest point of a swing). Move the reference and every PE value shifts by a constant; only changes in PE usually carry physical meaning.
  • PE is zero at the reference level and grows with height above it. A body below the reference level (in a pit, say) has negative PE relative to that level — a subtlety worth knowing even though ICSE problems rarely test it directly.
  • Mechanical energy ties potential energy to the earlier idea of kinetic energy: Emech=KE+PEE_{mech} = KE + PE. Ignoring friction and air resistance, mechanical energy stays constant even while KE and PE trade places — the falling hammer loses PE and gains an equal amount of KE.

Other forms of energy — chemical, heat, electrical, nuclear, sound, light, solar, wind, hydro, geothermal — appear in this ICSE chapter only qualitatively, through familiar conversions (chemical energy in fuel becoming heat and light in a flame; electrical energy becoming light in a bulb). Gravitational PE remains the only form given a formula at this level, which is exactly why it deserves careful, formula-level practice.

Figure
A hammer at three heights above a nail showing potential energy converting to kinetic energy as it falls
PE falls, KE rises — their sum stays constant reference level (ground) PE high, KE zero h = 5 m PE and KE both present h = 2.5 m PE zero, KE high h = 0 m
Derivation ADeriving PE = mgh from the work done against gravity

Show that lifting a body of mass mm at constant (very slow) speed through a vertical height hh requires work equal to mghmgh, and that this work is exactly the gravitational potential energy stored in the body relative to its starting level — the reasoning that justifies the formula used throughout this chapter.

Step 1. To raise the body without accelerating it, an external force must balance gravity at every instant. The weight of the body pulling it down is F=mgF = mg, so the lifting force needed is also F=mgF = mg, applied straight upward.

Step 2. Work done by a constant force moving a body through a distance in the direction of the force is W=F×dW = F \times d. Here the force is mgmg and the distance moved is the height hh, so:

W=mg×h=mghW = mg \times h = mgh

Step 3. This work does not vanish — no kinetic energy was produced (the body moved at constant, near-zero speed throughout), and no heat was generated (no friction is assumed). By the principle of conservation of energy, the work put in must be stored somewhere: it is stored in the raised body as gravitational potential energy relative to its starting level.

Step 4. Therefore the potential energy of the body at height hh equals the work done to raise it there: PE=mghPE = mgh. This is why the same formula reappears as "work done against gravity" in some textbook phrasings — they are the same quantity viewed two ways, one as stored energy, one as work input.

Worked example

A pile driver's hammer of mass 200 kg is raised 5 m above a pile and released. (a) Find its potential energy at the top, relative to the pile. (b) Find its kinetic energy just before it strikes the pile.

Step 1. List the knowns: m=200m = 200 kg, h=5h = 5 m, g=9.8 m/s2g = 9.8\ \text{m/s}^2.

Step 2. Apply PE=mghPE = mgh at the top:

PE=200×9.8×5PE = 200 \times 9.8 \times 5
PE=200×9.8=1960;1960×5=9800 JPE = 200 \times 9.8 = 1960; \quad 1960 \times 5 = 9800\ \text{J}

The hammer has 9800 J of potential energy relative to the pile when raised.

Step 3. Find the kinetic energy just before impact. Ignoring air resistance, mechanical energy is conserved: KE+PE=constantKE + PE = \text{constant}. At the top, KE=0KE = 0 and PE=9800PE = 9800 J, so Emech=9800E_{mech} = 9800 J. Just before striking the pile, the hammer is back at the reference level, so PE=0PE = 0, which means all of the mechanical energy has become kinetic energy.

KE just before impact = 9800 J.

Competitive stretch

On impact, this 9800 J of kinetic energy does work driving the pile into the ground, with a portion lost as heat and sound at the collision — a reminder that "conserved" mechanical energy only holds while friction and resistive losses are negligible, which stops being true the instant the hammer meets the pile.

Common traps

  • Treating PE as an absolute number with one "correct" value — it is always relative to a chosen reference level; only changes in PE usually matter physically.
  • Using the length of a slanted ramp or path instead of the true vertical height hh in PE=mghPE = mgh.
  • Assuming a motionless body has no energy — a book resting on a shelf has zero KE but nonzero PE relative to the floor; PE depends on position, not motion.
  • Forgetting that mechanical energy conservation (KE+PE=constantKE + PE = \text{constant}) only applies when friction and air resistance are negligible; real falls and collisions lose some energy as heat and sound.

Ask the tutor: Want to try a problem where a pendulum swings between two heights and you have to track PE and KE trading back and forth at several points along the swing?

Why does the formula use height and not the distance travelled along a slope

Potential energy depends only on vertical displacement from the reference level, because that vertical rise is what determines the work done against gravity. If a trolley is pushed up a long ramp to reach the same height as a shorter straight ladder, both trolleys gain identical potential energy at the top, even though the ramp trolley travelled a longer path — because hh in PE=mghPE = mgh is always the vertical height, not the path length.

Can potential energy ever be negative

Yes, if a body sits below the chosen reference level. Since PE is measured relative to a reference you pick, a stone at the bottom of a well has negative PE relative to the ground above, but this rarely comes up directly in ICSE Class 10 numericals, which mostly ask you to compute PE for a body raised above a stated reference. What matters in practice is being consistent about which level you call "zero" throughout a single problem.

Is elastic potential energy in a stretched spring part of this syllabus

No — at ICSE Class 10 level, potential energy is examined only in its gravitational form, PE=mghPE = mgh. Elastic potential energy (stored in a compressed or stretched spring) and other advanced forms belong to higher classes. You should know that other forms of potential energy exist conceptually, but you will not be asked to calculate them here — keep your formula-based answers strictly to PE=mghPE = mgh.

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