Gas and atmospheric pressure

Every moment of your life, you are sitting at the bottom of an ocean of air, and that ocean is pushing on you from every direction with surprising force. This is atmospheric pressure — the pressure created by the weight of the entire column of air stacked above a surface. It is the reason a drinking straw works, the reason a syringe fills, and the reason a rubber sucker clings to a smooth tile without any glue. Gas and atmospheric pressure is the closing idea of the ICSE Class 8 chapter "Force and Pressure," built directly on the general definition of pressure, P=F/AP = F/A, and the idea of liquid pressure that came just before it. Here we treat air itself as a fluid with weight, meet the standard sea-level value of atmospheric pressure, and use a single idea — a pressure difference pushing things from high pressure toward low pressure — to explain a whole family of everyday devices.

The core insight

Atmospheric pressure is the force per unit area exerted by the weight of the air column above a surface, and everyday suction devices work because removing air lowers the pressure in one place, so the higher pressure of the surrounding atmosphere pushes matter from high pressure to low pressure.

The core idea

The Earth is wrapped in a thick layer of air called the atmosphere. Air is matter, and like all matter it has weight. The atmosphere presses down on every surface beneath it because of the weight of the entire column of air stacked above that surface — this is exactly the same reasoning used for liquid pressure, applied to a fluid that happens to be a gas rather than a liquid. A few facts fix the idea precisely.

  • Atmospheric pressure is caused by the weight of the column of air above a surface. A taller or denser column presses harder, which is why pressure falls as you climb a mountain — there is less air left above you.
  • Like liquid pressure, atmospheric pressure acts in all directions at once — sideways and upward as well as downward — not only straight down.
  • At sea level, atmospheric pressure has a standard value that is worth memorising exactly:
1 atm=1.013×105 Pa=76 cm of mercury1\ \text{atm} = 1.013 \times 10^{5}\ \text{Pa} = 76\ \text{cm of mercury}

where: 1 atm1\ \text{atm} is one standard atmosphere, Pa\text{Pa} (pascal) is the SI unit of pressure equal to one newton per square metre, and 76 cm of mercury76\ \text{cm of mercury} is the equivalent height of a mercury column that this pressure can support — the two are simply two ways of stating the same push. That number is enormous once you connect it back to P=F/AP = F/A: since P=F/AP = F/A, the force on any area is F=P×AF = P \times A, so the atmosphere pushes on every square metre of surface at sea level with a force of about 1.013×105 N1.013 \times 10^{5}\ \text{N} — roughly the weight of ten large cars resting on that one square metre. We are not crushed by this because the fluids and gases inside our bodies push outward with a matching internal pressure, so the net force on our skin is essentially zero. A diagram makes the balance easier to hold in mind than the number alone.

Figure
A human figure at the centre of a circle with arrows of equal length pushing inward from all sides labelled atmospheric pressure, and a smaller set of arrows pushing outward from inside the figure labelled internal body pressure, showing the two nearly cancel
Why atmospheric pressure does not crush us atmospheric pressure — pushing in, about 1.013 times 10 to the 5 pascals internal body pressure — pushing out, nearly equal, so no net force

Many familiar devices work by deliberately creating a pressure difference: some action lowers the air pressure in a confined region, and the greater atmospheric pressure of the surrounding air then pushes a liquid or a surface from high pressure toward low pressure.

  • Drinking straw: sucking removes air from inside the straw, lowering the pressure there; the atmosphere pushes on the open drink and forces liquid up into your mouth.
  • Syringe: pulling the plunger back lowers the pressure inside the barrel; atmospheric pressure pushes liquid in through the needle to fill the empty space.
  • Rubber sucker: pressing it onto a surface squeezes out the trapped air beneath it, creating low pressure there; the full atmospheric pressure on the outside then holds the sucker firmly against the surface.
Derivation AThe force atmospheric pressure exerts

The goal of this derivation is to turn the abstract idea of "an enormous pressure" into a concrete number of newtons, using nothing beyond the defining relation P=F/AP = F/A rearranged for force, applied to the standard sea-level value of atmospheric pressure and a chosen surface area — the same arithmetic that explains why a rubber sucker or a large flat surface feels such a strong pull once the air beneath it is removed.

Step 1. Start from the defining relation for pressure, P=F/AP = F/A, where PP is pressure in pascals, FF is the force in newtons acting perpendicular to a surface, and AA is the area in square metres over which that force acts. This relation holds for gas pressure exactly as it does for the force a solid block exerts on a table.

Step 2. Rearrange for force: since P=F/AP = F/A, multiplying both sides by AA gives F=P×AF = P \times A. This says the total force pressing on a surface equals the pressure multiplied by the area it acts over — a larger area under the same pressure feels a proportionally larger total force.

Step 3. Substitute the standard sea-level value P=1.013×105 PaP = 1.013 \times 10^{5}\ \text{Pa} and a chosen area, say the palm of a hand with A=1.0×10−2 m2A = 1.0 \times 10^{-2}\ \text{m}^2 (about 100 cm2100\ \text{cm}^2). Then F=1.013×105×1.0×10−2=1.013×103 NF = 1.013 \times 10^{5} \times 1.0 \times 10^{-2} = 1.013 \times 10^{3}\ \text{N}, about one thousand newtons — roughly the weight of a hundred-kilogram mass — pressing on a single palm.

Step 4. Recognise why this force is not felt: the air trapped in the lungs, blood, and body fluids pushes outward with a matching internal pressure, so the net force on the skin is close to zero. The same F=P×AF = P \times A arithmetic, run in reverse with a lowered internal pressure, is exactly what explains why a sucker with the air removed beneath it clings so strongly — there the outward push has been made much smaller than the atmospheric push, so a large net force remains.

Worked example

Question: A rubber sucker with a flat circular base of area A=8.0×10−4 m2A = 8.0 \times 10^{-4}\ \text{m}^2 is pressed onto a smooth glass surface, squeezing out nearly all the air beneath it. Estimate the force with which the sucker is held against the glass by atmospheric pressure.

Step 1. Identify the pressure difference driving the effect. Once the trapped air is squeezed out, the pressure beneath the sucker is close to zero, while the full standard atmospheric pressure, P=1.013×105 PaP = 1.013 \times 10^{5}\ \text{Pa}, still acts on the outer face of the rubber.

Step 2. Apply F=P×AF = P \times A using the atmospheric pressure and the sucker's base area: F=1.013×105×8.0×10−4=81.0 NF = 1.013 \times 10^{5} \times 8.0 \times 10^{-4} = 81.0\ \text{N}.

Step 3. Interpret the result. A force of about 81 N81\ \text{N} is roughly the weight of an 8 kg8\ \text{kg} mass — more than enough to hold a light object firmly against a vertical or even an upside-down surface, which is exactly why suckers work in any orientation: atmospheric pressure pushes equally in all directions.

The sucker is held against the glass by a force of about 81 N, supplied entirely by the unbalanced atmospheric pressure on its outer face.

Competitive stretch

If the same sucker were used on a mountain where atmospheric pressure is only about 0.8×105 Pa0.8 \times 10^{5}\ \text{Pa}, the holding force drops to F=0.8×105×8.0×10−4=64 NF = 0.8 \times 10^{5} \times 8.0 \times 10^{-4} = 64\ \text{N} — noticeably weaker, since a shorter, thinner air column above presses down with less force.

Common traps

  • Thinking suction "pulls" liquid up a straw with some special force — it is actually the higher atmospheric pressure outside that pushes the liquid up; nothing pulls from inside.
  • Forgetting that atmospheric pressure acts in all directions, not only downward — this is essential to explaining why suckers stick to vertical or upside-down surfaces.
  • Believing we do not feel atmospheric pressure because it is weak — it is actually very large, about 1.013×105 Pa1.013 \times 10^{5}\ \text{Pa}; we do not feel it because internal body pressure balances it almost exactly.
  • Using F=P×AF = P \times A with the wrong area or forgetting to convert cm2\text{cm}^2 to m2\text{m}^2 before substituting, which gives an answer that is off by a factor of 10410^4.

Ask the tutor: Want to work through more F=P×AF = P \times A examples, or see how atmospheric pressure connects to the barometer you will meet in later classes? Ask the AI tutor to walk through it with you.

Why does a straw stop working if there is a tiny hole near the top?

A straw relies on lowering the pressure inside it below the atmospheric pressure pushing on the drink outside. If there is a hole near the top, sucking simply pulls in outside air through that hole instead of lowering the pressure inside the straw, so the pressure never drops enough below atmospheric. With no pressure difference along the straw's length below the hole, there is no push to lift the liquid, and the drink stays where it is.

Does atmospheric pressure stay the same everywhere on Earth?

No. Atmospheric pressure is highest at sea level and falls as altitude increases, because there is a shorter, lighter column of air above you higher up. This is why mountaineers on very tall peaks need extra oxygen — the lower pressure means fewer air molecules in each breath. At the ICSE Class 8 level, you only need the standard sea-level value, 1.013×105 Pa1.013 \times 10^{5}\ \text{Pa}, and the qualitative idea that pressure decreases with altitude.

Is atmospheric pressure the same idea as the pressure inside a gas cylinder or a balloon?

They are related but not identical. Atmospheric pressure specifically means the pressure exerted by the open atmosphere due to the weight of air above a surface. The pressure inside a sealed container, like a gas cylinder or an inflated balloon, is a separate quantity set by how much gas is squeezed into that space; it can be far higher or lower than atmospheric pressure. Both, however, obey the same underlying idea that pressure is force spread over area, P=F/AP = F/A.

Before this

Where this leads