SI units

A length measured as "25" means nothing until you say 25 what — centimetres, inches, or hand-spans. Physics avoids that ambiguity by insisting every measurement be reported in one universally agreed set of units: the SI system (Système International d'Unités). Built from just seven base units — one each for mass, length, time, current, temperature, luminous intensity and amount of substance — SI supplies every other unit in physics through combination, so that a joule in Delhi means exactly the same thing as a joule in Tokyo. This article fixes the seven base units and their symbols, shows how derived units like the newton and pascal are built from them, and works through the unit-conversion habits ICSE Class 9 numericals demand before a formula can even be applied.

The core insight

SI units are the seven internationally fixed base units (kg, m, s, A, K, cd, mol) from which every other physics unit is derived by combining them according to the defining formula of the quantity, so all answers must be reported in SI unless a question specifies otherwise.

The core idea

Fundamental (base) units measure the seven basic physical quantities that cannot be broken down into anything simpler:

Physical quantitySI unitSymbol
Masskilogramkg
Lengthmetrem
Timeseconds
Electric currentampereA
TemperaturekelvinK
Luminous intensitycandelacd
Amount of substancemolemol

Derived units are built from these seven by substituting into the defining equation of a quantity. Some are used so often that they earn a special one-word name — force (newton, N), pressure (pascal, Pa), energy (joule, J), power (watt, W), frequency (hertz, Hz), charge (coulomb, C), resistance (ohm, Ω\Omega) and potential difference (volt, V) — while most, like speed in m/s\text{m/s} or volume in m3\text{m}^3, simply combine the base units without a special name of their own. The rule that generates every derived unit is the same one that generates every derived quantity in mechanics:

[derived unit]=[base units]a [base units]b⋯[\text{derived unit}] = [\text{base units}]^{a}\,[\text{base units}]^{b}\cdots

where: the powers a,b,…a, b, \dots come directly from the algebraic formula defining the quantity — for speed =distance/time= \text{distance}/\text{time}, the unit is m1s−1\text{m}^1\text{s}^{-1}, written m/s\text{m/s}; for volume =l×b×h= l \times b \times h, it is m3\text{m}^3. Two older systems are named in the syllabus only so you can recognise them: the CGS system (centimetre, gram, second) and the FPS system (foot, pound, second). Both are legitimate systems of units, but neither is SI. Unless a question explicitly tells you otherwise, every measurement and every final numerical answer in ICSE Class 9 Physics must be reported in SI units — mixing cgs, fps and SI inside one calculation is the single commonest source of a wrong numerical answer.

Figure
A diagram showing the seven base units kilogram metre second ampere kelvin candela and mole feeding into combination boxes that produce the derived units newton pascal and joule
Base units combine, through a formula, into derived units kg m s A K cd mol seven SI base units F = m × a kg m s⁻² P = F / A kg m⁻¹ s⁻² newton (N) pascal (Pa) Special names are shortcuts for a fixed combination of base units, nothing more
Derivation ABuilding the pascal from the base units

Pressure is defined as force per unit area, and this derivation shows exactly how that one-line definition, combined with Newton's second law, forces the SI unit of pressure to be the specific combination of base units that we name the pascal — a chain any ICSE Class 9 student should be able to reproduce for other derived units too.

Step 1. Start from the defining formula of force. Newton's second law states F=maF = m a, where mm is mass and aa is acceleration. Substituting the SI base unit of mass (kg) and the SI unit of acceleration (m/s2\text{m/s}^2, itself derived from length over time squared) gives the unit of force as kg×m/s2=kg m s−2\text{kg} \times \text{m/s}^2 = \text{kg m s}^{-2}.

Step 2. Recognise that this combination is used constantly, so SI assigns it the special name newton, symbol N, defined as 1 N=1 kg m s−21\text{ N} = 1\text{ kg m s}^{-2}.

Step 3. Apply the defining formula of pressure, P=F/AP = F/A, where AA is area. Since area is length times length, its SI unit is m2\text{m}^2. Substituting the newton for force and m2\text{m}^2 for area gives the unit of pressure as N/m2=kg m s−2/m2=kg m−1s−2\text{N/m}^2 = \text{kg m s}^{-2} / \text{m}^2 = \text{kg m}^{-1}\text{s}^{-2}.

Step 4. Because this combination, too, appears everywhere, SI gives it the special name pascal, symbol Pa, so 1 Pa=1 N/m2=1 kg m−1s−21\text{ Pa} = 1\text{ N/m}^2 = 1\text{ kg m}^{-1}\text{s}^{-2}. The same two-step chain — write the defining formula, then substitute base or already-derived units — works for every derived unit in the syllabus, whether or not it ends up with a special name.

Worked example

Question: A rectangular block has length l=25 cml = 25\text{ cm}, breadth b=0.4 mb = 0.4\text{ m}, and height h=5 mmh = 5\text{ mm}. Express all three measurements in SI units, find the SI unit its volume should be reported in, compute the volume, and if the block has mass 1.5 kg1.5\text{ kg}, find its density in SI units.

Step 1. Convert each length to the SI unit of length, the metre: l=25 cm=25×10−2 m=0.25 ml = 25\text{ cm} = 25 \times 10^{-2}\text{ m} = 0.25\text{ m}; b=0.4 mb = 0.4\text{ m} (already SI); h=5 mm=5×10−3 m=0.005 mh = 5\text{ mm} = 5 \times 10^{-3}\text{ m} = 0.005\text{ m}.

Step 2. Identify the SI unit of volume from its defining formula, V=l×b×hV = l \times b \times h. Since each length is now in metres, three metres multiplied together give m3\text{m}^3 — the correct SI (derived) unit for volume, with no special name of its own.

Step 3. Compute the volume: V=0.25×0.4×0.005=5×10−4 m3V = 0.25 \times 0.4 \times 0.005 = 5 \times 10^{-4}\text{ m}^3.

Step 4. Find density from its defining formula, ρ=m/V\rho = m/V, substituting the SI unit of mass (kg) and the SI unit of volume (m3\text{m}^3) found in Step 2: ρ=1.5 kg5×10−4 m3=3000 kg/m3\rho = \dfrac{1.5\text{ kg}}{5 \times 10^{-4}\text{ m}^3} = 3000\text{ kg/m}^3.

Answer: l=0.25 ml = 0.25\text{ m}, b=0.4 mb = 0.4\text{ m}, h=0.005 mh = 0.005\text{ m}; volume =5×10−4 m3= 5 \times 10^{-4}\text{ m}^3; density =3000 kg/m3= 3000\text{ kg/m}^3, the SI unit of density.

Common traps

  • Writing unit symbols with the wrong case, such as "Kg" instead of "kg", or writing out "Newton" with a capital letter instead of using the symbol N (only the symbol is capitalised for units named after people, never the spelled-out word).
  • Forgetting to convert cm, mm or km to metres before substituting into a formula — mixing unit prefixes inside one calculation is the commonest source of a wrong final answer.
  • Assuming every derived quantity needs its own special unit name; most, like speed (m/s\text{m/s}) or volume (m3\text{m}^3), simply combine base units directly.
  • Confusing "SI system" with "metric system" — cgs is also a metric system, but it is not SI, and the syllabus expects SI unless told otherwise.

Ask the tutor: Want more practice converting between unit prefixes or building a derived unit's SI form from its formula? Ask the AI tutor for extra examples on SI units.

Why does physics insist on SI units instead of letting students use whatever unit is given?

Because a formula like F=maF = ma only gives a numerically correct answer when every quantity inside it is expressed in a consistent set of units. If mass is in grams and acceleration is in km/s2\text{km/s}^2, the numbers do not combine into a meaningful force unless you first convert everything to kilograms, metres and seconds. SI fixes that consistent set once and for all, so any formula from any topic can be applied without silently mismatched units.

How do I know if a derived unit gets a special name like newton or pascal, or stays as a combination like m/s?

There is no shortcut other than memorising the syllabus list — force, pressure, energy, power, frequency, charge, resistance and potential difference are the derived quantities that get special one-word names (N, Pa, J, W, Hz, C, ohm, V) because they are used so often. Every other derived quantity, such as speed, volume, density or area, is simply written as the combination of base units that its formula produces, with no special name attached.

Is it wrong to answer a numerical in cgs units if the question gives all the data in cgs?

For ICSE Class 9, no — if a question explicitly works entirely in cgs and asks for an answer in cgs, you follow it. But this is the exception, not the rule: unless a question specifically instructs you to use cgs or fps, every measurement and every final numerical answer should be converted to and reported in SI units. When in doubt, convert to SI first and work from there.

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