Comparing ionic and covalent bonds

Sodium chloride melts at a scorching 1074 K1074\ \text{K}; hydrogen chloride melts at a frosty 159 K159\ \text{K}. Both are simple compounds of a metal or hydrogen with chlorine, yet their behaviour could hardly be more different — and the reason is the kind of bond holding each together. In NaCl\text{NaCl}, sodium hands an electron over to chlorine outright; in HCl\text{HCl}, hydrogen and chlorine share a pair of electrons between them. This single distinction — transfer versus sharing — sets up nearly every contrast you will be asked to explain in this topic: melting points, conductivity, solubility, and structure. But the line is not as sharp as a textbook diagram suggests. Real compounds sit on a spectrum, and Fajans' rules tell you how to predict where on that spectrum a given ionic-looking compound actually falls.

The core insight

Ionic bonds form by complete electron transfer into an electrostatic 3-D lattice while covalent bonds form by electron sharing into discrete molecules, and Fajans' rules use cation charge density and anion size to predict how much covalent character a nominally ionic compound really has.

The core idea

Two mechanisms, two architectures. Ionic bonding transfers one or more electrons from an electropositive atom to an electronegative one, producing a cation and an anion that attract each other in every direction at once. There is no single "molecule" of NaCl\text{NaCl} — only an endlessly repeating crystal lattice of alternating ions. Covalent bonding instead shares electron pairs between two atoms so each reaches a stable configuration; the result is a discrete molecule, internally strong but only weakly attracted to its neighbours.

Why the properties diverge. Melting an ionic solid means breaking Coulombic attractions running through the entire lattice — a huge energy cost, hence high melting points and hardness. Melting a molecular covalent solid only requires overcoming the weak intermolecular forces between molecules; the strong covalent bonds inside each molecule stay intact, hence low melting points. The same logic explains conductivity: ionic compounds conduct only when their ions are freed to move, i.e. molten or in solution, never as a rigid solid; molecular covalent compounds generally lack free charge carriers altogether.

A rough quantitative handle on lattice strength comes from treating the ions as point charges obeying Coulomb's law:

Elattice∝q+ q−r0E_{\text{lattice}} \propto \frac{q^+ \, q^-}{r_0}

where: q+q^+ and q−q^- are the magnitudes of the cation and anion charge, and r0r_0 is the sum of the ionic radii (the centre-to-centre distance). Higher charges and smaller ions pack more Coulombic attraction into the lattice, which is exactly why MgO\text{MgO} (q+q−=4q^+q^- = 4) melts far higher than NaCl\text{NaCl} (q+q−=1q^+q^- = 1).

The same ratio, read differently, predicts covalent character. Define the ionic potential of the cation as ϕ=q+/r+\phi = q^+ / r^+ — charge packed into a small volume. A high ϕ\phi means the cation is a strong polariser: it distorts, or "pulls on," the electron cloud of the neighbouring anion. Fajans' rules turn this into three practical predictors of increased covalent character in an otherwise ionic compound: a small, highly charged cation (high polarising power); a large, easily distorted anion (high polarisability); and a cation with a pseudo-noble-gas (d10d^{10}) electron configuration, which polarises more strongly than a true noble-gas cation of equal charge and size.

Figure
Two panels contrasting electron transfer in sodium chloride with electron sharing in hydrogen chloride
Electron transfer versus electron sharing Ionic — NaCl (transfer) Na Cl one electron moves fully Na⁺ Cl⁻ electrostatic attraction in all directions builds an extended crystal lattice Covalent — HCl (sharing) H Cl shared electron pair strong bond inside the molecule, weak forces between separate molecules

Why it works

The physical driver behind every ionic-versus-covalent contrast is where the shared electron density actually sits. In a purely ionic picture the electron has moved completely onto the anion, so the bond is nothing but electrostatic attraction between two spherical, non-directional charge clouds — free to pack in whichever geometry maximises attraction and minimises repulsion, which is exactly a lattice. That is why ionic bonding gives no fixed "bond angle": each ion is simply surrounded by as many opposite-charge neighbours as will fit. Covalent bonding, by contrast, concentrates electron density between two specific nuclei, so the bond has a definite direction and a definite partner — which is why covalent compounds form discrete molecules with fixed bond angles rather than open-ended lattices. Fajans' rules matter because no real bond is a perfect point-charge transfer. When a small, highly charged cation such as Al3+\text{Al}^{3+} sits next to a large anion such as Cl−\text{Cl}^-, its concentrated positive charge drags the anion's outer electron cloud toward itself. Push that distortion far enough and electron density starts accumulating between the two nuclei — the defining feature of a covalent bond — even though the compound formally consists of a metal and a non-metal. So covalent character is not an exception to ionic bonding; it is what happens whenever polarisation becomes large enough to matter, and the ionic potential ϕ=q+/r+\phi = q^+/r^+ is the single number that tells you how far along that spectrum a compound sits.

Worked example

Rank NaCl\text{NaCl}, MgCl2\text{MgCl}_2 and AlCl3\text{AlCl}_3 in order of increasing covalent character, and explain the melting-point trend 1074 K→987 K→465 K1074\ \text{K} \to 987\ \text{K} \to 465\ \text{K} (sublimes) that goes with it.

Step 1. All three share the same anion, Cl−\text{Cl}^-, so by Fajans' rules the polarising power of the cation — governed by ϕ=q+/r+\phi = q^+/r^+ — controls the trend. The cation charges are +1+1, +2+2 and +3+3 respectively, and ionic radius shrinks as charge rises across a period (Na+>Mg2+>Al3+\text{Na}^+ > \text{Mg}^{2+} > \text{Al}^{3+}), so ϕ\phi rises sharply from Na+\text{Na}^+ to Mg2+\text{Mg}^{2+} to Al3+\text{Al}^{3+}.

Step 2. Higher ϕ\phi means stronger distortion of the shared Cl−\text{Cl}^- cloud, so covalent character increases in the order NaCl<MgCl2<AlCl3\text{NaCl} < \text{MgCl}_2 < \text{AlCl}_3. AlCl3\text{AlCl}_3 is polarised so strongly that it behaves like a covalent compound in many respects — it sublimes rather than melts at a high temperature, dissolves in organic solvents, and exists as the dimer Al2Cl6\text{Al}_2\text{Cl}_6 in the vapour phase.

Step 3. The melting-point fall follows directly: NaCl\text{NaCl}, essentially fully ionic, needs the most energy to break its extended Coulombic lattice (1074 K1074\ \text{K}). MgCl2\text{MgCl}_2, more polarised, melts lower (987 K987\ \text{K}) but is still a genuine ionic lattice. AlCl3\text{AlCl}_3, so covalent that it consists of discrete molecular units held by weak intermolecular forces, needs comparatively little energy to separate its units and sublimes at only 465 K465\ \text{K}.

Answer: covalent character rises NaCl<MgCl2<AlCl3\text{NaCl} < \text{MgCl}_2 < \text{AlCl}_3, tracking the rising ionic potential of the cation, and melting point falls in the same order because the lattice progressively weakens into a molecular solid.

Common traps

  • Treating "ionic" and "covalent" as two watertight boxes. Fajans' rules exist precisely because real bonds sit on a continuum; a metal–non-metal pair can still be substantially covalent.
  • Forgetting that anion size matters too. Polarising power is about the cation, but polarisability — how easily the electron cloud distorts — is an anion property; a large, diffuse anion like I−\text{I}^- is polarised far more easily than a small, tightly-held anion like F−\text{F}^-.
  • Confusing solid-state and molten/solution conductivity. Ionic compounds never conduct as rigid solids — the ions must be free to move, which happens only molten or dissolved.
  • Assuming low melting point always means "purely covalent." Giant covalent networks such as diamond have very high melting points despite being covalent; the low-melting-point rule applies specifically to molecular covalent compounds, where only weak intermolecular forces need breaking.

Ask the tutor: Want to work through Fajans' rules for a different cation-anion pair, such as comparing MgCl2 and MgO for covalent character?

If NaCl and HCl are both formed from chlorine, why is one a lattice and the other a molecule?

The difference is not chlorine but its partner. Sodium has very low ionisation enthalpy, so it readily gives up its outer electron entirely to chlorine, forming discrete Na+\text{Na}^+ and Cl−\text{Cl}^- ions that then pack into a lattice held by non-directional electrostatic attraction. Hydrogen, by contrast, does not lose its single electron easily and instead shares it with chlorine, forming one directional covalent bond and a self-contained diatomic molecule. Same chlorine, very different partner behaviour, very different bond.

Is Fajans rules only about cations, since we always talk about polarising power?

No — polarisation needs two partners. The cation supplies the polarising power (higher for small, highly charged, or pseudo-noble-gas cations), but the anion supplies the polarisability, meaning how easily its own electron cloud can be pulled out of shape. A weakly polarising cation next to a highly polarisable anion, such as a large iodide ion, can still show significant covalent character. You always have to look at both ions together, not the cation alone.

Does more covalent character mean a compound is no longer really ionic at all?

Not necessarily — it means the bond has shifted along a continuum rather than switched categories entirely. A compound like AlCl3\text{AlCl}_3 still forms from a metal and a non-metal and still shows some ionic behaviour, but its properties (subliming instead of melting at very high temperature, dissolving in organic solvents, existing as molecular Al2Cl6\text{Al}_2\text{Cl}_6 in vapour) are dominated by its covalent character. Fajans' rules let you predict how far along that continuum a compound sits, not just which side of a false boundary it falls on.

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