Magnetic materials

Hold a bar of iron near a magnet and it leaps toward it. Hold a bar of copper near the same magnet and almost nothing happens — except a faint, easy-to-miss push away. Every material on Earth reacts to a magnetic field in one of these three families of ways: weak repulsion, weak attraction, or dramatic, self-reinforcing attraction that can persist even after the field is switched off. This article gives that behaviour a precise vocabulary. You will define magnetic susceptibility χm\chi_m and relative permeability μr\mu_r, use their sign and size to sort any material into diamagnetic, paramagnetic, or ferromagnetic, and apply Curie's law to see how a paramagnet's response fades as it heats up — closing out the "Magnetic Effects of Current and Magnetism" unit before hysteresis takes over next.

The core insight

Every material's magnetic response is captured by one number, the susceptibility χm=M/H\chi_m = M/H, whose sign and size sort it as diamagnetic (small, negative), paramagnetic (small, positive, weakening with temperature per Curie's law), or ferromagnetic (large, positive, collapsing to paramagnetic above the Curie temperature).

The core idea

Place any material inside an external magnetic field. The field, called the magnetising field HH, is what a solenoid's free (conduction) current alone would produce. Inside the material, the atomic magnetic dipoles respond and produce a net dipole moment per unit volume called the magnetisation MM. How readily MM builds up in response to HH is the single number that classifies a material:

χm=MH\chi_m = \frac{M}{H}

where: χm\chi_m is the magnetic susceptibility (dimensionless — a ratio of two quantities with the same units, A/m), MM is the magnetisation and HH is the magnetising field. A closely related number is the relative permeability,

μr=1+χm\mu_r = 1+\chi_m

which tells you the factor by which the total field inside the material, B=μ0μrHB = \mu_0\mu_r H, differs from what a vacuum would give. Since μ=μ0μr\mu = \mu_0 \mu_r is the material's absolute permeability, this can also be written B=μHB = \mu H.

Three families, read off the sign and size of χm\chi_m.

  • Diamagnetic — χm\chi_m small and negative, μr\mu_r a hair below 1. Atoms have no permanent dipole moment of their own; the applied field induces a tiny opposing moment (an application of Lenz's law at the atomic scale), so the material is weakly repelled. This effect exists in every atom but is only visible when nothing stronger is present. Examples: bismuth, copper, water.
  • Paramagnetic — χm\chi_m small and positive, μr\mu_r a hair above 1. Atoms carry a small permanent dipole moment (from unpaired electrons) that tends to line up with HH, but thermal jostling constantly disrupts the alignment, so the net effect stays weak. Examples: aluminium, sodium, platinum.
  • Ferromagnetic — χm\chi_m large and positive, μr\mu_r often in the hundreds or thousands. Neighbouring atomic dipoles lock together cooperatively within microscopic regions called domains, so even a modest HH produces a huge MM. Examples: iron, cobalt, nickel.

Curie's law governs the paramagnetic case: as temperature TT rises, thermal agitation fights harder against the field's attempt to align the dipoles, so susceptibility falls:

χm∝1T\chi_m \propto \frac{1}{T}

This is a qualitative, inverse proportionality — useful for "susceptibility at one temperature, find it at another" problems, not something you are asked to derive. Ferromagnets, meanwhile, don't fade gradually — they collapse. Above a sharply defined Curie temperature TCT_C, thermal energy overwhelms the cooperative domain alignment entirely, and the material becomes an ordinary paramagnet. Iron's TC≈1043 KT_C \approx 1043\ \text{K} (770°C770°\text{C}): heat an iron nail past that point and it stops behaving like a strong magnet.

Figure
Three bar magnets showing a diamagnetic sample weakly pushed away, a paramagnetic sample weakly pulled in, and a ferromagnetic sample strongly pulled in with aligned domain arrows
Three responses to the same external field H N field source diamagnetic weak push away paramagnetic weak pull in ferromagnetic strong pull, aligned domains Arrow direction and thickness show whether each sample is repelled or attracted, and how strongly
Derivation AApplying Curie's law to find susceptibility at a new temperature

The goal is to show, step by step, how the single proportionality χm∝1/T\chi_m \propto 1/T turns into a working formula for predicting a paramagnetic sample's susceptibility at a second temperature once you know it at a first — the exact kind of question ISC Class 12 sets on this topic.

Step 1. Write Curie's law as a proportionality: χm∝1/T\chi_m \propto 1/T, which means χmT\chi_m T is the same constant at every temperature for a given paramagnetic sample (as long as it stays paramagnetic, i.e. below any Curie temperature it might have if it were really a weakened ferromagnet).

Step 2. Because χmT\chi_m T is constant, its value at temperature T1T_1 must equal its value at temperature T2T_2:

χm1T1=χm2T2\chi_{m1}T_1 = \chi_{m2}T_2

Step 3. Rearrange to isolate the unknown susceptibility:

χm2=χm1(T1T2)\chi_{m2} = \chi_{m1}\left(\frac{T_1}{T_2}\right)

Step 4. Read the physics in the formula: if T2>T1T_2 > T_1 (heating the sample), the ratio T1/T2T_1/T_2 is less than 1, so χm2<χm1\chi_{m2} < \chi_{m1} — susceptibility must fall as temperature rises, exactly as the qualitative statement of Curie's law demands. This formula is the one to reach for whenever a problem gives χm\chi_m at one temperature and asks for it at another.

Worked example

A paramagnetic sample has susceptibility χm=2.4×10−3\chi_m = 2.4\times10^{-3} at T1=300 KT_1 = 300\ \text{K}. Find its susceptibility at T2=400 KT_2 = 400\ \text{K}, and separately, a second sample with H=2000 A/mH = 2000\ \text{A/m} produces M=6 A/mM = 6\ \text{A/m} — classify it and find μr\mu_r.

Step 1. Apply the Curie's-law formula from the derivation: χm2=χm1(T1/T2)=(2.4×10−3)(300/400)\chi_{m2} = \chi_{m1}(T_1/T_2) = (2.4\times10^{-3})(300/400).

Step 2. Compute: χm2=(2.4×10−3)(0.75)=1.8×10−3\chi_{m2} = (2.4\times10^{-3})(0.75) = 1.8\times10^{-3}. As expected, susceptibility dropped as the sample warmed from 300 K300\ \text{K} to 400 K400\ \text{K}.

Step 3. For the second sample, find susceptibility directly from its definition: χm=M/H=6/2000=3×10−3\chi_m = M/H = 6/2000 = 3\times10^{-3}.

Step 4. Classify from the sign: χm\chi_m is small and positive, so this material is paramagnetic. Its relative permeability is μr=1+χm=1+3×10−3=1.003\mu_r = 1+\chi_m = 1+3\times10^{-3} = 1.003.

Final answers: χm2=1.8×10−3\chi_{m2} = 1.8\times10^{-3} at 400 K400\ \text{K}; the second sample is paramagnetic with χm=3×10−3\chi_m = 3\times10^{-3} and μr=1.003\mu_r = 1.003.

Common traps

  • Flipping the sign convention — diamagnetic materials have negative χm\chi_m and μr\mu_r slightly below 1; paramagnetic materials have positive χm\chi_m and μr\mu_r slightly above 1.
  • Thinking a material is purely one type — diamagnetism is present in all matter but is masked whenever paramagnetic or ferromagnetic behaviour is also present.
  • Applying Curie's law (χm∝1/T\chi_m \propto 1/T) to a ferromagnet below its Curie temperature — the law is for the paramagnetic regime only; ferromagnetic ordering is governed by the cooperative domain physics, not this simple proportionality.
  • Confusing the Curie temperature with a melting point — it marks where ferromagnetic order breaks down into ordinary paramagnetism, not a change of physical state.

Ask the tutor: Want a side-by-side comparison table of diamagnetic, paramagnetic, and ferromagnetic materials, or a walkthrough of a trickier Curie's-law proportion problem?

Why does diamagnetism exist in every material but we usually only notice it in a few?

Diamagnetism comes from the field inducing a tiny opposing moment in atoms that otherwise have no permanent dipole of their own — a universal, Lenz's-law-like response present in every atom. But if a material's atoms also happen to carry a permanent dipole moment (unpaired electrons), paramagnetic or ferromagnetic effects kick in, and these are far stronger, so they completely swamp the tiny diamagnetic contribution. You only "see" pure diamagnetism in materials like bismuth or copper where no permanent atomic moment exists to compete with it.

Is mu_r always bigger than 1?

No. For diamagnetic materials χm\chi_m is negative, so μr=1+χm\mu_r = 1+\chi_m is slightly less than 1 — the field inside is marginally weaker than the applied field. For paramagnetic and ferromagnetic materials χm\chi_m is positive, so μr\mu_r is greater than 1, ranging from just above 1 (paramagnetic) to hundreds or thousands (ferromagnetic). Always check the sign of χm\chi_m before assuming μr>1\mu_r > 1.

Does Curie's law mean a paramagnetic material eventually becomes non-magnetic at high enough temperature?

Not exactly — χm∝1/T\chi_m \propto 1/T says susceptibility keeps shrinking as TT rises, approaching zero at very high temperatures, but it is a smooth, gradual fade rather than a sharp cutoff. That's different from what happens to a ferromagnet at its Curie temperature, where the strong cooperative domain alignment collapses abruptly at one specific temperature and the material switches over to ordinary (much weaker) paramagnetic behaviour. Curie's law itself applies only to that already-paramagnetic regime.

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