Determine the general solution of .

MATHEMATICS · Single correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

Determine the general solution of 2sin⁡xcos⁡x−sin⁡x=02\sin x\cos x - \sin x = 0. (a) x=nπorx=2nπ±π6,  n∈Zx = n\pi \quad \text{or} \quad x = 2n\pi \pm \dfrac{\pi}{6},\; n\in\mathbb{Z} (b) x=nπorx=2nπ±π3,  n∈Zx = n\pi \quad \text{or} \quad x = 2n\pi \pm \dfrac{\pi}{3},\; n\in\mathbb{Z} (c) x=nπorx=nπ±π3,  n∈Zx = n\pi \quad \text{or} \quad x = n\pi \pm \dfrac{\pi}{3},\; n\in\mathbb{Z} (d) x=nπorx=2nπ±2π3,  n∈Zx = n\pi \quad \text{or} \quad x = 2n\pi \pm \dfrac{2\pi}{3},\; n\in\mathbb{Z}

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