A solution initially contains and

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

A solution initially contains 0.010 M Fe3+0.010\,\mathrm{M}\,\mathrm{Fe^{3+}} and 0.010 M Cu2+0.010\,\mathrm{M}\,\mathrm{Cu^{2+}}. As the pH is raised slowly from 1 to 9, hydroxide salts may precipitate. Given Ksp(Fe(OH)3)=4×10−38K_{sp}(\mathrm{Fe(OH)_3}) = 4 \times 10^{-38} and Ksp(Cu(OH)2)=2×10−20K_{sp}(\mathrm{Cu(OH)_2}) = 2 \times 10^{-20}, which statement best predicts the order of precipitation? (a) Cu(OH)2\mathrm{Cu(OH)_2} precipitates before Fe(OH)3\mathrm{Fe(OH)_3} because its larger KspK_{sp} indicates lower solubility. (b) Cu(OH)2\mathrm{Cu(OH)_2} precipitates before Fe(OH)3\mathrm{Fe(OH)_3} because Cu2+^{2+} needs only two OH−\mathrm{OH^-} ions, whereas Fe3+^{3+} needs three. (c) Fe(OH)3\mathrm{Fe(OH)_3} precipitates before Cu(OH)2\mathrm{Cu(OH)_2} because it reaches its KspK_{sp} at a lower [OH−]\mathrm{[OH^-]}. (d) Both hydroxides begin to precipitate at the same pH since the metal-ion concentrations are equal.

Related theory

Browse the problem library