Let be the first term and the common ratio of a geometric progression
MATHEMATICS · Multi-part · A Level · Mathematics · Sequences and series · Sequences and series
Problem
Let a be the first term and r(=1) the common ratio of a geometric progression. The sum of the first n terms is denoted by Sn.
(i) Show that S2n=Sn+rnSn.
(ii) Hence obtain SnS2n in terms of r and n.
(iii) Taking r=2, determine the least positive integer n for which S2n exceeds Sn by more than 999a. Show all steps clearly.