The height (in metres) of a stone thrown vertically upwards after seconds is given by…

MATHEMATICS · Multi-part · CBSE · Mathematics · Quadratic Equations · Quadratic Equations

Problem

The height h(t)h(t) (in metres) of a stone thrown vertically upwards after tt seconds is given by h(t)=−5t2+20t+3h(t)=-5t^{2}+20t+3 for t≥0t\ge 0. (a) Find the value(s) of tt when the stone is at ground level (h=0h=0). (b) Determine the maximum height reached by the stone and the time at which it occurs. (c) Draw a rough sketch of the graph of hh against tt, marking clearly the intercepts with the axes and the highest point. Explain the physical meaning of the zeros in this context.

Related theory

Browse the problem library