For solid A, and . For solid B, and . Both solids are sparingly soluble at . When the…

CHEMISTRY · Subjective · A Level · Chemistry · Thermodynamics · Thermodynamics

Problem

For solid A, ΔHdiss∘=−10 kJ mol−1\Delta H^{\circ}_{\text{diss}} = -10\,\text{kJ mol}^{-1} and ΔSdiss∘=−40 J mol−1 K−1\Delta S^{\circ}_{\text{diss}} = -40\,\text{J mol}^{-1}\,\text{K}^{-1}. For solid B, ΔHdiss∘=+10 kJ mol−1\Delta H^{\circ}_{\text{diss}} = +10\,\text{kJ mol}^{-1} and ΔSdiss∘=+40 J mol−1 K−1\Delta S^{\circ}_{\text{diss}} = +40\,\text{J mol}^{-1}\,\text{K}^{-1}. Both solids are sparingly soluble at 0∘C0^{\circ}\text{C}. When the temperature is raised to 60∘C60^{\circ}\text{C}, which solid is expected to show the larger increase in solubility? Briefly explain your choice.

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