The answers are in Chapter 24.

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Problem

The answers are in Chapter 24. (A) y−1=−143(x−3)y-1=-\frac{1}{4 \sqrt{3}}(x-3) (B) y−3=−143(x−1)y-\sqrt{3}=-\frac{1}{4 \sqrt{3}}(x-1) (C) y−3=−12(x−1)y-\sqrt{3}=-\frac{1}{2}(x-1) (D) y−1=−12(x−3)y-1=-\frac{1}{2}(x-3)

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