For a quantity whose rate of change is given by a continuous function (units per…

MATHEMATICS · Single correct · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

For a quantity whose rate of change is given by a continuous function r(t)r(t) (units per hour) and whose initial amount is zero, the accumulated amount after tt hours is A(t)=∫0tr(s) dsA(t)=\displaystyle\int_{0}^{t} r(s)\,ds. To find the time TT at which the accumulated amount first equals a fixed value KK units, which of the following equations should be solved for TT? (a) r(T) T=Kr(T)\,T = K (b) ∫T0r(s) ds=K\displaystyle\int_{T}^{0} r(s)\,ds = K (c) ∫0Tr(s) ds=K\displaystyle\int_{0}^{T} r(s)\,ds = K (d) ∫0T∣ r(s) ∣ ds=K\displaystyle\int_{0}^{T} |\,r(s)\,|\,ds = K

Related theory

Browse the problem library