AP

MATHEMATICS · Multi-part · AP · Calculus BC · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Let I(b)=∫0bx3e2x dx I(b)=\displaystyle \int_{0}^{b} x^{3} e^{2x}\,dx\, for b>0b>0. (a) Calculate I(b)I(b) and express your result as e2be^{2b} multiplied by a cubic polynomial in bb minus a constant. (b) Verify your result in part (a) by differentiating your antiderivative and simplifying to recover the integrand x3e2xx^{3}e^{2x}. (c) Use the structure of your answer in part (a) to derive, by inspection, a closed–form expression for ∫xne2x dx\displaystyle \int x^{n}e^{2x}\,dx when nn is a non-negative integer. Write your answer as e2xe^{2x} multiplied by a finite sum written with sigma notation. (d) Apply the formula you obtained in part (c) to evaluate ∫0ln⁡2x4e2x dx.\displaystyle \int_{0}^{\ln 2} x^{4} e^{2x}\,dx.

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