A student wants to verify that the function is a solution of the differential equation

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

A student wants to verify that the function y=x1+x2y = x\sqrt{1 + x^{2}} is a solution of the differential equation x dydx=1+x2+x21+x2x\,\dfrac{dy}{dx} = \sqrt{1 + x^{2}} + \dfrac{x^{2}}{\sqrt{1 + x^{2}}}. Which of the following steps is both necessary and sufficient to complete this verification? (a) Integrate the right–hand side of the differential equation and compare the antiderivative with yy (ignoring the constant of integration). (b) Verify the equation only at x=0x=0; if both sides agree there, the function must satisfy the differential equation everywhere. (c) Differentiate yy with respect to xx, substitute dydx\dfrac{dy}{dx} into the differential equation, and confirm that the resulting identity holds for all xx in the domain. (d) Compute dydx\dfrac{dy}{dx} and set it equal to 1+x2+x21+x2\sqrt{1+x^{2}}+\dfrac{x^{2}}{\sqrt{1+x^{2}}}, since matching the slopes is sufficient.

Related theory

Browse the problem library