An EM wave from air enters a medium

PHYSICS · Single correct · CBSE · Physics · Electromagnetic Waves · Electromagnetic Waves

Problem

An EM wave from air enters a medium. The electric fields are E⃗1=E01x^cos⁡[2πv(zc−t)]\vec{E}_1 = E_{01} \hat{x} \cos \left[ 2\pi v \left( \frac{z}{c} - t \right) \right] in air and E⃗2=E02x^cos⁡[k(2z−ct)]\vec{E}_2 = E_{02} \hat{x} \cos[k(2z - ct)] in medium, where the wave number kk and frequency vv refer to their values in air. The medium is nonmagnetic. If ϵr\epsilon_r and ϵr2\epsilon_{r2} refer to relative permittivities of air and medium respectively, which of the following options is correct? (1) ϵr1ϵr2=4\frac{\epsilon_{r1}}{\epsilon_{r2}} = 4 (2) ϵr1ϵr2=2\frac{\epsilon_{r1}}{\epsilon_{r2}} = 2 (3) ϵr1ϵr2=14\frac{\epsilon_{r1}}{\epsilon_{r2}} = \frac{1}{4} (4) ϵr1ϵr2=12\frac{\epsilon_{r1}}{\epsilon_{r2}} = \frac{1}{2}

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