The minimum value of where is :

MATHEMATICS · Single correct · CBSE · Mathematics · Sequences and Series · Sequences and Series

Problem

The minimum value of

\frac{(A^2 + A + 1)(B^2 + B + 1)(C^2 + C + 1)(D^2 + D + 1)}{ABCD}

where

A, B, C, D > 0

is : (a)

\frac{1}{3^4}

(b)

\frac{1}{2^4}

(c)

2^4

(d)

3^4