Two transparent polymer films are suspended in air and illuminated with white light…

PHYSICS · Single correct · A Level · Physics · Waves · Waves

Problem

Two transparent polymer films are suspended in air and illuminated with white light at normal incidence. Both films have an index of refraction n=1.50n = 1.50. Film X has thickness tX=75 nmt_X = 75\,\text{nm}, and Film Y has thickness tY=150 nmt_Y = 150\,\text{nm}. An observer looks at the light reflected from each film. Which film will appear brighter in blue light of wavelength 450 nm450\,\text{nm} in air, and why? (a) Film Y, because 2ntY2 n t_Y equals mλm\lambda for some integer mm, giving constructive interference for blue light. (b) Film X, because its thickness is λ/(4n)\lambda/(4n), a textbook “quarter-wave” thickness that maximizes reflection of that color. (c) Film X, because 2ntX2 n t_X equals (m+0.5)λ(m+0.5)\lambda for some integer mm, producing constructive interference for blue light. (d) Film Y, because both reflected rays experience the same phase shift, so constructive interference occurs when 2ntY2 n t_Y equals mλm\lambda.

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