Lead(II) chromate has at

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

Lead(II) chromate has Ksp=1.2×10−13K_{sp}=1.2\times10^{-13} at 25∘C25^{\circ}\text{C}. Which statement best justifies labeling this salt as “insoluble” in water? (a) Because Ksp=1.2×10−13K_{sp}=1.2\times10^{-13} is smaller than KwK_w, the salt must be insoluble in water. (b) The large molar mass of PbCrO4\text{PbCrO}_4 makes its molarity in solution extremely small, accounting for its insolubility. (c) Its KspK_{sp} is many orders of magnitude smaller than 1, so the dissolution equilibrium strongly favors the solid phase and only a negligible amount dissolves. (d) A low KspK_{sp} means the maximum concentration of PbCrO4\text{PbCrO}_4 that can dissolve is exactly 1.2×10−13 M1.2\times10^{-13}\,\text{M}, a vanishingly small amount.

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