At , the thermal energy per mole of particles is approximately . A chemist is…

CHEMISTRY · Multi-part · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

At 298 K298\,\text{K}, the thermal energy per mole of particles is approximately 2.5 kJ2.5\,\text{kJ}. A chemist is studying the reversible reaction X(g)⇌Y(g)X(g) \rightleftharpoons Y(g) and measures the standard free-energy change, ΔG∘\Delta G^\circ, for three different modifications of the reaction conditions (such as different isotopologues or catalysts). The values obtained are listed below. Trial 1 ΔG∘=−2.0 kJ mol−1\Delta G^\circ = -2.0\,\text{kJ mol}^{-1} Trial 2 ΔG∘=+0.3 kJ mol−1\Delta G^\circ = +0.3\,\text{kJ mol}^{-1} Trial 3 ΔG∘=+5.5 kJ mol−1\Delta G^\circ = +5.5\,\text{kJ mol}^{-1} Answer the following questions about the position of equilibrium for each trial. No calculator is permitted. (1) Part 1: For each trial, state whether the equilibrium mixture will consist of (i) mostly X, (ii) roughly equal amounts of X and Y, or (iii) mostly Y. Justify each choice qualitatively. (2) Part 2: Rank the three trials from largest to smallest equilibrium constant, KK, and explain your reasoning. (3) Part 3: For Trial 2, estimate the percent of molecules present as Y at equilibrium and explain why only an approximate value is required rather than an exact calculation.

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