Which expression gives the change in gravitational potential energy of an object of…

PHYSICS · Single correct · AP · Physics 1: Algebra-based · Work Energy and Power · Work Energy and Power

Problem

Which expression gives the change in gravitational potential energy ΔU\Delta U of an object of mass mm lifted vertically by a distance Δy\Delta y near Earth’s surface where the acceleration due to gravity gg is approximately constant? (a) ΔU=−mg Δy\Delta U = -mg\,\Delta y (b) ΔU=12mg Δy\Delta U = \dfrac{1}{2}mg\,\Delta y (c) ΔU=mg Δy\Delta U = mg\,\Delta y (d) ΔU=−GmMEΔy\Delta U = -\dfrac{G m M_E}{\Delta y}

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