CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

Calculate

\displaystyle \int (x-1)\cos 4x\,dx

. (a)

\dfrac{1}{4}(x-1)\cos 4x+\dfrac{1}{16}\sin 4x+C

(b)

\dfrac{1}{4}(x-1)\sin 4x+\dfrac{1}{16}\cos 4x+C

(c)

\dfrac{1}{4}(x-1)\sin 4x-\dfrac{1}{16}\cos 4x+C

(d)

\dfrac{1}{4}(x+1)\sin 4x+\dfrac{1}{16}\cos 4x+C