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E^ 2x -1 e^ 2x +1 ,dx=
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
e
2
x
−
1
e
2
x
+
1
d
x
=
\int\frac{e^{2x}-1}{e^{2x}+1}\,dx=
∫
e
2
x
+
1
e
2
x
−
1
d
x
=
(a)
e
2
x
−
1
e
2
x
+
1
+
C
\frac{e^{2x}-1}{e^{2x}+1}+C
e
2
x
+
1
e
2
x
−
1
+
C
(b)
log
(
e
2
x
+
1
)
−
x
+
C
\log(e^{2x}+1)-x+C
lo
g
(
e
2
x
+
1
)
−
x
+
C
(c)
log
(
e
2
x
+
1
)
+
C
\log(e^{2x}+1)+C
lo
g
(
e
2
x
+
1
)
+
C
(d) None of these
Related theory
Integration Techniques
Standard algebraic integrals
Integrals of additional types
Integrals
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