A car travels along a straight road so that its position (in meters) after seconds is…

PHYSICS · Single correct · CBSE · Physics · Motion · Motion

Problem

A car travels along a straight road so that its position (in meters) after tt seconds is given by s(t)=120−90e−0.05ts(t)=120-90e^{-0.05t}. Determine the average velocity of the car, in meters per second, over the first 1010 seconds. Round your answer to two decimal places. (a) 6.54 m/s6.54\text{ m/s} (b) 7.08 m/s7.08\text{ m/s} (c) 3.54 m/s3.54\text{ m/s} (d) 3.50 m/s3.50\text{ m/s}

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