A spring with force constant is stretched to the right of its equilibrium position

PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations

Problem

A spring with force constant 200 N m−1200\,\text{N m}^{-1} is stretched 0.04 m0.04\,\text{m} to the right of its equilibrium position. Taking right as the positive direction, the restoring force on the attached mass is (a) −0.8 N-0.8\,\text{N} (b) −8 N-8\,\text{N} (c) +8 N+8\,\text{N} (d) +0.8 N+0.8\,\text{N}

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