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A spring with force constant is stretched to the right of its equilibrium position
PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations
Problem
A spring with force constant
200
N m
−
1
200\,\text{N m}^{-1}
200
N m
−
1
is stretched
0.04
m
0.04\,\text{m}
0.04
m
to the right of its equilibrium position. Taking right as the positive direction, the restoring force on the attached mass is (a)
−
0.8
N
-0.8\,\text{N}
−
0.8
N
(b)
−
8
N
-8\,\text{N}
−
8
N
(c)
+
8
N
+8\,\text{N}
+
8
N
(d)
+
0.8
N
+0.8\,\text{N}
+
0.8
N
Related theory
Simple Harmonic Motion (SHM)
Simple harmonic motion
Oscillations
Pendulum and spring systems
Force law in SHM
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