The negative base-10 logarithm of the solubility product for is at 25 °C

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

The negative base-10 logarithm of the solubility product for

\text{Fe(OH)}_3

pK_{sp}=38.6

at 25 °C. What is the molar solubility of

\text{Fe(OH)}_3

in pure water at this temperature? (a)

2.2\times10^{-10}\,\text{M}

(b)

6.6\times10^{-14}\,\text{M}

(c)

1.0\times10^{-10}\,\text{M}

(d)

2.9\times10^{-20}\,\text{M}