When a particle of mass is attached to a vertical spring of spring constant and released

PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations

Problem

When a particle of mass mm is attached to a vertical spring of spring constant kk and released, its motion is described by y(t)=y0sin⁡2ωty(t) = y_0 \sin^2 \omega t , where ' yy ' is measured from the lower end of unstretched spring. Then ω\omega is : (1) 12gy0\frac{1}{2} \sqrt{\frac{g}{y_0}} (2) gy0\sqrt{\frac{g}{y_0}} (3) g2y0\sqrt{\frac{g}{2y_0}} (4) 2gy0\sqrt{\frac{2g}{y_0}}

Related theory

Browse the problem library