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The solubility–product constant of at 25 °C is
CHEMISTRY · Subjective · AP · Chemistry · Equilibrium · Equilibrium
Problem
The solubility–product constant of
C
a
3
(
P
O
4
)
2
Ca_3(PO_4)_2
C
a
3
(
P
O
4
)
2
at 25 °C is
K
s
p
=
2.0
×
10
−
29
K_{sp}=2.0\times10^{-29}
K
s
p
=
2.0
×
1
0
−
29
. Determine the molar solubility of
C
a
3
(
P
O
4
)
2
Ca_3(PO_4)_2
C
a
3
(
P
O
4
)
2
in a solution that is initially
0.010
M
0.010\,\text{M}
0.010
M
in
C
a
2
+
Ca^{2+}
C
a
2
+
. Report your answer in mol L
−
1
^{-1}
−
1
using two significant figures.
Related theory
Equilibrium
Chemical Equilibrium
Solubility product
Solubility Equilibria
Common-Ion Effect
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