For a mixing situation in which liquid enters and leaves at equal rates so that the…

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

For a mixing situation in which liquid enters and leaves at equal rates so that the tank volume VV remains constant, which of the following best explains why the differential equation governing the quantity of dissolved substance Q(t)Q(t) can be solved by direct separation of variables? (a) Because equal flow rates cancel the inflow and outflow terms, leaving dQdt=0\dfrac{dQ}{dt}=0, so separation is unnecessary. (b) Because VV is constant, the outflow term is proportional only to QQ, giving an equation of the form dQdt=a−bQ\dfrac{dQ}{dt}=a-bQ, whose variables can be separated. (c) Because the inflow concentration is always constant, the equation is linear but never separable into QQ and tt terms. (d) Because the outflow term can be written as (Q/V)r(Q/V)r, the inflow term disappears, giving dQdt=−QV\dfrac{dQ}{dt}=-\dfrac{Q}{V}, which does not allow full separation of QQ and tt."

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