The average binding energy per nucleon of is about

PHYSICS · Single correct · A Level · Physics · Nuclear physics · Nuclear physics

Problem

The average binding energy per nucleon of 56 ⁣Fe^{56}\!\text{Fe} is about 8.8 MeV8.8\,\text{MeV}. For 86 ⁣Kr^{86}\!\text{Kr} it is roughly 8.5 MeV8.5\,\text{MeV}. Which statement about 86 ⁣Kr^{86}\!\text{Kr} is most appropriate? (a) It would absorb energy whether it underwent fission or fusion. (b) It would release energy chiefly by fusing with lighter nuclei. (c) It would release energy chiefly by splitting into two lighter fragments. (d) It is so stable that neither fusion nor fission can release energy from it.

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