CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

∫1(x2+a2)(x2+b2) dx=\int \frac{1}{(x^2+a^2)(x^2+b^2)}\,dx = (a) 1(a2−b2)[1btan⁡−1(xb)−1atan⁡−1(xa)]+c\frac{1}{(a^2-b^2)}\left[\frac{1}{b}\tan^{-1}\left(\frac{x}{b}\right)-\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)\right]+c (b) 1(b2−a2)[1btan⁡−1(xb)−1atan⁡−1(xa)]+c\frac{1}{(b^2-a^2)}\left[\frac{1}{b}\tan^{-1}\left(\frac{x}{b}\right)-\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)\right]+c (c) 1btan⁡−1(xb)−1atan⁡−1(xa)+c\frac{1}{b}\tan^{-1}\left(\frac{x}{b}\right)-\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)+c (d) 1atan⁡−1(xa)−1btan⁡−1(xb)+c\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)-\frac{1}{b}\tan^{-1}\left(\frac{x}{b}\right)+c

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