Taking the wavelength of first Balmer line in hydrogen spectrum ( to ) as

CHEMISTRY · Single correct · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

Taking the wavelength of first Balmer line in hydrogen spectrum (

n = 3

n = 2

) as

660 \text{ nm}

, the wavelength of the 2^nd Balmer line (

n = 4

n = 2

) will be; (1)

889.2 \text{ nm}

(2)

488.9 \text{ nm}

(3)

642.7 \text{ nm}

(4)

388.9 \text{ nm}