Industrial wastewater contains 0.015 M Pb(NO ) and 0.015 M Cd(NO )

CHEMISTRY · Multi-part · CBSE · Chemistry · Equilibrium · Equilibrium

Problem

Industrial wastewater contains 0.015 M Pb(NO3_3)2_2 and 0.015 M Cd(NO3_3)2_2. To remove lead(II) ions selectively, engineers add aqueous Na2_2S, introducing sulfide ion into the solution. The solubility‐product constants at 25 °C are Ksp(PbS)=8.0×10−28K_{sp}(\text{PbS})=8.0\times10^{-28} and Ksp(CdS)=1.0×10−27K_{sp}(\text{CdS})=1.0\times10^{-27}. Assume the added volume of Na2_2S solution is negligible. (a) Derive an expression for the minimum sulfide ion concentration required to reduce the equilibrium concentration of Pb2+^{2+} to 1.0×10−61.0\times10^{-6} M. (b) Calculate this minimum [S2−^{2-}]. (c) Using the [S2−^{2-}] obtained in part (b), determine the ionic product QQ for CdS and predict whether CdS will precipitate under these conditions. Show your reasoning. (d) Discuss the effectiveness of sulfide addition as a selective precipitation method for separating Pb2+^{2+} from Cd2+^{2+} in this wastewater. Include the balanced net ionic equation for any precipitation that occurs.

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