The complete combustion of liquid ethanol at 298 K is represented by
C₂H₅OH(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(l)
with ΔH° = −1367 kJ for the reaction as written. Given ΔH_f° values (kJ mol⁻¹): CO₂(g) = −393.5; H₂O(l) = −285.8; O₂(g) = 0, determine the standard enthalpy of formation of C₂H₅OH(l).