In attempting to show that for all

MATHEMATICS · Single correct · CBSE · Mathematics · Binomial Theorem · Binomial Theorem

Problem

In attempting to show that (2nn)≤4 n\binom{2n}{n} \le 4^{\,n} for all n≥1n \ge 1, which of the following identities is required to relate (2n+2 n+1)\binom{2n+2}{\,n+1} to (2n n)\binom{2n}{\,n} in the inductive step? (a) (2n+2 n+1)=(2n+2)(n+1) (2n n)\displaystyle \binom{2n+2}{\,n+1} = \frac{(2n+2)}{(n+1)}\,\binom{2n}{\,n} (b) (2n+2 n+1)=(2n+2)(2n+1)(n+1)(n+1) (2n n)\displaystyle \binom{2n+2}{\,n+1} = \frac{(2n+2)(2n+1)}{(n+1)(n+1)}\,\binom{2n}{\,n} (c) (2n+2 n+1)=(2n+1)(n+1) (2n n)\displaystyle \binom{2n+2}{\,n+1} = \frac{(2n+1)}{(n+1)}\,\binom{2n}{\,n} (d) (2n+2 n+1)=(2n+2)(2n+1)(n+1) (2n n)\displaystyle \binom{2n+2}{\,n+1} = \frac{(2n+2)(2n+1)}{(n+1)}\,\binom{2n}{\,n}

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