A chemist plots mass versus amount for two pure diatomic gases under identical…

CHEMISTRY · Single correct · AP · Chemistry · Atomic Structure and Properties · Atomic Structure and Properties

Problem

A chemist plots mass versus amount for two pure diatomic gases under identical conditions and obtains two lines with slopes of 28 g mol−1^{-1} and 32 g mol−1^{-1}. The gases are N2\text{N}_2 and O2\text{O}_2. Which of the following correctly identifies the gas associated with each slope? (a) 28 g mol−1^{-1} → O2\text{O}_2; 32 g mol−1^{-1} → N2\text{N}_2 (b) Both slopes could correspond to either gas because the graph alone cannot identify molecular identity. (c) 28 g mol−1^{-1} → N2\text{N}_2; 32 g mol−1^{-1} → O2\text{O}_2 (d) Both slopes represent mixtures of N2\text{N}_2 and O2\text{O}_2 rather than pure gases.

Related theory

Browse the problem library