A simple pendulum of length on Earth has a time period

PHYSICS · Single correct · AP · Physics 1: Algebra-based · Oscillations · Oscillations

Problem

A simple pendulum of length 0.50 m0.50\,\text{m} on Earth has a time period TT. If its length is increased to 2.0 m2.0\,\text{m} and the pendulum is taken to a planet where the acceleration due to gravity is 4.9 m s−24.9\,\text{m\,s}^{-2}, what is the ratio T′/TT'/T of the new time period T′T' to the original time period TT? (Take gEarth=9.8 m s−2g_{\text{Earth}} = 9.8\,\text{m\,s}^{-2}.) (a) 1.41.4 (b) 0.710.71 (c) 2.82.8 (d) 2.02.0

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